Mechanical Properties of Metals & Alloys – Part 1

Learning Outcomes

  • By the end of the chapter a student should be able to:
    • Define engineering stress and engineering strain.
    • Given an engineering stress–strain diagram, determine:
    • Modulus of elasticity EE (Young’s modulus).
    • Tensile (ultimate) strength σUTS\sigma_\text{UTS}.
    • Estimate percent elongation %EL\%EL at fracture.
    • Compute ductility in terms of:
    • Percent elongation %EL\%EL.
    • Percent reduction of area %RA\%RA.

Why Study Mechanical Properties?

  • Mechanical engineers
    • Design machines/structures that experience forces & deformations.
    • Must choose materials so that unacceptable deformation or failure does not occur.
  • Structural engineers
    • Determine & predict stress distributions in loaded members (experimentally or analytically).
  • Materials & metallurgical engineers
    • Produce / fabricate materials to meet the above service requirements.
    • Study relationships between micro-structure and mechanical properties.

Definition of Mechanical Properties

  • Describe a material’s response/deformation under applied load.
  • Behaviour shows both elastic (recoverable) and plastic (permanent) deformation before failure.
  • Measured by mechanical tests; response depends on bonding & atomic arrangement.
  • Two basic deformation types for load-carrying materials:
    • Elastic deformation – instantaneous, fully recoverable.
    • Plastic deformation – non-recoverable; permanent shape change.

Common Mechanical Properties & Associated Tests

  • Properties: hardness, ductility, yield strength, toughness, brittleness, tensile/ultimate strength, modulus of elasticity, malleability, fracture strength, stiffness, flexural strength.
  • Tests: tension, compression, hardness (micro/macro), impact, flexural/bending, torsion/shear, fatigue (S–N, fatigue crack growth), creep (elevated-temperature), fracture toughness.

Material Property Assessment Summary

  • Hardness → Micro/Macro hardness tests.
  • Strength/yield/ultimate → Tension tests, torsion tests.
  • Ductility (elongation, area reduction) → Tension tests.
  • Creep (high-T strength) → Creep tests.
  • Toughness (resistance to failure) → Impact tests, fracture toughness tests.
  • Fatigue strength → S–N tests, fatigue crack growth tests.
  • Modulus of elasticity/stiffness/flexural strength → Tension, flexural tests.

Elastic Deformation ("Elastic means reversible")

  • Sequence for small load FF on bonds:
    1. Initial, undeformed.
    2. Bonds stretch by distance dd.
    3. Upon unloading, material returns to original shape.
  • Two elastic categories on stress–strain curve:
    • Linear-elastic (Hookean).
    • Non-linear elastic.

Plastic Deformation ("Plastic means permanent")

  • After yield, atoms/glide planes shear; even after unloading only elastic part recovers, plastic offset remains dplasticd_{plastic}.
  • For metals, plasticity is accommodated by slip of planes & dislocation motion.

Modes of Loading / Types of Stress

  • Tension, compression, shear, torsion, bending, buckling.
  • Visualised deformations:
    • (a) Tension → elongation (+ve strain).
    • (b) Compression → contraction (−ve strain).
    • (c) Shear → γ=tanθ\gamma = \tan\theta.
    • (d) Torsion → angle of twist ϕ\phi under torque TT.

Concept of Stress & Strain – General States

  • Tensile stress: σ=FA0\sigma = \dfrac{F}{A_0}.
  • Shear stress (torsion): τ=F<em>sA</em>0\tau = \dfrac{F<em>s}{A</em>0} or for a circular shaft τ=MAcR\tau = \dfrac{M}{A_c R}.
  • Compression identical formula with \sigma<0.
  • Engineering strains (dimensionless):
    • Axial tensile/compressive: ε=ΔLL0\varepsilon = \dfrac{\Delta L}{L_0}.
    • Lateral: ε<em>L=Δww</em>0\varepsilon<em>L = \dfrac{\Delta w}{w</em>0}.
    • Shear: γ=tanθ=Δxy\gamma = \tan\theta = \dfrac{\Delta x}{y}.

Poisson’s Ratio ν\nu

  • ν=εLε\nu = -\dfrac{\varepsilon_L}{\varepsilon} (negative sign gives positive ν\nu because lateral strain is opposite sign to axial strain).
  • Typical values: metals ≈ 0.33; ceramics ≈ 0.25; polymers ≈ 0.40.
  • Theoretical isotropic: 0.250.25; maximum 0.500.50 (incompressible). \nu>0.50 → density increases; \nu<0.50 → density decreases (voids form).

Tensile Test: Equipment & Procedure

  • Universal test machine with hydraulic actuator.
  • Specimen clamped, elongated at constant rate.
  • Load cell measures instantaneous force FF, extensometer/gauge marks measure elongation ΔL\Delta L.
  • Results converted to engineering stress σ=F/A<em>0\sigma=F/A<em>0 and engineering strain ε=ΔL/L</em>0\varepsilon=\Delta L/L</em>0 to compare specimens of differing size.

Engineering Stress–Strain Curve (Typical)

  • Regions:
    • Elastic (linear) with slope EE.
    • Yield point / proportional limit PP.
    • Strain-hardening (uniform plastic deformation).
    • Ultimate tensile strength (maximum σUTS\sigma_{UTS}).
    • Necking (non-uniform plastic deformation).
    • Fracture (stress at break σf\sigma_f).
  • Key ordinates:
    • EE: modulus of elasticity E=ΔσΔεE = \dfrac{\Delta\sigma}{\Delta\varepsilon} within linear segment.
    • Yield strength σy\sigma_y defined by 0.2%0.2\% offset ( ε=0.002\varepsilon=0.002 ).
    • Ultimate strength σUTS\sigma_{UTS} – peak engineering stress.
    • Fracture strength σf\sigma_f – stress at specimen failure.

Mechanical Properties Obtained from Tensile Test

  1. Modulus of elasticity EE (GPa).
  2. Proportional limit & 0.2%0.2\% offset yield strength σy\sigma_y.
  3. Ultimate tensile strength σUTS\sigma_{UTS}.
  4. Fracture strength σf\sigma_f.
  5. Ductility metrics: %EL\%EL, %RA\%RA.
  • Example property table (room-temperature, typical):
    • Aluminium: σ<em>y35MPa,  σ</em>UTS90MPa,  %EL40\sigma<em>y≈35\,\text{MPa},\;\sigma</em>{UTS}≈90\,\text{MPa},\;\%EL≈40.
    • Steel 1020: σ<em>y180MPa,  σ</em>UTS380MPa,  %EL25\sigma<em>y≈180\,\text{MPa},\;\sigma</em>{UTS}≈380\,\text{MPa},\;\%EL≈25.
      (Full table provided in transcript.)

Calculating Ductility

  • Percent elongation:
    • %EL=L<em>fL</em>0L0×100\%EL = \dfrac{L<em>f - L</em>0}{L_0}\times 100.
  • Percent reduction in area:
    • %RA=A<em>0A</em>fA0×100\%RA = \dfrac{A<em>0 - A</em>f}{A_0}\times 100.
  • Requires measurements after fracture (final gauge length & necked diameter).

Linear Elasticity & Hooke’s Law

  • For tension/compression: σ=Eε\sigma = E\varepsilon.
  • Rearrangements:
    • E=σεE = \dfrac{\sigma}{\varepsilon}.
    • ε=σE\varepsilon = \dfrac{\sigma}{E}.
  • Elastic elongation of prismatic bar:
    • ΔL=FL<em>0A</em>0E\Delta L = \dfrac{F L<em>0}{A</em>0 E}.

Example Problems (Highlights)

Example 1: Elastic Elongation of Copper Bar
  • Given: L<em>0=305mmL<em>0=305\,\text{mm}, σ=276MPa\sigma=276\,\text{MPa}, E</em>Cu=110GPaE</em>{Cu}=110\,\text{GPa}.
  • ΔL=σL0E=(276)(305)110×103=0.77mm\Delta L = \dfrac{\sigma L_0}{E} = \dfrac{(276)(305)}{110\times10^3}=0.77\,\text{mm}.
Example 2: Load Causing Specified Diameter Change in Brass Rod
  • Diameter d0=10mmd_0=10\,\text{mm}, desired Δd=2.5×103mm\Delta d = -2.5\times10^{-3}\,\text{mm} (negative = shrink).
  • Lateral strain ε<em>x=Δdd</em>0=2.5×104\varepsilon<em>x = \dfrac{\Delta d}{d</em>0} = -2.5\times10^{-4}.
  • Axial strain ε<em>z=ε</em>xν=7.35×104\varepsilon<em>z = -\dfrac{\varepsilon</em>x}{\nu} = 7.35\times10^{-4} with ν=0.34\nu=0.34.
  • Axial stress σ=Eε<em>z=71.3MPa\sigma = E\varepsilon<em>z = 71.3\,\text{MPa} (E</em>Brass=97GPa)\big(E</em>{Brass}=97\,\text{GPa}\big).
  • Load: F=σA0=(71.3×106)π(10×103)24=5.6kNF = \sigma A_0 = (71.3\times10^6)\dfrac{\pi (10\times10^{-3})^2}{4}=5.6\,\text{kN}.
Example 3: Brass Specimen – Properties from Stress–Strain Curve
  • (a) E94GPaE \approx 94\,\text{GPa} (from linear slope).
  • (b) σy250MPa\sigma_y \approx 250\,\text{MPa} at 0.2%0.2\% offset.
  • (c) Max load for d<em>0=12.8mmd<em>0=12.8\,\text{mm}: F</em>max=57.9kNF</em>{max}=57.9\,\text{kN} using σUTS=450MPa\sigma_{UTS}=450\,\text{MPa}.
  • (d) For σ=345MPa\sigma=345\,\text{MPa}, read ε0.06\varepsilon≈0.06ΔL=(0.06)(250)=15mm\Delta L=(0.06)(250)=15\,\text{mm}.
Example 4: Steel Specimen Ductility & True Stress at Fracture
  • d<em>0=12.8mm,  d</em>f=10.7mm,  σf=460MPad<em>0=12.8\,\text{mm},\;d</em>f=10.7\,\text{mm},\;\sigma_f=460\,\text{MPa}.
  • A<em>0=128.7mm2,  A</em>f=89.9mm2A<em>0=128.7\,\text{mm}^2,\;A</em>f=89.9\,\text{mm}^2.
  • %RA=128.789.9128.7×100=30%\%RA = \dfrac{128.7-89.9}{128.7}\times100=30\%.
  • Load at fracture: F=σ<em>fA</em>0=59.2kNF=\sigma<em>f A</em>0 = 59.2\,\text{kN}.
  • True stress at fracture: σ<em>T=FA</em>f=660MPa\sigma<em>T = \dfrac{F}{A</em>f}=660\,\text{MPa}.

Key Equations (Summary)

  • Engineering stress: σ=FA0\sigma = \dfrac{F}{A_0}.
  • Engineering strain: ε=ΔLL0\varepsilon = \dfrac{\Delta L}{L_0}.
  • Hooke’s law (linear elastic): σ=Eε\sigma = E \varepsilon.
  • Poisson’s ratio: ν=εLε\nu = -\dfrac{\varepsilon_L}{\varepsilon}.
  • Percent elongation: %EL=L<em>fL</em>0L0×100\%EL = \dfrac{L<em>f-L</em>0}{L_0}\times100.
  • Percent reduction in area: %RA=A<em>0A</em>fA0×100\%RA = \dfrac{A<em>0-A</em>f}{A_0}\times100.
  • True stress (at any instant): σ<em>T=FA</em>inst\sigma<em>T = \dfrac{F}{A</em>{inst}}; at fracture use AfA_f.

Practical / Philosophical Implications

  • Choice of material & cross-section is guided by property limits such as σ<em>y\sigma<em>y, σ</em>UTS\sigma</em>{UTS}, EE, %EL\%EL ensuring safety factors.
  • Ethical responsibility for engineers to avoid catastrophic failure through accurate testing & interpretation of mechanical properties.
  • Awareness of test limitations (destructive, room-temperature, static) is crucial; actual service may involve high T, cyclic or impact loads → additional tests (creep, fatigue, impact) required.

Connections & Real-World Relevance

  • Design codes (ASME, AISC, ISO) embed yield & tensile requirements; test data feed into Finite-Element stress analyses.
  • Ductility metrics inform forming processes (rolling, drawing) and failure modes (ductile vs brittle fracture).
  • Poisson’s ratio enters vibration, stability and multi-axial stress calculations (e.g., pressure vessels, biomechanics).

Reference Values (Room-Temperature)

  • E<em>Steel207GPaE<em>{Steel}\approx207\,\text{GPa}; E</em>Al69GPaE</em>{Al}\approx69\,\text{GPa}; E<em>Brass97GPaE<em>{Brass}\approx97\,\text{GPa}; E</em>Cu110GPaE</em>{Cu}\approx110\,\text{GPa}.
  • Shear modulus GG linked: G=E2(1+ν)G = \dfrac{E}{2(1+\nu)} for isotropic materials.

Testing Ethics & Disclaimer

  • Tests are destructive; specimens permanently deformed/fractured.
  • Data compiled for educational, non-commercial purposes; reliability depends on cited sources (Callister, Smith & Hashemi, etc.).