Equations, Formulas, and Equivalence Transformations

Fundamentals of Equations and Formulas

  • Equation (Gleichung): An equation consists of two algebraic terms joined by an equality sign (==).
  • Formula (Formel): A formula is an equation containing multiple variables. It describes how variables, physical or mathematical quantities (Gro¨ßen\text{Größen}), and numbers relate to one another.

Setting up Equations and Formulas

  • Formulating Algebraic Equations (Problem 556):

    • Variable definitions:
      • mm: Number of girls (Anzahl der Ma¨dchen\text{Anzahl der Mädchen})
      • bb: Number of boys (Anzahl der Buben\text{Anzahl der Buben})
    • Relational equations:
      • Part a: m+2=bm + 2 = b
      • Part b: 2⋅(m−1)=b2 \cdot (m - 1) = b
  • Travel Bus Pricing Formula (Problem 559):

    • Variable definitions:
      • bb: Base price for the charter bus (Preis fu¨r Reisebus\text{Preis für Reisebus})
      • ff: Ticket price for each individual passenger (Preis fu¨r jeden Fahrgast\text{Preis für jeden Fahrgast})
      • nn: Total number of passengers (Anzahl der Fahrga¨ste\text{Anzahl der Fahrgäste})
      • PP: Total price
    • 1) General formula for total price PP:
      • P=b+n⋅fP = b + n \cdot f
    • 2) Evaluation given specific parameter values (b=50 €b = 50\,\text{€}, f=7 €f = 7\,\text{€}, n=12n = 12):
      • P=50+12⋅7P = 50 + 12 \cdot 7
      • P=50+84P = 50 + 84
      • P=134 €P = 134\,\text{€}

Geometric Formulas for Perimeter and Area

  • Perimeter and Area Expressions (Problem 564):

    • Part a:
      • 1) Perimeter (UU): U=2⋅4u+2⋅4v+2⋅3v=8u+8v+6v=8u+14vU = 2 \cdot 4u + 2 \cdot 4v + 2 \cdot 3v = 8u + 8v + 6v = 8u + 14v
      • 2) Area (AA): A=10uvA = 10uv
    • Part b:
      • 1) Perimeter (UU): U=20xU = 20x
      • 2) Area (AA): A=9x2A = 9x^2
  • Perimeter and Area Expressions (Problem 565):

    • Part a:
      • 1) Perimeter (UU): U=8aU = 8a
      • 2) Area (AA): A=3a2A = 3a^2
    • Part b:
      • 1) Perimeter (UU): U=8x+2yU = 8x + 2y
      • 2) Area (AA): A=3x⋅y−x2A = 3x \cdot y - x^2
    • Part c:
      • 1) Perimeter (UU): U=4u+4vU = 4u + 4v
      • 2) Area (AA): A=u2−v2A = u^2 - v^2

Equivalent Equations (Äquivalente Gleichungen)

  • Definition: Equivalent equations (A¨quivalente Gleichungen\text{Äquivalente Gleichungen}) are equations that possess the exact same solution set (mit der gleichen Lo¨sung\text{mit der gleichen Lösung}).
  • Examples of Equivalent Sets (Problem 568):
    • Part a:
      • Base equation: 5x=105x = 10
      • Solution: x=2x = 2
      • Equivalent equations sharing the solution x=2x = 2:
        • 15x=3015x = 30
        • 5x+3=135x + 3 = 13
    • Part c:
      • Base equation: 3−2x=13 - 2x = 1
      • Solution: x=1x = 1
      • Equivalent equations sharing the solution x=1x = 1:
        • −2x=−2-2x = -2
        • 2x=22x = 2

Equivalence Transformations (Äquivalenzumformungen)

  • Core Principle: Equivalence transformations (A¨quivalenzumformungen\text{Äquivalenzumformungen}) convert equations into equivalent equations. The solution of an equation remains unchanged when performing valid algebraic operations on both sides of the equality sign.

  • Valid Operations: An equation's solution set does not change if on both sides:

    • The same number is added (dieselbe Zahl addiert\text{dieselbe Zahl addiert}).
    • The same number is subtracted (dieselbe Zahl subtrahiert\text{dieselbe Zahl subtrahiert}).
    • Multiplied by the same non-zero number (mit derselben Zahl ≠0 multipliziert\text{mit derselben Zahl } \neq 0 \text{ multipliziert}).
    • Divided by the same non-zero number (durch dieselbe Zahl ≠0 dividiert\text{durch dieselbe Zahl } \neq 0 \text{ dividiert}).
    • The same multiple of the unknown variable is added or subtracted (dasselbe Vielfache der Unbekannten addiert bzw. subtrahiert\text{dasselbe Vielfache der Unbekannten addiert bzw. subtrahiert}).
  • Step-by-Step Transformation Examples (Problem 572):

    • Part a:
      • Given equation: x+6=1x + 6 = 1
      • Transformation: Subtract 66 from both sides (∣−6\mid -6)
      • Resulting solution: x=−5x = -5
    • Part b:
      • Given equation: 7x=217x = 21
      • Transformation: Divide both sides by 77 (∣:7\mid :7)
      • Resulting solution: x=3x = 3
    • Part c:
      • Given equation: 3t=3t3t = 3t
      • Transformation: Divide both sides by 33 (∣:3\mid :3)
      • Resulting equation: t=tt = t
    • Part d:
      • Given equation: 3x−7=2x+13x - 7 = 2x + 1
      • Transformation step: Subtract 2x2x from both sides (∣−2x\mid -2x)
      • Resulting step: x−7=1x - 7 = 1
    • Part e:
      • Given equation: 5z+8=1−2z5z + 8 = 1 - 2z
      • Transformation step: Subtract 11 from both sides (∣−1\mid -1)
      • Resulting step: 5z+7=−2z5z + 7 = -2z