Geometric Sequence: nth Term (Notes and Examples)
Definitions and Key Formula
Geometric sequence: a sequence where the ratio between consecutive terms is constant.
Variables in the nth-term formula:
a_n = the nth term of the sequence.
a_1 = the first term of the sequence.
r = the common ratio (the factor between successive terms).
n = the term position (the term number you want).
Core formula for the nth term:
an = a1 rn-1
Explanation: exponent is (n-1) because when (n=1) you should get the first term: (a1 = a1) and ( an = the nth term)
How to identify geometric vs arithmetic sequences
Look at consecutive terms:
Arithmetic sequence has a constant difference: (d = a
Geometric sequence has a constant ratio: (r = \dfrac{a{k+1}}{ak}).
Example sequence: 3, 6, 12, 24
Check differences: (6-3=3, 12-6=6, 24-12=12) — not constant, so not arithmetic.
Check ratios: (\dfrac{6}{3}=2, \dfrac{12}{6}=2, \dfrac{24}{12}=2) — constant ratio, so geometric with r=2.
Identify initial term: a_1 = 3.
Step-by-step method to find a_n for a geometric sequence
Step 1: Verify the sequence is geometric (find and confirm the common ratio r).
Step 2: Record the known values from the sequence: a_1 and r.
Step 3: Decide which term you need, i.e., determine n.
Step 4: Substitute into the nth-term formula: an = a1 \, r^{\,n-1}.
Step 5: Compute the power and then multiply by the first term.
Note on computation:
Powers can be computed by hand or with a calculator (e.g., 2^{6} = 64, \; 2^{9} = 512).
Example 1: Find the seventh term of 3, 6, 12, 24
Given sequence: 3, 6, 12, 24
Determine parameters:
a_1 = 3
Common ratio: r = \dfrac{6}{3} = 2 (also \dfrac{12}{6}=2, \dfrac{24}{12}=2)
Target term: n=7
Compute using the formula:
a7 = a1 \cdot r^{7-1} = 3 \cdot 2^{6}
Evaluate: 2^{6} = 64
Multiply: 3 \cdot 64 = 192
Result: a_7 = 192
Interpretation: The seventh term of the sequence is 192.
Example 2: Find the tenth term of 3, 6, 12, 24
Given sequence: 3, 6, 12, 24 (same as above)
Parameters unchanged:
a_1 = 3
r = 2
Target term: n=10
Compute using the formula:
a{10} = a1 \cdot r^{10-1} = 3 \cdot 2^{9}
Evaluate: 2^{9} = 512
Multiply: 3 \cdot 512 = 1536
Result: a_{10} = 1536
Interpretation: The tenth term of the sequence is 1536.
Quick assignment (from the video)
Using the same sequence, find the 12th term:a{12} = a1 \cdot r^{12-1} = 3 \cdot 2^{11} = 3 \cdot 2048 = 6144.
Note: This follows directly from the same steps; the 12th term would be 6144 given the sequence 3, 6, 12, 24.
Practical tips and common pitfalls
Always confirm the type of sequence before applying the formula.
Be careful with the exponent: it is always (n-1) for the nth term formula.
If a term or ratio is negative or fractional, the same method applies: compute with the given a_1 and r.
Use a calculator for large powers, but verify smaller powers with mental math where convenient.
Remember the interpretation: geometric sequences exhibit exponential growth or decay depending on the sign and magnitude of r.
Connections to broader concepts
The nth-term formula is a specific case of exponential functions: terms grow by a constant factor each step.
Real-world relevance includes compound interest, population growth/decay, and any process with multiplicative changes over time.
Foundational principle: discrete exponential dynamics, in contrast to linear changes in arithmetic sequences.
Summary of key formulas
Geometric nth term: an = a1 \, r^{\,n-1}
Common ratio from terms: r = \dfrac{a{k+1}}{ak} \, (k\ge 1)
Example computations from the transcript:
For the sequence 3, 6, 12, 24 with a_1 = 3, \; r = 2:
a_7 = 3 \cdot 2^{6} = 192
a_{10} = 3 \cdot 2^{9} = 1536