Normal Approximation To Binomial
Normal Approximation to the Binomial
Overview
A Binomial random variable X counts the number of successes in n independent trials, each with success probability p.
Binomial probabilities can be calculated using exact formulas:
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
For cumulative probabilities, use: P(a ≤ X ≤ b) = Σ P(X = k) from a to b, often calculated using tables or statistical software.
When n is large and p is not near 0 or 1, binomial probabilities can be approximated using the normal distribution.
Normal Approximation Conditions
Works well when:
n is large
p is not too close to 0 or 1.
Visual Representation
The binomial distribution for large n will resemble a normal distribution.
Example: For Binomial(n = 100, p = 0.5), the distribution is bell-shaped like the normal curve.
Choosing the Correct Normal Distribution
Parameters of the Normal Distribution
A binomial random variable has parameters:
Mean (μ): μ = n * p
Variance (σ²): σ² = n * p * (1 - p)
Standard deviation (σ): σ = √(n * p * (1 - p)).
From Discrete to Continuous
Binomial random variables are discrete, with integer outcomes (e.g., P(X = 50)).
Normal distributions are continuous, making P(Y = 50) = 0.
To tackle this, we approximate using intervals (like 49.5 ≤ X ≤ 50.5) to define continuous probabilities.
Effectiveness of the Approximation
Example:
For Binomial(n=100, p=0.5): P(X = 50) is approximately 0.0796.
For Normal(μ = 50, σ = 5): P(49.5 ≤ Y ≤ 50.5) ≈ 0.0797.
Key Rules for Using the Approximation
Continuity Correction:
Include the entire rectangle for values of x in the interval of interest.
Standardization:
If using a table, standardize the values of X: Z = (X - μ) / σ.
Conditions on np and n(1 - p):
Ensure both np and n(1 - p) > 5 for accurate approximations.
Importance of the Last Rule
Example of poor approximation:
For n = 50 and p = 0.05, the binomial distribution looks skewed.
A normal approximation yields P(X ≤ 1) which differs significantly from actual value, leading to inaccuracies.
Examples
Example 1:
X is a binomial random variable with n = 30 and p = 0.4.
Use normal approximation for P(X ≤ 10).
Calculate: np = 12, n(1 - p) = 18.
Approximation is satisfactory.
Example 2: Production Line of Batteries
95% reliability rate, n = 200.
Find P(X ≥ 195):
Success (working battery) = 195.
np = 190, n(1 - p) = 10.
Normalize: P(X ≥ 195) ≈ P(Z ≥ (194.5 - 190) / √[200(0.95)(0.05)]).
Result: P(Z ≥ 1.46) = 1 - 0.9278 = 0.0722.