Alkenes – Comprehensive Study Notes (AS 91165)
Alkenes – Classification + Name
- Alkenes are a homologous series of hydrocarbons that contain at least one C=C double bond.
- Naming rules:
- Suffix = -ene.
- The double bond must be on the lowest possible carbon number; the number is stated before "-ene" to indicate the location of the C=C bond.
- Alkenes are unsaturated (contain fewer than the maximum number of hydrogens).
- Examples from the transcript:
- Ethene (CH2=CH2)
- Propene (CH3-CH=CH2)
- But-1-ene (CH2=CH-CH2-CH3)
- But-2-ene (CH3-CH=CH-CH3)
- Notes on structure:
- A C=C bond prevents rotation, fixing the relative positions of groups around the double bond.
- The location of the double bond is indicated in IUPAC naming by a number (e.g., but-2-ene).
Alkenes – Geometric Isomers
- Geometric isomers arise from the same order of bonding but different spatial arrangement around the C=C bond.
- Why they exist:
- The double bond does not rotate; thus substituents on each carbon can be arranged on the same side (cis) or opposite sides (trans).
- Key features:
- Each end of the C=C must have two different groups attached to be able to distinguish cis/trans forms.
- The C=C angle around the double bond is effectively around 120° due to the sp2 geometry.
- Geometric isomers may have different physical properties but often similar chemical properties.
- Nomenclature:
- Use prefixes cis- and trans- before the alkene name, separated by a dash (e.g., cis-but-2-ene, trans-but-2-ene).
- Examples from the transcript:
- cis-1,2-dichloroethene vs trans-1,2-dichloroethene.
- But-2-ene examples showing different arrangements of CH3 groups around the double bond.
Alkenes – Physical Properties
- Similar to alkanes in many respects.
- As C-chain increases, melting point and boiling point increase.
- Insoluble in polar solvents like water; alkenes are nonpolar.
- Do not conduct electricity (no free electrons or ions).
- Density is lower than water; alkenes typically float on water.
- Physical state:
Alkenes – Chemical Properties
Combustion
- Alkenes undergo complete and incomplete combustion depending on oxygen availability.
- Complete combustion products:
- \text{CO}2 + \text{H}2 ext{O}
- Incomplete combustion products can include C, CO, H2O depending on oxygen.
- Alkenes tend to burn with a yellow, sooty flame (less cleanly than alkanes).
Preparation (from Alcohols)
- Alcohols can be dehydrated to form alkenes using concentrated sulfuric acid (H2SO4) with heat.
- Net reaction:
- Alcohol → alkene + water
- \text{Alcohol} \xrightarrow{H2SO4, heat} \text{alkene} + \text{H2O}
Zaitsev’s Rule (Say: “the poor get poorer”)
- In elimination reactions, especially with asymmetric substrates, the double bond forms preferentially at the carbon that has fewer attached hydrogens (the more substituted carbon).
- Major product: double bond between carbons with fewer hydrogens (more substituted).
- Minor product: double bond between carbons with more hydrogens (less substituted).
- This rule helps predict the major vs minor products in E2 eliminations from alkenes or haloalkanes.
Addition Reactions (to a C=C bond)
- Common reagents include H2, X2 (Br2, Cl2), H2O (acid-catalyzed hydration), ROH, and HX (HBr, HCl).
- General observation: the double bond is broken, and two atoms/groups are added across the two carbons.
- Markovnikov’s Rule (the “rich get richer”): in the addition of HX or H-OH to an asymmetric alkene, the hydrogen attaches to the carbon that already has more hydrogens, and the other group attaches to the other carbon.
- E.g., addition of HBr to propene yields 2-bromopropane as the major product and 1-bromopropane as the minor product.
- Additional rules/examples mentioned in the transcript:
- Hydration of alkenes (dilute acid) yields alcohols following Markovnikov's rule; major product often places the OH on the more substituted carbon.
- Halogen addition (Br2, Cl2) across the double bond yields vicinal dihalides (e.g., ethene + Br2 → 1,2-dibromoethane).
- Hydrogenation (H2 with Pt catalyst) across C=C yields alkanes (saturation).
- Oxidation with oxidants like KMnO4 can convert alkenes to diols (e.g., ethene to ethane-1,2-diol) under certain conditions.
- Specific examples from the transcript:
- Ethene + Br2 → 1,2-dibromoethane:
extCH<em>2=extCH</em>2+extBr<em>2ightarrowextBr−CH</em>2extCH2extBr - Ethene + H2O/H+ (hydration) → ethanol:
extCH<em>2=extCH</em>2+extH<em>2extOightarrowextCH</em>3extCH2extOH - Ethene + KMnO4 (oxidation) → ethene-1,2-diol (ethane-1,2-diol):
extCH<em>2=extCH</em>2+ext[O]<br/>ightarrowextHO−CH−CH−OHext(ethyleneglycol) - Propene + HCl (Markovnikov): major product is 2-chloropropane, minor product is 1-chloropropane.
- Major: extCH<em>3−extCH(Cl)−extCH</em>3
- Minor: extCH<em>3−extCH</em>2−extCH2extCl
Oxidation (of alkenes)
- Oxidation with oxidants like KMnO4 in dilute acid or basic conditions can add across the double bond to form diols (vicinal diols).
- Example: Ethene → ethane-1,2-diol (ethylene glycol) as noted above.
Hydrogen Halide Addition (Markovnikov and exceptions)
- Addition of HX (HCl, HBr) follows Markovnikov’s rule in most cases for asymmetric alkenes.
- Examples from the transcript include: propene + HCl → major product 2-chloropropane; minor product 1-chloropropane.
- This principle also applies to the addition of HBr and other hydrogen halides to alkenes.
Distinguishing Alkanes vs Alkenes (Bromine Water Test)
- Bromine water (Br2(aq)) test is used to distinguish alkanes from alkenes:
- Alkenes: addition reaction occurs rapidly; orange/brown Br2 is decolorized quickly.
- Alkanes: substitution with Br2 is slow; oxidation requires UV light to proceed noticeably.
- Observed color change:
- Alkenes: orange to colorless quickly (rapid, adds across double bond).
- Alkanes: slow decolorization under UV or light due to substitution mechanism.
Elimination Reactions: Haloalkanes → Alkenes
- Haloalkanes treated with KOH (alcohol) undergo elimination to form alkenes and water + potassium halide:
- Example: haloalkane (e.g., 2-chloropropane) with KOH (alc) → propene (elimination) + KCl + H2O
- Zaitsev’s rule applies: in asymmetric haloalkanes, the major alkene product forms with the double bond between the carbon that has fewer hydrogens (more substituted alkene).
- Transcript examples:
- Reaction of but-1-ene with HBr yields two products due to asymmetry of the alkene and reagent; major product corresponds to Markovnikov addition.
- In elimination from haloalkanes, the more substituted alkene is the major product (Zaitsev).
Reactions (Examples from NCEA Assessments)
- NCEA 2018 Reactions (addition): But-1-ene + HBr (asymmetric) → two products; major: 2-bromobutane; minor: 1-bromobutane; base reasoning via Markovnikov’s rule and hydrogen distribution.
- NCEA 2018 Reactions (substitution vs elimination): 2-chloropropane with KOH under different conditions:
- Dilute aqueous KOH: substitution to give propan-2-ol (primary or secondary alcohol depending on substrate).
- Concentrated KOH (alc): elimination to give propene.
- Reasoning: dilute KOH favors substitution; concentrated KOH favors elimination; symmetry of product affects whether a single product or mixture is formed.
- NCEA 2016 Reactions (addition): Ethene reacts with Br2(aq) and KMnO4(aq) and H2O/H+ and HBr under various conditions; observations include color changes (orange Br2 decolorization) and product types (diol, bromoalcohol, etc.).
Polymerisation (Alkenes to Polymers)
- Polymers are large molecules formed from many repeating units (monomers).
- Addition polymerisation: monomers add to form polymers, breaking C=C bonds in the process.
- Key idea: each monomer is derived from an alkene.
- General pattern:
- Monomer: \ce{CH2=CH2} (ethylene) → Polymer: polyethene, with repeating unit \ce{(-CH2-CH2-)_n}.
- Example: Propene monomer yields polypropylene (polypropene).
- Naming of addition polymers is based on the monomer: ethene → polyethene; propene → polypropylene; etc.
- Polymerisation in practice builds long chains by repeating the unit from the monomer until n repeats occur.
- Example from transcript: Polystyrene involves the monomer styrene (vinyl benzene) and forms polystyrene via addition polymerisation; monomer is styrene, polymer is polystyrene.
- Monomer identification from polymers:
- Example: Polystyrene monomer is styrene (C6H5-CH=CH2).
- The polymer repeating unit is -CH2-CH(C6H5)-.
Test for Unsaturation and Real-World Relevance
- Unsaturation test cases (toluene vs cyclohexene vs cyclohexane) illustrate the presence of C=C bonds (unsaturation) in cycloalkenes vs saturated rings.
- Real-world relevance:
- Alkenes are central to manufacturing polymers (polyethylene, polypropylene, polystyrene, etc.).
- Geometric isomerism affects physical properties (melting point, boiling point, crystallinity) and can influence reactivity.
- Markovnikov’s rule and Zaitsev’s rule guide product distributions in industrial alkene reactions, impacting yield and selectivity of chemicals like alcohols, halides, diols, and dihalides.
- General alkene structure: extR−CH=CH−R′
- Markovnikov addition (for HX or H2O across C=C): major product places H on the carbon with more hydrogens; example:
- Propene + HBr → major: extCH<em>3−extCH(Br)−extCH</em>3, minor: extCH<em>3−extCH</em>2−extCH2extBr
- Hydration (acid-catalyzed) on alkenes:
- extR−CH=CH−R′+extH<em>2extOightarrowextR−CH(OH)−CH</em>2−R′ (major product follows Markovnikov’s rule)
- Bromination across C=C:
- extR−CH=CH−R′+extBr2<br/>ightarrowextR−CH(Br)−CH(R′)Br
- Hydrogenation (addition of H2 to saturate):
- extR−CH=CH−R′+extH<em>2ightarrowextR−CH</em>2−extCH2ext−R′
- Oxidation of alkenes to diols (vicinal diols):
- extR−CH=CH−R′+ext[O]<br/>ightarrowextR−CH(OH)−CH(R′)OH
- Polymer repeating unit (polymer from an alkene):
- For ethene: ext(−CH<em>2−extCH</em>2−)n
- For styrene (polystyrene): monomer is extCH<em>2=extCH−Ph; polymer repeating unit is ext(−CH</em>2−extCH(Ph)−)n
Connections to Foundational Principles
- The double bond’s restricted rotation explains geometric isomerism and its impact on physical properties.
- The concept of unsaturation connects to NSA (n= number of repeating units) in polymers and to the degree of hydrogen deficiency in reactions.
- Catalysis and reaction conditions (temperature, solvent, acid concentration) govern substitution vs elimination and the selectivity of addition reactions per Markovnikov’s and Zaitsev’s rules.
- Redox chemistry (e.g., KMnO4 oxidation) demonstrates how functional groups are introduced or altered under oxidative conditions, essential for understanding transformations in organic synthesis.
Practical and Ethical Considerations
- Many of these reactions underpin industrial synthesis of plastics, solvents, and fine chemicals; understanding reaction conditions helps optimize safety, yield, and environmental impact.
- The use of strong acids (e.g., conc H2SO4) and oxidants (KMnO4) requires proper handling and waste management.
- Knowledge of reaction mechanisms and product distributions supports ethical decision-making in chemical manufacturing, including considerations of waste, byproducts, and energy use.