Mechanical Properties of Metals & Alloys – Part 1
Learning Outcomes
- By the end of the chapter a student should be able to:
- Define engineering stress and engineering strain.
- Given an engineering stress–strain diagram, determine:
- Modulus of elasticity E (Young’s modulus).
- Tensile (ultimate) strength σUTS.
- Estimate percent elongation %EL at fracture.
- Compute ductility in terms of:
- Percent elongation %EL.
- Percent reduction of area %RA.
Why Study Mechanical Properties?
- Mechanical engineers
- Design machines/structures that experience forces & deformations.
- Must choose materials so that unacceptable deformation or failure does not occur.
- Structural engineers
- Determine & predict stress distributions in loaded members (experimentally or analytically).
- Materials & metallurgical engineers
- Produce / fabricate materials to meet the above service requirements.
- Study relationships between micro-structure and mechanical properties.
Definition of Mechanical Properties
- Describe a material’s response/deformation under applied load.
- Behaviour shows both elastic (recoverable) and plastic (permanent) deformation before failure.
- Measured by mechanical tests; response depends on bonding & atomic arrangement.
- Two basic deformation types for load-carrying materials:
- Elastic deformation – instantaneous, fully recoverable.
- Plastic deformation – non-recoverable; permanent shape change.
Common Mechanical Properties & Associated Tests
- Properties: hardness, ductility, yield strength, toughness, brittleness, tensile/ultimate strength, modulus of elasticity, malleability, fracture strength, stiffness, flexural strength.
- Tests: tension, compression, hardness (micro/macro), impact, flexural/bending, torsion/shear, fatigue (S–N, fatigue crack growth), creep (elevated-temperature), fracture toughness.
Material Property Assessment Summary
- Hardness → Micro/Macro hardness tests.
- Strength/yield/ultimate → Tension tests, torsion tests.
- Ductility (elongation, area reduction) → Tension tests.
- Creep (high-T strength) → Creep tests.
- Toughness (resistance to failure) → Impact tests, fracture toughness tests.
- Fatigue strength → S–N tests, fatigue crack growth tests.
- Modulus of elasticity/stiffness/flexural strength → Tension, flexural tests.
- Sequence for small load F on bonds:
- Initial, undeformed.
- Bonds stretch by distance d.
- Upon unloading, material returns to original shape.
- Two elastic categories on stress–strain curve:
- Linear-elastic (Hookean).
- Non-linear elastic.
- After yield, atoms/glide planes shear; even after unloading only elastic part recovers, plastic offset remains dplastic.
- For metals, plasticity is accommodated by slip of planes & dislocation motion.
Modes of Loading / Types of Stress
- Tension, compression, shear, torsion, bending, buckling.
- Visualised deformations:
- (a) Tension → elongation (+ve strain).
- (b) Compression → contraction (−ve strain).
- (c) Shear → γ=tanθ.
- (d) Torsion → angle of twist ϕ under torque T.
Concept of Stress & Strain – General States
- Tensile stress: σ=A0F.
- Shear stress (torsion): τ=A</em>0F<em>s or for a circular shaft τ=AcRM.
- Compression identical formula with \sigma<0.
- Engineering strains (dimensionless):
- Axial tensile/compressive: ε=L0ΔL.
- Lateral: ε<em>L=w</em>0Δw.
- Shear: γ=tanθ=yΔx.
Poisson’s Ratio ν
- ν=−εεL (negative sign gives positive ν because lateral strain is opposite sign to axial strain).
- Typical values: metals ≈ 0.33; ceramics ≈ 0.25; polymers ≈ 0.40.
- Theoretical isotropic: 0.25; maximum 0.50 (incompressible). \nu>0.50 → density increases; \nu<0.50 → density decreases (voids form).
Tensile Test: Equipment & Procedure
- Universal test machine with hydraulic actuator.
- Specimen clamped, elongated at constant rate.
- Load cell measures instantaneous force F, extensometer/gauge marks measure elongation ΔL.
- Results converted to engineering stress σ=F/A<em>0 and engineering strain ε=ΔL/L</em>0 to compare specimens of differing size.
Engineering Stress–Strain Curve (Typical)
- Regions:
- Elastic (linear) with slope E.
- Yield point / proportional limit P.
- Strain-hardening (uniform plastic deformation).
- Ultimate tensile strength (maximum σUTS).
- Necking (non-uniform plastic deformation).
- Fracture (stress at break σf).
- Key ordinates:
- E: modulus of elasticity E=ΔεΔσ within linear segment.
- Yield strength σy defined by 0.2% offset ( ε=0.002 ).
- Ultimate strength σUTS – peak engineering stress.
- Fracture strength σf – stress at specimen failure.
Mechanical Properties Obtained from Tensile Test
- Modulus of elasticity E (GPa).
- Proportional limit & 0.2% offset yield strength σy.
- Ultimate tensile strength σUTS.
- Fracture strength σf.
- Ductility metrics: %EL, %RA.
- Example property table (room-temperature, typical):
- Aluminium: σ<em>y≈35MPa,σ</em>UTS≈90MPa,%EL≈40.
- Steel 1020: σ<em>y≈180MPa,σ</em>UTS≈380MPa,%EL≈25.
(Full table provided in transcript.)
Calculating Ductility
- Percent elongation:
- %EL=L0L<em>f−L</em>0×100.
- Percent reduction in area:
- %RA=A0A<em>0−A</em>f×100.
- Requires measurements after fracture (final gauge length & necked diameter).
Linear Elasticity & Hooke’s Law
- For tension/compression: σ=Eε.
- Rearrangements:
- E=εσ.
- ε=Eσ.
- Elastic elongation of prismatic bar:
- ΔL=A</em>0EFL<em>0.
Example Problems (Highlights)
Example 1: Elastic Elongation of Copper Bar
- Given: L<em>0=305mm, σ=276MPa, E</em>Cu=110GPa.
- ΔL=EσL0=110×103(276)(305)=0.77mm.
Example 2: Load Causing Specified Diameter Change in Brass Rod
- Diameter d0=10mm, desired Δd=−2.5×10−3mm (negative = shrink).
- Lateral strain ε<em>x=d</em>0Δd=−2.5×10−4.
- Axial strain ε<em>z=−νε</em>x=7.35×10−4 with ν=0.34.
- Axial stress σ=Eε<em>z=71.3MPa (E</em>Brass=97GPa).
- Load: F=σA0=(71.3×106)4π(10×10−3)2=5.6kN.
Example 3: Brass Specimen – Properties from Stress–Strain Curve
- (a) E≈94GPa (from linear slope).
- (b) σy≈250MPa at 0.2% offset.
- (c) Max load for d<em>0=12.8mm: F</em>max=57.9kN using σUTS=450MPa.
- (d) For σ=345MPa, read ε≈0.06 → ΔL=(0.06)(250)=15mm.
Example 4: Steel Specimen Ductility & True Stress at Fracture
- d<em>0=12.8mm,d</em>f=10.7mm,σf=460MPa.
- A<em>0=128.7mm2,A</em>f=89.9mm2.
- %RA=128.7128.7−89.9×100=30%.
- Load at fracture: F=σ<em>fA</em>0=59.2kN.
- True stress at fracture: σ<em>T=A</em>fF=660MPa.
Key Equations (Summary)
- Engineering stress: σ=A0F.
- Engineering strain: ε=L0ΔL.
- Hooke’s law (linear elastic): σ=Eε.
- Poisson’s ratio: ν=−εεL.
- Percent elongation: %EL=L0L<em>f−L</em>0×100.
- Percent reduction in area: %RA=A0A<em>0−A</em>f×100.
- True stress (at any instant): σ<em>T=A</em>instF; at fracture use Af.
Practical / Philosophical Implications
- Choice of material & cross-section is guided by property limits such as σ<em>y, σ</em>UTS, E, %EL ensuring safety factors.
- Ethical responsibility for engineers to avoid catastrophic failure through accurate testing & interpretation of mechanical properties.
- Awareness of test limitations (destructive, room-temperature, static) is crucial; actual service may involve high T, cyclic or impact loads → additional tests (creep, fatigue, impact) required.
Connections & Real-World Relevance
- Design codes (ASME, AISC, ISO) embed yield & tensile requirements; test data feed into Finite-Element stress analyses.
- Ductility metrics inform forming processes (rolling, drawing) and failure modes (ductile vs brittle fracture).
- Poisson’s ratio enters vibration, stability and multi-axial stress calculations (e.g., pressure vessels, biomechanics).
Reference Values (Room-Temperature)
- E<em>Steel≈207GPa; E</em>Al≈69GPa; E<em>Brass≈97GPa; E</em>Cu≈110GPa.
- Shear modulus G linked: G=2(1+ν)E for isotropic materials.
Testing Ethics & Disclaimer
- Tests are destructive; specimens permanently deformed/fractured.
- Data compiled for educational, non-commercial purposes; reliability depends on cited sources (Callister, Smith & Hashemi, etc.).