Chemistry Study Guide: Moles, Mass, Formulas, and Composition

Chapter 1: Foundations — Units, Measurements, & Matter

  • Units and Conversions

    • Quantity, SI Unit, Symbol

      • Length: meter (m)

      • Mass: kilogram (kg)

      • Time: second (s)

      • Temperature: kelvin (K)

      • Amount of substance: mole (mol)

  • Scientific notation is used for very large/small numbers (e.g., Avogadro’s Number = 6.022 \times 10^{23}).

  • Density (d) = mass ÷ volume

    • Example: A 63.4 g piece of metal has a density of 12.86 g/cm³. Volume = 63.4 ÷ 12.86 = 4.93 cm^3

Chapter 2: Atoms, Molecules, and Ions

  • Atomic Theory

    • All matter is made of atoms (Dalton's Theory).

    • Subatomic particles:

      • Proton: +1 charge, ~1 u

      • Neutron: 0 charge, ~1 u

      • Electron: –1 charge, ~1/1800 u

  • Atomic and Mass Numbers

    • Atomic number (Z) = number of protons

    • Mass number (A) = protons + neutrons

  • Isotopes and Atomic Mass

    • Average atomic mass = weighted average of all isotopes

    • Average \space mass = \sum(fractional \space abundance \times isotopic \space mass)

    • Example: Carbon: 98.89% ¹²C and 1.11% ¹³C = (0.9889)(12.00) + (0.0111)(13.00) = 12.01 u

Chapter 3: Stoichiometry — Formulas, Moles, and Mass

  • Avogadro’s Number and the Mole

    • 1 mol = 6.022 × 10^{23} particles

    • Mass (in grams) of 1 mole of a substance = molar mass

      • Examples:

        • 1 mol H₂O = 2(1.008) + 16.00 = 18.02 g

        • 13.2 g Na → moles = 13.2 g ÷ 22.99 g/mol = 0.574 mol

  • Formula, Molecular, and Molar Mass

    • Formula Weight: Sum of atomic masses in ionic or covalent units. Example: NaCl = 22.99 + 35.45 = 58.44 u

    • Molecular Weight: Same as formula weight, but for molecules. Example: H₂SO₄ = 98.09 u

    • Molar Mass: Mass (g) of 1 mol of substance. Example: 1 mol H₂SO₄ = 98.09 g

  • Percent Composition

    • Percent \space by \space mass = \frac{n \times atomic \space mass}{molar \space mass} \times 100\%%

    • Example: Glucose, C₆H₁₂O₆

      • Total mass = 180.16 g/mol

      • %C = \frac{(6 × 12.01)}{180.16} × 100 = 40.00\%%

      • %H = \frac{(12 × 1.008)}{180.16} × 100 = 6.72\%%

      • %O = \frac{(6 × 16.00)}{180.16} × 100 = 53.28\%%

  • Empirical vs. Molecular Formulas

    • Empirical Formula

      1. Convert % to grams (assume 100 g).

      2. Convert grams to moles.

      3. Divide all by smallest mole value.

      4. Multiply to get integers if necessary.

        • Example: 40.92% C, 4.58% H, 54.50% O → Empirical formula = C₃H₄O₃

    • Molecular Formula

      1. Calculate molar mass of empirical formula.

      2. Divide molecular mass by empirical mass.

      3. Multiply empirical subscripts by that factor.

  • Limiting Reactants and Stoichiometry

    • Limiting reagent: Used up first in a reaction.

    • Use mole ratios from the balanced chemical equation.

      • Example: 5.52 g Na + 5.10 g Al₂O₃

        • Balanced: 6Na + Al₂O₃ → 2Al + 3Na₂O

        • Determine limiting reactant by comparing mol to mol ratio.

  • Percent Yield

    • Percent \space Yield = \frac{actual \space yield}{theoretical \space yield} × 100\%%

    • Example: Theoretical yield = 42.8 g; actual yield = 37.6 g → % yield = \frac{37.6}{42.8} × 100 = 87.9\%%

  • Memory Aids

    • Diatomic Elements: BrINClHOF — Br₂, I₂, N₂, Cl₂, H₂, O₂, F₂

    • Empirical Steps: % → g → mol → divide → multiply

    • Polyatomic Ions: Learn common ones (e.g., NO₃⁻ , SO₄²⁻)

Okay, I can explain each section:

Chapter 1: Foundations — Units, Measurements, & Matter

  • Units and Conversions: This section covers the basic units of measurement used in science, particularly the SI units. It's important to understand these units and how to convert between them to solve problems.

    • Quantity, SI Unit, Symbol: Lists the fundamental quantities (length, mass, time, etc.) along with their corresponding SI units and symbols.

    • Scientific notation: Explains how to express very large or very small numbers in a compact and convenient form. For instance, Avogadro’s Number is expressed as 6.022 × 10^{23}.

    • Density: Defines density as mass divided by volume and provides an example calculation.

Chapter 2: Atoms, Molecules, and Ions

  • Atomic Theory: Introduces Dalton's atomic theory, which states that all matter is made of atoms.

    • Subatomic particles: Lists the three main subatomic particles (protons, neutrons, and electrons) along with their charges and approximate masses.

    • Atomic and Mass Numbers: Defines atomic number as the number of protons in an atom and mass number as the sum of protons and neutrons.

    • Isotopes and Atomic Mass: Explains that isotopes are atoms of the same element with different numbers of neutrons. It also defines average atomic mass as the weighted average of all isotopes, with an example calculation for carbon.

Chapter 3: Stoichiometry — Formulas, Moles, and Mass

  • Avogadro’s Number and the Mole: Defines the mole as a unit of measurement for the amount of substance, with Avogadro’s number as the number of particles in one mole. It also explains how to calculate the mass of one mole of a substance (molar mass), with examples for water and sodium.

    • Formula, Molecular, and Molar Mass: Defines formula weight, molecular weight, and molar mass, with examples for NaCl and H₂SO₄.

    • Percent Composition: Explains how to calculate the percent by mass of each element in a compound, with an example for glucose.

    • Empirical vs. Molecular Formulas: Describes the difference between empirical and molecular formulas and outlines the steps to determine each, with an example.

      • Empirical Formula:
        Convert % to grams (assume 100 g).
        Convert grams to moles.
        Divide all by smallest mole value.
        Multiply to get integers if necessary.
        Example: 40.92% C, 4.58% H, 54.50% O → Empirical formula = C₃H₄O₃

      • Molecular Formula
        Calculate molar mass of empirical formula.
        Divide molecular mass by empirical mass.
        Multiply empirical subscripts by that factor.

    • Limiting Reactants and Stoichiometry: Defines the limiting reagent as the reactant that is used up first in a reaction. It also explains how to use mole ratios from the balanced chemical equation to determine the limiting reactant, with an example.

      • Use mole ratios from the balanced chemical equation.

      • Example: 5.52 g Na + 5.10 g Al₂O₃

      • Balanced: 6Na + Al₂O₃ → 2Al + 3Na₂O

      • Determine limiting reactant by comparing mol to mol ratio