Topic 7: Materials

Materials Overview

  • Deforming materials: Understanding how materials respond to applied forces.

  • Stress and strain: Quantifying the deformation of materials under load.

  • Young’s modulus: Measures a material's resistance to stretching.

  • Shear modulus: Measures a material's resistance to shear stress.

  • Bulk modulus: Measures a material's resistance to uniform compression.

  • Thermal expansion: How materials change in size with temperature changes.

  • Phases of matter: Solid, liquid, and gas states and their properties.

Applying Forces to Materials

  • Examples of forces applied to materials:

    • Stretching a rubber band or bungee rope.

    • Bending sheet metal like a car body panel.

    • Predicting the weight a bridge, lift cable, or floor can withstand.

    • Squeezing rocks to produce layered strata.

  • Applying a force results in a measurable deformation.

Deformation of Materials

  • Normal Stress: Force applied perpendicularly to an area.

    • Compressional stress: Stress that decreases the volume of the material.

    • Tensional stress: Stress that increases the length of the material.

    • σ=FA\sigma = \frac{F}{A}, where σ\sigma is stress, FF is force, and AA is area.

  • Shear Stress: Force applied parallel to a surface area.

    • Shear Stress=FA\text{Shear Stress} = \frac{F}{A}, where FF is the force applied parallel to the surface and AA is the area of the surface.

Stress and Strain

  • Stress: Tensile (stretching) force FF applied to a rope of cross-sectional area AA.

    • stress σ=Force FArea A\text{stress } \sigma = \frac{\text{Force } F}{\text{Area } A}

    • Units of stress are Nm2N \cdot m^{-2} (Pascals, Pa), equivalent to pressure units.

  • Strain: Fractional change in length due to stress.

    • strain ϵ=displacement eLength l\text{strain } \epsilon = \frac{\text{displacement } e}{\text{Length } l}

    • Strain is dimensionless.

Young’s Modulus

  • Young’s modulus is an inverse measure of stretchiness.

    • A metal cable will undergo less strain than a bungee rope of the same area, length, and force applied.

  • For small stresses, stress is proportional to strain:

    • σϵ\sigma \propto \epsilon

  • Constant of proportionality is Young’s modulus, EE.

    • σ=Eϵ\sigma = E \epsilon

    • E=σϵE = \frac{\sigma}{\epsilon}

Young's Modulus (Continued)

  • Young's modulus: Property of a material that indicates how easily it stretches and deforms.

  • Key point: relates Force FF to fractional-extension el\frac{e}{l}

    • E=σϵ=F/Ae/l=FleAE = \frac{\sigma}{\epsilon} = \frac{F/A}{e/l} = \frac{Fl}{eA}

  • Units of Young's modulus are Nm2=PaN \cdot m^{-2} = Pa, the same as stress.

  • Values of Young's modulus:

    • Steel: 21×1010Pa=210GPa21 \times 10^{10} Pa = 210 GPa (very low stretch)

    • Copper: 130GPa130 GPa

    • Glass: 70GPa70 GPa

    • Polyethylene: 5GPa5 GPa

    • Rubber: 0.05GPa0.05 GPa (very stretchy)

    • Quartz Crystal (SiO2): 7697GPa76-97 GPa

    • Diamond (C): 10501210GPa1050-1210 GPa

    • Graphene and carbon nanotube (C): +1000GPa+1000 GPa

Example

  • A 100g weight is hung on a 1.5m length of copper wire with a cross sectional area of 0.1mm2\text{mm}^2. By how much is the wire stretched? For copper Young’s modulus is 130GPa.

  • Use σ=Eϵ\sigma = E \epsilon, so ϵ=σE\epsilon = \frac{\sigma}{E}

  • σ=FA=mgA=0.1 kg×9.8 ms20.1 mm2×106 m2/mm2=9.8×106 Nm2\sigma = \frac{F}{A} = \frac{mg}{A} = \frac{0.1 \text{ kg} \times 9.8 \text{ ms}^{-2}}{0.1 \text{ mm}^2 \times 10^{-6} \text{ m}^2/\text{mm}^2} = 9.8 \times 10^6 \text{ Nm}^{-2}

  • ϵ=σE=9.8×106 Nm2130×109 Pa=7.5×105\epsilon = \frac{\sigma}{E} = \frac{9.8 \times 10^6 \text{ Nm}^{-2}}{130 \times 10^9 \text{ Pa}} = 7.5 \times 10^{-5}

  • Extension e=ϵl=7.5×105×1.5m=1.13×104 me = \epsilon l = 7.5 \times 10^{-5} \times 1.5\text{m} = 1.13 \times 10^{-4} \text{ m}

Shear Modulus

  • Shear modulus is like Young’s modulus but for “shear”

    • Shear Modulus = shear stressshear strain\frac{\text{shear stress}}{\text{shear strain}}

  • Shear stress = force FF applied to top face of block area AA of top face of block.

  • Shear strain = tanθ\tan \theta

  • Δxl=tanθ\frac{\Delta x}{l} = \tan \theta

Seismic Waves (S- and P-waves)

  • Seismic waves are used to study the Earth's internal structure.

  • Waves are refracted (bent) as they pass through different layers.

  • Wave speed depends on density, allowing mapping of density changes with depth.

  • Earth is composed of layers: inner core, outer core, mantle.

  • P-waves: refracted at core-mantle boundary, create shadow zones.

  • S-waves: do not reappear, indicating liquid outer core.

Seismic waves (S- and P- waves) Continued

  • After an earthquake, seismic waves travel through the Earth’s interior.

  • Two types: primary (P-waves) and secondary (S-waves).

    • P-waves (Primary):

      • Longitudinal.

      • Speed depends on compressibility of the medium (rock) but faster than S-waves.

      • Can travel in solids and liquids.

    • S-Waves (Secondary):

      • Transverse.

      • Speed depends on different properties of medium (rock elasticity / stiffness).

      • Cannot travel in liquids (rapid diffusion).

      • Not propagated through Earth’s core.

Shear Modulus Continued

  • The velocity of a shear wave, vsv_s, depends on the shear modulus

    • vs=Gρv_s = \sqrt{\frac{G}{\rho}}; GG = shear modulus, ρ\rho = solid’s density

  • Typical values for shear modulus

    • Diamond 478 GPa

    • Steel 79 GPa

    • Glass 26 GPa

    • Polyethylene 0.117 GPa

    • Rubber 0.0006 GPa

Bulk Modulus (uniform compression)

  • A volume of a substance is compressed by a change in external pressure; volume reduces (e.g. waste material in a landfill site).

  • Bulk strain: relative change in volume ΔVV\frac{\Delta V}{V} (where VV is the original volume).

  • Bulk stress: increase in external pressure Δp\Delta p

  • Bulk modulus: K=bulk stressbulk strain=ΔpΔVV=VΔpΔVK = \frac{\text{bulk stress}}{\text{bulk strain}} = - \frac{\Delta p}{\frac{\Delta V}{V}} = -V \frac{\Delta p}{\Delta V}

  • Values of bulk modulus:

    • Steel 160 GPa

    • Glass 35-55 GPa (note the minus sign indicates compression)

    • Water 2.2 GPa

Example - Bulk Modulus

  • A steel bar with a volume of 104 m310^{-4} \text{ m}^3 at the surface is taken to a depth of 1 km in the ocean. By how much does its volume change?

  • Δp=ρgh=1000 kg m3×9.8 ms2×1000 m=9.8×106 Pa\Delta p = \rho gh = 1000 \text{ kg m}^{-3} \times 9.8 \text{ ms}^{-2} \times 1000 \text{ m} = 9.8 \times 10^6 \text{ Pa}

  • ΔV=VΔpK=104 m3×9.8×106 Pa160×109 Pa=6.1×109 m3\Delta V = -V \frac{\Delta p}{K} = - 10^{-4} \text{ m}^3 \times \frac{9.8 \times 10^6 \text{ Pa}}{160 \times 10^9 \text{ Pa}} = -6.1 \times 10^{-9} \text{ m}^3

Compressibility

  • Compressibility = 1bulk modulus\frac{1}{\text{bulk modulus}}

  • If you want to work out how much you can squash into a landfill site, the compressibility of various waste materials is relevant.

  • The velocity of a pressure wave, vpv_p, depends on both the bulk modulus KK and the shear modulus GG

    • vp=K+43Gρv_p = \sqrt{\frac{K + \frac{4}{3} G}{\rho}}

Stiffness of Materials

  • Young's modulus describes the material's response to uniaxial stress.

    • Examples: pulling on the ends of a wire or putting a weight on top of a column.

  • Shear modulus describes the material's response to shear stress.

    • Example: cutting it with dull scissors.

  • Bulk modulus describes the material's response to uniform pressure.

    • Examples: the pressure at the bottom of the ocean or a deep swimming pool.

Thermal Expansion

  • Solids and liquids usually expand when heated.

  • Different materials expand by different amounts.

  • Expansion occurs in all directions.

  • Water is unusual – it expands when it freezes → burst pipes, freeze-thaw weathering

  • Physics laws for thermal expansion similar to those we’ve explained for extension of elastic materials

Linear Thermal Expansion (1 dimension)

  • Examples: mercury thread in thermometer, metal rod or bar

  • LL = original length, ΔL\Delta L = increase in length, ΔT\Delta T = change in temperature

  • α\alpha is the coefficient of linear thermal expansion.

  • Very similar equation to that for Young’s modulus (EE)

    • tensile strain, e=ΔLL=(1E)σ=(1E)(Forcecross-sec-area)e = \frac{\Delta L}{L} = (\frac{1}{E})\sigma = (\frac{1}{E})(\frac{\text{Force}}{\text{cross-sec-area}})

    • thermal expansion, ΔLL=αΔT\frac{\Delta L}{L} = \alpha \Delta T (change-in-temperature)

    • α=ΔLL1ΔT\alpha = \frac{\Delta L}{L} \frac{1}{\Delta T}

Coefficient of linear thermal expansion, α\alpha

  • α\alpha has units of K1^{-1}

  • ΔL=LTL0LT=L0(1+αΔT)\Delta L=L_{T}-L_0\rightarrow L_{T}=L_0\left(1+\alpha\Delta T\right)

    • where L0_{0} is the length after a temperature rise ΔT\Delta T

    • (note: in reality, α\alpha varies slightly with temperature but this can be neglected in most applications because small across temperature range in the environment).

    • ΔLL=αΔT\frac{\Delta L}{L} = \alpha \Delta T

Values of linear thermal expansion (at 20°C)

  • Steel 1.1 to 1.3 x 10-5 K1^{-1}

  • Copper 1.7 x 10-5 K1^{-1}

  • Brass 1.9 x 10-5 K1^{-1}

  • Concrete 1.2 x 10-5 K1^{-1}

  • Water 6.9 x 10-5 K1^{-1}

  • Rubber 7.7 x 10-5 K1^{-1}

  • Oak 5.4 x 10-5 K1^{-1}

  • Diamond 1.0 x 10-6 K1^{-1}

Example of Linear Thermal Expansion

  • A 0.5m long brass rod is heated from 20°C to 100°C. By how much does the length of the rod change?

  • Use ΔL=LαΔT\Delta L = L \alpha \Delta T

    • = 0.5 m x 1.9 x 10-5 K1^{-1} x 80 K

    • = 7.6 x 10-4 m

Bimetallic strip

  • Bimetallic strip made by joining together 2 different metals with different linear thermal expansion coefficients

  • Bends when heated

  • Uses:

    • Thermometer

    • In thermostats

    • Temperature compensation in clocks

    • Circuit breakers

Coefficient of volume expansion γ\gamma

  • γ\gamma is the fractional increase in volume per unit temperature rise

  • V<em>T=V</em>0(1+γΔT)V<em>T = V</em>0 (1 + \gamma \Delta T )

    • where V<em>0V<em>0 is the original volume and V</em>TV</em>T is the volume after a temperature rise ΔT\Delta T

  • γ=3α\gamma = 3\alpha

Thermal expansion - sea level rise

  • Thermal expansion of water contributes to sea level rise.

  • IPCC projections for 21st-century sea level rise include contributions from:

    • Thermal expansion

    • Melting glaciers

    • Melting ice sheets (Greenland and Antarctica)

  • Different Representative Concentration Pathways (RCPs) predict varying levels of sea level rise.

Density change with temperature

  • A liquid has a density ρ0\rho_0 at a certain temperature

  • If the temperature rises by T degrees then the density decreases to ρθ\rho_{_{\theta}}

  • ρ0=ρθ(1+γT)\rho_{0_{}}=\rho_{\theta}\left(1+\gamma T\right)

  • density change of a liquid as it expands relates to its coefficient of thermal expansion \rightarrow that’s because density is mass/volume and volume increases as liquid expands.

Expansion of water

  • Water has its maximum density at 4ºC

  • Cool from 20ºC to 4ºC → contracts

  • Cool from 4ºC to 0ºC → expands

  • Becomes solid at 0ºC

  • Below 0ºC → contracts slightly

  • 100 cm3 of water becomes 109 cm3 of ice.

  • Densities:

    • ice at 0 °C: 0.917 g/cm3

    • water at 0 °C: 0.9998 g/cm3

    • ice at −180 °C: 0.934 g/cm3

Phases of matter

  • Inter-atomic / inter-molecular forces pull atoms / molecules together.

  • Motion due to internal energy pushes them apart

  • Balance between these two forces determines whether the material is solid, liquid or gas.

Solids, liquids and gases

  • Solids

    • Atoms / molecules vibrate about equilibrium positions

    • Well ordered, packed together

  • Liquids

    • Atoms / molecules can partly overcome the interatomic / intermolecular forces

    • Move randomly but can't leave the liquid

    • Less ordered but still closely packed

  • Gases

    • Atoms / molecules move randomly at high speeds

    • Atoms / molecules are further apart and fill available space

Types of solid

  • Crystalline

    • Most solids, all metals, many minerals

    • Regular, repeating structures, ordered throughout the material

    • Polycrystalline solids are a mass of tiny crystals at various angles (e.g. metals)

  • Amorphous / glassy

    • More disordered structure

    • Short-range order only

    • E.g. glass

Recycling metals

  • Economics of recycling metals depends on:

    • purity of scrap metal

    • cost of extraction of the metal (e.g. Al is very expensive to extract from its ore)

  • Recycling is straightforward if there is a main use for a given metal

    • e.g. photographic film for silver

    • e.g. car batteries for lead

Metal alloys

  • Pure metals are often alloyed with other metals or non-metals to improve mechanical properties (e.g. 0.002-2% carbon added iron → steel for stronger/tougher metal)

  • But alloying can create problems :

    • Some elements in alloys (e.g. Al) can be leached (e.g. environmental hazard from slag heap)

    • Some elements (e.g. Cu and Sn) remain in the alloyed metal which makes re-cycling difficult.

Polymer materials (chained molecular structure)

  • Many polymer materials have variable structure some regions semi-crystalline, others amorphous

    • semi-crystalline implies its structure is ordered (where polymer chains in parallel) → rigid, fairly strong material

    • amorphous means it has disordered regions where polymer chains are tangled → here the material is soft or flexible

  • For many applications flexibility is beneficial whereas in others it is a potential weakness.

Thermo-plastics and thermoset-plastics

  • Thermoplastics are materials that can be softened by heating and re-moulding (e.g. polyethene, PVC)

  • By contrast, Thermosetting plastics are chemically cross-linked to avoid re-moulding – retain shape.

    • Strong chemical bonds are introduced between polymer chains (e.g. vulcanise = sulphur in rubber)

    • Cross-linking polymers acts to strengthen material à less temperature softening → prevent remoulding (e.g. ebonite, bakelite, melamine, Formica)

Strategies for Stronger, Stiffer Materials

  • Increase degree of crystallinity

  • Stretch material to produce more ordered material (untangles and aligns molecules)

  • Adjust chain length, chain branching

  • Chemical cross-linking

  • Produce polymer chains which are themselves stiff (e.g. by using a monomer* with a rigid ring structure)

    • *a molecule that may bind chemically to other molecules to form a polymer

Stronger, stiffer, tougher polymers

  • Co-polymers: polymerize different monomers together → co-polymer with different properties from either polymer type

  • Polymer blends: mixture of two types of polymer chain (e.g. synthetic rubber with PVC to give a rubber toughened polymer)

  • Implications of chemical cross-linking, co-polymers and blends for recycling polymers?

Summary

  • Deformation of materials (elastic properties)

    • Stress and strain – Young’s modulus

    • Shear modulus

    • Bulk modulus

  • Thermal expansion

  • Phases of matter

  • Types of solid

  • Engineering materials for particular applications

    • Alloying metals and strengthening plastics