Calculating Reaction Rates, Collision Theory, and Reaction Mechanisms

Calculating Reaction Rates Practice

  • Reaction components and chemical equation: Reaction of solid zinc with aqueous hydrochloric acid to produce hydrogen gas and aqueous zinc chloride.

    • Chemical Equation: Zn(s)+2HCl(aq)→H2(g)+ZnCl2(aq)Zn_{(s)} + 2HCl_{(aq)} \rightarrow H_{2(g)} + ZnCl_{2(aq)}

  • Experimental Setup and Data:

    • Initial conditions: A piece of zinc is dropped into 1.00 dm31.00\,dm^3 (1.00 L1.00\text{ L}) of 0.100 M HCl0.100\text{ M } HCl.

    • Time vs. Mass Data:

    • 0 s0\text{ s}: 0.016 g0.016\text{ g}

    • 4 s4\text{ s}: 0.014 g0.014\text{ g}

    • 8 s8\text{ s}: 0.012 g0.012\text{ g}

    • 12 s12\text{ s}: 0.010 g0.010\text{ g}

    • 16 s16\text{ s}: 0.008 g0.008\text{ g}

    • 20 s20\text{ s}: 0.006 g0.006\text{ g}

  • Rate Calculations and Conceptual Questions:

    • Average rate of reaction in grams of ZnZn consumed per second:

    • Rate of Reaction=−ΔmassΔt=−(0.006 g−0.016 g20 s)=5×10−4 g s−1\text{Rate of Reaction} = -\frac{\Delta \text{mass}}{\Delta t} = -\left(\frac{0.006\text{ g} - 0.016\text{ g}}{20\text{ s}}\right) = 5 \times 10^{-4}\text{ g\,s}^{-1}

    • Average rate of reaction in moles of ZnZn consumed per second:

    • Molar mass of ZnZn (MM) = 65.38 g mol−165.38\text{ g\,mol}^{-1}

    • Formula: n=mMn = \frac{m}{M}

    • Rate: 5×10−4 g s−165.38 g mol−1=7.65×10−6 mol s−1≈8×10−6 mol s−1\frac{5 \times 10^{-4}\text{ g\,s}^{-1}}{65.38\text{ g\,mol}^{-1}} = 7.65 \times 10^{-6}\text{ mol\,s}^{-1} \approx 8 \times 10^{-6}\text{ mol\,s}^{-1}

    • Effect on [HCl][HCl] as reaction proceeds: Concentration decreases as HClHCl is consumed by reacting with zinc.

    • Effect on [ZnCl2][ZnCl_2] as reaction proceeds: Concentration increases because ZnCl2ZnCl_2 is a product formed in the reaction.

  • Reaction of Magnesium with Hydrochloric Acid:

    • Chemical Description: Reaction of magnesium metal with dilute hydrochloric acid to form hydrogen gas and aqueous magnesium chloride.

    • Balanced Chemical Equation: Mg(s)+2HCl(aq)→H2(g)+MgCl2(aq)Mg_{(s)} + 2HCl_{(aq)} \rightarrow H_{2(g)} + MgCl_{2(aq)}

    • Rate Stoichiometry Problems:

    • Given: Rate of consumption of magnesium = 5.0×10−9 mol s−15.0 \times 10^{-9}\text{ mol\,s}^{-1}

    • Rate of consumption of HClHCl: 5.0×10−9 mol s−1×(2 mol HCl1 mol Mg)=1.0×10−8 mol s−1 HCl5.0 \times 10^{-9}\text{ mol\,s}^{-1} \times \left(\frac{2\text{ mol } HCl}{1\text{ mol } Mg}\right) = 1.0 \times 10^{-8}\text{ mol\,s}^{-1}\text{ } HCl

    • Rate of production of H2H_2: 5.0×10−9 mol s−1×(1 mol H21 mol Mg)=5.0×10−9 mol s−1 H25.0 \times 10^{-9}\text{ mol\,s}^{-1} \times \left(\frac{1\text{ mol } H_2}{1\text{ mol } Mg}\right) = 5.0 \times 10^{-9}\text{ mol\,s}^{-1}\text{ } H_2

    • Mass of Magnesium consumed in 5.0 minutes5.0\text{ minutes}:

    • Time conversion: 5.0 min=300 s5.0\text{ min} = 300\text{ s}

    • Step 1 (Moles consumed): nMg=5.00×10−9 mol s−1×300 s=1.5×10−6 moln_{Mg} = 5.00 \times 10^{-9}\text{ mol\,s}^{-1} \times 300\text{ s} = 1.5 \times 10^{-6}\text{ mol}

    • Step 2 (Mass calculation): m=n×M=1.5×10−6 mol×24.305 g mol−1=3.645×10−5 g≈3.65×10−5 gm = n \times M = 1.5 \times 10^{-6}\text{ mol} \times 24.305\text{ g\,mol}^{-1} = 3.645 \times 10^{-5}\text{ g} \approx 3.65 \times 10^{-5}\text{ g}

Collision Theory & Rate Factors

  • Requirements for Chemical Reaction (Collision Theory):

    • For two substances to react, chemical bonds must break and form. Reacting species must:

    • Collide with one another.

    • Have correct orientation to overcome activation energy barrier.

    • Possess enough energy (kinetic energy equal to or greater than activation energy).

    • It is very rare for all required criteria to happen simultaneously during a collision.

  • Key Energy Definitions:

    • Kinetic Energy: The energy of movement; temperature is a measurement of average kinetic energy.

    • Activation Energy (EaE_a): The minimum amount of energy required for a chemical reaction to occur.

  • Potential Energy (PE) Diagrams:

    • Exothermic Reaction:

    • Potential energy of reactants is higher than potential energy of products.

    • Peak of graph represents the transition state.

    • Activation energy (EaE_a) is the energy difference between reactants and the transition state.

    • Enthalpy change (ΔH\Delta H) is negative (releases heat to surroundings).

    • Endothermic Reaction:

    • Potential energy of reactants is lower than potential energy of products.

    • Peak of graph represents the transition state.

    • Activation energy (EaE_a) is the large energy difference between reactants and the transition state.

    • Enthalpy change (ΔH\Delta H) is positive (absorbs heat from surroundings).

Potential Energy Diagrams for Exothermic and Endothermic Reactions
  • Activation Energy for Reversible Reactions:

    • Reversible System Example: CO(g)+NO2(g)⇌CO2(g)+NO(g)CO_{(g)} + NO_{2(g)} \rightleftharpoons CO_{2(g)} + NO_{(g)}

    • Reaction profile elements:

    • Reactants: CO(g)+NO2(g)CO_{(g)} + NO_{2(g)}

    • Peak: Activated complex

    • Forward Activation Energy (Ea(fwd)E_{a(fwd)}): Energy barrier from reactants to activated complex.

    • Reverse Activation Energy (Ea(rev)E_{a(rev)}): Energy barrier from products to activated complex.

    • Products: CO2(g)+NO(g)CO_{2(g)} + NO_{(g)}

    • Enthalpy change (ΔH\Delta H): Difference in potential energy between reactants and products.

Summary of Factors Affecting Rate

  • Factors Affecting Reaction Rates Table:

    • Concentration:

    • Effect on Rate: Rate increases as concentration ([][\quad]) increases (Rate↑ as []↑\text{Rate} \uparrow\text{ as }[\quad] \uparrow).

    • Reason: More reactant molecules present per unit volume leading to a higher frequency/chance of collisions.

    • Pressure (Gases Only):

    • Effect on Rate: Rate increases as pressure increases (P↑P \uparrow).

    • Reason: Decreased volume (Boyle's Law) forces particles closer together, creating a higher chance of collision.

    • Surface Area:

    • Effect on Rate: Rate increases as surface area increases (Rate ↑\uparrow as Surface Area ↑\uparrow).

    • Reason: Exposes more solid/liquid particles to the outer boundary, increasing collision opportunities (e.g., sugar dissolving faster when finely ground).

    • Temperature:

    • Effect on Rate: Rate increases as temperature increases (T↑T \uparrow).

    • Reason: Increasing TT adds kinetic energy, making particles move faster with more energy to overcome activation energy (EaE_a).

    • Catalyst:

    • Effect on Rate: Rate increases with addition of a catalyst.

    • Reason: Provides an alternate reaction pathway with a lower activation energy (EaE_a), enabling a greater proportion of molecules to possess sufficient energy to react.

Catalyzed vs Uncatalyzed Reaction Profile

Mechanistic Details of Rate Factors

  • Fundamental Determinants of Reaction Rate:

    • Determined by frequency of particle collisions.

    • Determined by proportion of collisions that result in broken bonds, which depends on collision energy and collision orientation.

    • Any factor influencing collision frequency or collision energy/orientation affects reaction rate.

  • Detailed Mechanism of Factors:

    • Temperature:

    • Higher temperature causes reactant particles to move faster, giving them more kinetic energy.

    • Faster movement increases collision frequency.

    • Higher kinetic energy means a larger proportion of collisions meet or exceed activation energy (EaE_a) to break bonds, further increasing rate.

    • Concentration and Pressure:

    • An increase in concentration of solutions or pressure of gases increases number of particles in a given volume.

    • More particles in a given space yields more total collisions, increasing rate.

    • Surface Area:

    • Increasing surface area of solids or liquids exposes more surface particles to collisions.

    • Greater number of exposed particles leads to more collisions, increasing rate.

    • Stirring:

    • Stirring a heterogeneous reaction mixture (mixture with two or more phases) increases collision rate between reactant particles, increasing overall reaction rate.

    • Catalysts:

    • Catalysts lower activation energy (EaE_a) required to break bonds by orienting molecules in specific alignments that weaken existing bonds.

    • Lower activation energy means a larger proportion of collisions have sufficient energy to react, increasing rate.

    • Catalysts are not consumed or permanently changed in chemical reactions.

    • Biological catalysts are called enzymes.

Visual Diagrams for Temperature, Concentration, and PressureVisual Diagrams for Surface Area, Stirring, and Catalysts
  • Comprehensive Impact Matrix:

    • Increasing temperature: Increases collision number; does not change EaE_a but increases kinetic energy so more particles overcome EaE_a ; increases reaction rate.

    • Increasing pressure of gases: Increases collision number; no effect on collision energy; increases reaction rate.

    • Increasing concentration of solutions: Increases collision number; no effect on collision energy; increases reaction rate.

    • Increasing surface area of solid/liquid reactants: Increases collision number; no effect on collision energy; increases reaction rate.

    • Stirring heterogeneous reaction mixtures: Increases collision number; no effect on collision energy; increases reaction rate.

    • Using a catalyst: No effect on collision number; lowers EaE_a so more particles can overcome it; increases reaction rate.

  • Summary Matching of Factors to Primary Effects:

    • Temperature: Affects the speed of particles, thereby influencing both frequency and kinetic energy of collisions.

    • Pressure and concentration: Affects the number of particles in a given volume, thereby influencing collision frequency.

    • Surface area and stirring: Affects the quantity of reactant particles exposed to collisions, thereby influencing collision frequency.

    • Catalyst: Lowers energy barrier required for collisions to break existing bonds.

Rate Laws

  • General Rate Law Expression:

    • For a general reaction: aA+bB→cABaA + bB \rightarrow cAB

    • Rate Law formula: r=k[A]x[B]yr = k [A]^x [B]^y

  • The Rate Constant (kk):

    • Value varies with temperature only.

    • If kk is very large, reaction proceeds very rapidly.

    • If kk is very small, reaction proceeds very slowly.

  • Reaction Orders:

    • Overall Order: Sum of individual reactant exponents in the rate law (x+yx + y).

    • Order with Respect to Specific Reactants: Expressed as "xxth order for reactant AA" and "yyth order for reactant BB".

  • Order Characteristics Table:

    • 0th Order (Zero Order):

    • Effect on Rate: Rate is completely unaffected by concentration of any reactant (A+B→ABA + B \rightarrow AB).

    • Rate Law Equation: r=k[A]0[B]0⇒r=kr = k [A]^0 [B]^0 \Rightarrow r = k

    • Concentration vs. Time Graph: Linear downward slope with constant negative gradient.

    • 1st Order (First Order):

    • Effect on Rate: Rate is directly proportional to concentration of a single reactant.

    • Rate Law Equation: r=k[A]1r = k [A]^1 or r=k[B]1r = k [B]^1

    • Concentration vs. Time Graph: Exponential decay curve.

    • 2nd Order (Second Order):

    • Effect on Rate: Rate is proportional to concentration of both reactants combined or proportional to the square of concentration of one reactant ([]2[\quad]^2).

    • Rate Law Equation: r=k[A]1[B]1r = k [A]^1 [B]^1, r=k[A]2r = k [A]^2, or r=k[B]2r = k [B]^2

    • Concentration vs. Time Graph: Steep exponential decay curve.

Rate Law Concentration vs Time Graphs

Reaction Mechanisms

  • Important Mechanism Terms:

    • Reaction Mechanism: A series of elementary steps that make up an overall chemical reaction (analogous to Hess' Law steps).

    • Elementary Step: A single simple step/reaction in a multi-step reaction mechanism that adds up to the overall reaction.

    • Reaction Intermediate: A chemical species produced in one elementary step and subsequently consumed in a later elementary step.

    • Catalyst: A substance that is consumed in an early elementary step and subsequently regenerated as a product in a later step (remains unconsumed overall).

  • Example Reaction Mechanism:

    • Overall Reaction: 2N2O(g)→2N2(g)+O2(g)2N_2O_{(g)} \rightarrow 2N_{2(g)} + O_{2(g)}

    • Elementary Step 1: N2O→N2+ON_2O \rightarrow N_2 + O

    • Elementary Step 2: N2O+O→N2+O2N_2O + O \rightarrow N_2 + O_2

  • Molecularity of Elementary Steps:

    • Elementary steps typically involve 1 or 2 colliding molecules.

    • Unimolecular: Involves 1 reactant molecule in the elementary step.

    • Equation: A→productsA \rightarrow \text{products}

    • Elementary Rate Law: r=k[A]r = k [A]

    • Bimolecular: Involves 2 reactant molecules colliding in the elementary step.

    • Equation: A+B→products  ⟹  r=k[A][B]A + B \rightarrow \text{products} \implies r = k [A][B]

    • Equation: 2A→products  ⟹  r=k[A]22A \rightarrow \text{products} \implies r = k [A]^2

  • Rate-Determining Step (RDS):

    • Reaction rates are determined experimentally.

    • For a reaction mechanism, the slowest elementary step dictates the overall rate of reaction.

    • Slowest step is termed the Rate-Determining Step (RDS).

    • Stoichiometric coefficients of reactants in the RDS equation determine the rate law for the overall reaction.

Oxidation of HBr Mechanism Problem

  • Overall Reaction System:

    • Balanced overall equation: 4HBr(g)+O2(g)→2H2O(g)+2Br2(g)4HBr_{(g)} + O_{2(g)} \rightarrow 2H_2O_{(g)} + 2Br_{2(g)}

    • Proposed multi-step mechanism:

    • Step 1: HBr(g)+O2(g)→HOOBr(g)HBr_{(g)} + O_{2(g)} \rightarrow HOOBr_{(g)}

    • Step 2: HOOBr(g)+HBr(g)→2HOBr(g)HOOBr_{(g)} + HBr_{(g)} \rightarrow 2HOBr_{(g)}

    • Step 3: 2(HOBr(g)+HBr(g)→H2O(g)+Br2(g))⇒2HOBr(g)+2HBr(g)→2H2O(g)+2Br2(g)2\left(HOBr_{(g)} + HBr_{(g)} \rightarrow H_2O_{(g)} + Br_{2(g)}\right) \Rightarrow 2HOBr_{(g)} + 2HBr_{(g)} \rightarrow 2H_2O_{(g)} + 2Br_{2(g)}

  • Analysis Questions and Solutions:

    • Elementary Steps Addition Verification:

    • Adding all three steps together:       HBr+O2→HOOBrHOOBr+HBr→2HOBr2HOBr+2HBr→2H2O+2Br2\begin{aligned} HBr + O_2 &\rightarrow HOOBr \\ HOOBr + HBr &\rightarrow 2HOBr \\ 2HOBr + 2HBr &\rightarrow 2H_2O + 2Br_2 \end{aligned}

    • Canceling intermediate species (HOOBrHOOBr and 2HOBr2HOBr) on both sides yields: 4HBr+O2→2H2O+2Br24HBr + O_2 \rightarrow 2H_2O + 2Br_2

    • Result: Yes, elementary steps add up to the overall balanced equation.

    • Elementary Step Rate Laws:

    • Step 1 Rate Law: r1=k1[HBr][O2]r_1 = k_1 [HBr][O_2]

    • Step 2 Rate Law: r2=k2[HOOBr][HBr]r_2 = k_2 [HOOBr][HBr]

    • Step 3 Rate Law: r3=k3[HOBr]2[HBr]2r_3 = k_3 [HOBr]^2 [HBr]^2

    • Identification of Intermediates:

    • Chemical species HOOBrHOOBr and HOBrHOBr are intermediates because both are produced in one step and consumed in a subsequent step.

    • Identification of Catalysts:

    • There are no catalysts in this reaction, as no chemical species is introduced as an initial reactant and subsequently regenerated as a final product.

    • Rate-Determining Step Deduction:

    • Experimental finding: Overall reaction is first order with respect to HBrHBr and first order with respect to O2O_2 (rexp=k[HBr]1[O2]1r_{exp} = k [HBr]^1 [O_2]^1).

    • Comparison: Rate law of Step 1 (r1=k1[HBr][O2]r_1 = k_1 [HBr][O_2]) matches experimental rate law.

    • Conclusion: Step 1 must be the slow rate-determining step (RDS) that dictates the overall reaction rate.