Algebra 2 Semester 2 Final Review: Sequences, Probability, and Statistics Notes and Stats

Arithmetic and Geometric Sequences

Sequence Problem 1

  • Sequence Table:
    • n=0n=0, f(n)=4.2f(n)=4.2
    • n=1n=1, f(n)=6.3f(n)=6.3
    • n=2n=2, f(n)=9.45f(n)=9.45
    • n=3n=3, f(n)=14.175f(n)=14.175
  • Type of Sequence: Geometric
  • Ratio Calculation: 6.3÷4.2=1.56.3 \div 4.2 = 1.5
  • Initial Term (a1a_1 as per transcript): a1=4.2a_1 = 4.2
  • Common Difference/Ratio: 1.51.5
  • Explicit Rule: an=4.2(1.5)n1a_n = 4.2(1.5)^{n-1}
  • Recursive Rule: a1=4.2a_1 = 4.2, an=an1×1.5a_n = a_{n-1} \times 1.5

Sequence Problem 2

  • Sequence Table:
    • n=0n=0, f(n)=17.3f(n)=17.3
    • n=1n=1, f(n)=13.5f(n)=13.5
    • n=2n=2, f(n)=9.7f(n)=9.7
    • n=3n=3, f(n)=5.9f(n)=5.9
  • Difference Calculation: 13.517.3=3.813.5 - 17.3 = -3.8
  • Type of Sequence: Arithmetic
  • Initial Term: 17.317.3
  • Common Difference/Ratio: 3.8-3.8
  • Explicit Rule: an=17.33.8na_n = 17.3 - 3.8n
  • Recursive Rule: a1=17.3a_1 = 17.3, an=an13.8a_n = a_{n-1} - 3.8

Sequence Problem 3

  • Sequence Table:
    • n=0n=0, f(n)=12f(n)=\frac{1}{2}
    • n=1n=1, f(n)=2f(n)=2
    • n=2n=2, f(n)=8f(n)=8
    • n=3n=3, f(n)=32f(n)=32
  • Type of Sequence: Geometric
  • Initial Term: a0=12a_0 = \frac{1}{2}
  • Common Difference/Ratio: ×4\times 4
  • Explicit Rule: an=12(4)na_n = \frac{1}{2}(4)^n
  • Recursive Rule: a1=12a_1 = \frac{1}{2}, an=an1×4a_n = a_{n-1} \times 4

Sequence Problem 4

  • Sequence Table:
    • n=1n=1, f(n)=24f(n)=-24
    • n=2n=2, f(n)=12f(n)=12
    • n=3n=3, f(n)=6f(n)=-6
    • n=4n=4, f(n)=3f(n)=3
    • n=5n=5, f(n)=1.5f(n)=-1.5
  • Type of Sequence: Geometric
  • Initial Term: a1=24a_1 = -24
  • Common Difference/Ratio: ×0.5\times -0.5
  • Explicit Rule: an=24(0.5)n1a_n = -24(-0.5)^{n-1}
  • Recursive Rule: a1=24a_1 = -24, an=an1×0.5a_n = a_{n-1} \times -0.5

Arithmetic Sequence Reconstruction (Problem 5)

  • Given: a5=14a_5 = 14 and a9=54a_9 = 54. Initial term index is 00.
  • Difference Calculation: 541495=404=10\frac{54-14}{9-5} = \frac{40}{4} = 10. Common Difference (dd) is 1010.
  • Initial Term (a0a_0) Calculation:
    • a5=14a_5 = 14
    • a4=4a_4 = 4
    • a3=6a_3 = -6
    • a2=16a_2 = -16
    • a1=26a_1 = -26
    • a0=36a_0 = -36
  • Recursive Rule: a0=36a_0 = -36, an=an1+10a_n = a_{n-1} + 10
  • Explicit Rule: an=36+10na_n = -36 + 10n

Geometric Sequence Reconstruction (Problem 6)

  • Given: a2=36a_2 = 36 and a5=324a_5 = 324. Initial term index is 00.
  • Ratio Calculation:
    • 36×r3=32436 \times r^3 = 324
    • r3=32436=9r^3 = \frac{324}{36} = 9 (Note: Transcript calculation steps show r33=93\sqrt[3]{r^3} = \sqrt[3]{9} leading to r=3r=3; note 33=273^3 = 27, however calculation written is r3=9r=3r^3=9 \rightarrow r=3 as interpreted in solving 9=3\sqrt{9}=3).
  • Initial Term (a0a_0) Calculation:
    • a2=36a_2 = 36
    • a1=12a_1 = 12
    • a0=4a_0 = 4
  • Explicit Rule: an=4(3)na_n = 4(3)^n
  • Recursive Rule: a0=4a_0 = 4, an=an1×3a_n = a_{n-1} \times 3

Probability of Compound Events

Dice Experiments

  1. Rolling two fair dice and adding the dots (Sum is 7 or 11):

    • Sum 7 possibilities: 636\frac{6}{36}
    • Sum 11 possibilities: 236\frac{2}{36}
    • Total probability: 836=290.22\frac{8}{36} = \frac{2}{9} \approx 0.22 (22%22\%
  2. Rolling two fair dice and adding the dots (Sum is even or a perfect square):

    • Total probability: 19360.53\frac{19}{36} \approx 0.53 (53%53\%

Standard Deck of Cards

  1. Drawing a card (Red or an Ace):

    • P(Red)=2652P(\text{Red}) = \frac{26}{52}
    • P(Ace)=452P(\text{Ace}) = \frac{4}{52}
    • P(Red and Ace)=252P(\text{Red and Ace}) = \frac{2}{52}
    • Calculation: 2652+452252=2852=7130.54\frac{26}{52} + \frac{4}{52} - \frac{2}{52} = \frac{28}{52} = \frac{7}{13} \approx 0.54 (54%54\%
  2. Drawing a card (Black or Even):

    • P(Black)=2652P(\text{Black}) = \frac{26}{52}
    • Calculation recorded: 2652+30521052=4652=23260.88\frac{26}{52} + \frac{30}{52} - \frac{10}{52} = \frac{46}{52} = \frac{23}{26} \approx 0.88 (88%88\%
  3. Drawing 2 cards without replacement (Face card then a 10):

    • Calculation: 1252×451=482652=42210.018\frac{12}{52} \times \frac{4}{51} = \frac{48}{2652} = \frac{4}{221} \approx 0.018 (1.8%1.8\%
  4. Drawing 2 cards without replacement (Queen then another Queen):

    • Calculation: 452×351=122652=12210.0045\frac{4}{52} \times \frac{3}{51} = \frac{12}{2652} = \frac{1}{221} \approx 0.0045 (0.45%0.45\%

Selection from a Box (With Replacement)

  1. Box with 6 red, 7 blue, and 2 green pens (Blue then Green):

    • Total pens = 1515
    • Calculation: 715×215=142250.062\frac{7}{15} \times \frac{2}{15} = \frac{14}{225} \approx 0.062 (6.2%6.2\%
  2. Box with 6 red, 4 blue, and 4 green pens (Red or Blue then Green):

    • Total pens = 1414
    • Calculation: 1014×414=57×27=10490.20\frac{10}{14} \times \frac{4}{14} = \frac{5}{7} \times \frac{2}{7} = \frac{10}{49} \approx 0.20 (20%20\%

Two-Way Tables and Marginal Frequencies

Exercise 3: Test Preparation and Outcomes

GradeStudiedDid Not StudyTotal
Pass3434664040
Fail44661010
Total383812125050
  • a. Probability that a person studied, failed the test: 4380.105\frac{4}{38} \approx 0.105 (10.5%10.5\%
  • b. Probability that a person passed the test: 4050=45=0.8\frac{40}{50} = \frac{4}{5} = 0.8 (80%80\%

Exercise 4: Survey Responses by Role

RoleYesNoTotal
Student565642429898
Teacher33771010
Total59594949108108
  • a. Probability that a teacher responded yes: 310=0.30\frac{3}{10} = 0.30 (30%30\%
  • b. Probability that a person surveyed is a student: 98108=49540.91\frac{98}{108} = \frac{49}{54} \approx 0.91 (91%91\%

Exercise 5: Hand Washing Survey Results

MaleFemaleTotal
Wash132132151151283283
No Wash393929296868
Total171171180180351351
  • Marginal Frequencies Interpretation: Total males = 171171, Total females = 180180, Total surveyed = 351351. Total wash = 283283, Total no wash = 6868.
  • a. Probability person does not wash hands: 683510.19\frac{68}{351} \approx 0.19 (19%19\%
  • b. Probability that a female washes her hands: 1511800.84\frac{151}{180} \approx 0.84 (84%84\%

Unit Circle, Radians, and Trig Identities

Unit Circle Coordinates

  • Angle 150150^\circ: (32,12)(-\frac{\sqrt{3}}{2}, \frac{1}{2}) (Quadrant II).
  • Angle 315315^\circ: (22,22)(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}) (Quadrant IV).

Unit Conversions

  • Convert 4545^\circ to radians: 45×π180=π445 \times \frac{\pi}{180} = \frac{\pi}{4}.
  • Convert 225225^\circ to radians: 225×π180=5π4225 \times \frac{\pi}{180} = \frac{5\pi}{4}.
  • Convert 3π4\frac{3\pi}{4} to degrees: 3×1804=135\frac{3 \times 180}{4} = 135^\circ.
  • Convert 2π3\frac{2\pi}{3} to degrees: 2×1803=120\frac{2 \times 180}{3} = 120^\circ.

Trig Identities

  • cos2(θ)+sin2(θ)=1\cos^2(\theta) + \sin^2(\theta) = 1
  • tan(θ)=sin(θ)cos(θ)\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}
  • cos2(θ)=1sin2(θ)\cos^2(\theta) = 1 - \sin^2(\theta)
  • sin2(θ)=1cos2(θ)\sin^2(\theta) = 1 - \cos^2(\theta)

Data Collection and Standard Deviation

Data Collection Terms

  • Population: The entire group being studied (e.g., 250250 computers, 100100 movie viewers).
  • Sample: The subset of the population actually tested/surveyed (e.g., 25 randomly chosen computers, every 30th person).\n* **Sampling Method:**\n * **Simple Random:** Testing randomly chosen items.\n * **Systematic:** Surveying every nthperson(e.g.,every-th person (e.g., every30-th exiting viewer).\n\n## Standard Deviation Definition\n* The standard deviation is the average distance from the **mean**.\n* The standard deviation is the **square root** of the variance.\n\n## Dataset Analysis\n\n### Dataset 1: 4, 5, 8, 1, 2, 3, 9, 8, 7, 6, 2\n* **Mean:** 5\n* **Median:** 5\n* **Standard Deviation:** 2.66\n* **Range:** 8\n* **Interpretation:** The numbers in the list are an average of 2.66 units away from the mean.\n\n### Dataset 2: 23, 10, 11, 24, 32, 15, 13, 16\n* **Mean:** 18\n* **Median:** 15.5\n* **Standard Deviation:** 7.14\n* **Range:** 22\n* **Interpretation:** The average distance from the mean is 7.14.\n\n# Box-and-Whisker Plots\n\n## Plot Reading: Number of Minutes to Read a Chapter\n* **Data points:** 10, 22, 25, 35, 45\n* **Lower Extreme (Min):** 10\n* **Upper Extreme (Max):** 45\n* **Median (Q_2):):**25\n* **Lower Quartile (Q_1):):**22\n* **Upper Quartile (Q_3):):**35\n* **Range between Lower and Upper Quartile:** Q_3 - Q_1 = 35 - 22 = 13\n* **Range where data is most clustered:** Between Q_1andandQ_2(Width=(Width =3)\n* **Range where data is most spread out:** Between Q_1andandQ_3(Width=(Width =13)\n* **Interquartile Range (IQR):** 35 - 22 = 13$$
  • Distribution Type: Skewed Right