Aqueous Equilibria Lecture Notes
Aqueous Equilibria Notes
SECTION 17.1 INTRODUCTION TO BUFFER SOLUTIONS
Learning Goals:
Explain how buffer solutions work.
Calculate pH changes in buffer solutions after adding a strong acid or a strong base.
The Importance of Buffers
Regulation of pH is critical to survival: Organisms require a stable pH environment.
Buffer solutions control pH: These solutions actively resist pH changes through the neutralization of added acids or bases.
Governance by the common-ion effect: The ability to maintain pH is heavily influenced by the presence of common ions in solution.
The Common-Ion Effect
Ionization of Weak Acid: Nitrous Acid (HNO2):
The dissociation of a weak acid in water can be represented as:
HNO_2(aq) + H_2O(l)
ightleftharpoons NO_2^{-}(aq) + H_3O^{+}(aq)This creates small equilibrium concentrations of nitrite ion and hydronium ion.
Addition of Sodium Nitrite (NaNO2):
Formula: NaNO_2(aq)
ightarrow Na^{+}(aq) + NO_2^{-}(aq)Increases the concentration of the NO₂⁻ ion, establishing the necessary acid-base pair for buffering.
Definition of Common-Ion Effect: Suppression of ionization of a weak electrolyte when mixed with a strong electrolyte containing a common ion.
The Common-Ion Effect in Buffer Solutions
When acid is added:
Reaction: H^{+} + NO_2^{-}
ightarrow HNO_2The nitrite ion reacts with the added acid, converting it back to nitrous acid and suppressing pH changes.
When base is added:
Reaction: OH^{-} + HNO_2
ightarrow NO_2^{-} + H_2ONitrous acid reacts with the base to produce more NO₂⁻, preventing significant pH alterations.
Quiz #1: Calculation of pH
Task: Calculate the pH of the following:
(a) An aqueous solution containing 0.30 M HNO2.
(b) A solution containing 0.30 M HNO2 and 0.20 M NaNO2.
Ka of HNO2: 5.6 imes 10^{-4}
Solution to Quiz #1
General Reaction:
HNO_2(aq) + H_2O
ightleftharpoons H_3O^{+}(aq) + NO_2^{-}(aq)
Construct an ICE Table for Part (b):
Prepare an ICE table to track changes in concentrations of all species during ionization.
Buffer Solutions
Definition of Buffer Solution:
A system containing both a weak acid and its conjugate base, allowing it to resist pH changes.
Mechanism of Action:
HA(aq) + H_2O(l)
ightleftharpoons H_3O^{+}(aq) + A^{-}(aq)Addition of H⁺ shifts equilibrium left; A⁻ neutralizes forming HA.
Addition of OH⁻ shifts equilibrium right; HA neutralizes base forming products.
Principle Utilized: Le Chatelier's Principle.
Quiz #2: Buffer Solution Identification
Question: Identify which combinations yield buffer solutions:
(a) HCl and NaOH
(b) HCO3− and CO3^2−
(c) HBr and NaBr
Solutions:
(a) Strong acid and strong base—not a buffer.
(b) Weak acid and its conjugate base—a buffer.
(c) Strong acid and its counter ion—not a buffer.
Quiz #3: Buffer pH Calculation
Task: Calculate the pH of a buffer with:
Initial concentrations: [NH3] = 0.21 M, [NH4+] = 0.14 M.
Kb of NH3: 1.8 imes 10^{-5}.
Conclusions Regarding Buffer pH Calculations
Weak acids (or bases) in buffers ionize minimally due to the influence of the common ion.
Initial concentrations can serve as good approximations for equilibrium concentrations.
In many cases, there’s no need for an ICE table for buffer pH calculations.
Review of Buffer Concepts
Common-Ion Effect: Suppresses ionization when a weak electrolyte combines with a strong electrolyte with a common ion.
Buffer Composition: Can consist of a weak acid and conjugate base, or weak base and conjugate acid, effectively resisting pH changes.
SECTION 17.2 THE HENDERSON–HASSELBALCH EQUATION
Learning Goals: Apply the Henderson–Hasselbalch equation in pH calculations for buffer solutions.
Henderson–Hasselbalch Equation Derivation
Start with the equilibrium expression for weak acid ionization:
HA(aq) + H_2O(l)
ightleftharpoons H_3O^{+}(aq) + A^{-}(aq)K_a = rac{[H_3O^{+}][A^{-}]}{[HA]}
Rearranging leads to:
[H_3O^{+}] = K_a rac{[HA]}{[A^{-}]}
Taking the negative log, we arrive at:
pH = pK_a + ext{log} rac{[A^{-}]}{[HA]} (Henderson–Hasselbalch Equation)
Henderson–Hasselbalch Application
Concentration terms in the equation can be expressed in molarity or moles.
The equation is valid only when initial concentration equals equilibrium concentration.
Quiz: Henderson–Hasselbalch Application
Task: Calculate pH for a formic acid buffer with:
(a) 0.170 M formic acid and 0.120 M sodium formate.
(b) 0.100 mol formic acid and 0.150 mol sodium formate.
Use Ka of formic acid 1.8 imes 10^{-4}.
Quiz Solutions:
For part (a):
pH = pK_a + ext{log} rac{[A^{-}]}{[HA]}
Evaluation yields:
pH ext{ (a)} = 3.74 - 0.151 = 3.59
For part (b):
pH = 3.74 + 0.176 = 3.92
pH Concentration Ratios and Implications
pH and concentration comparison:
When [A^{-}] > [HA], pH > pK_a.
When [HA] > [A^{-}], pH < pK_a.
When [HA] = [A^{-}], pH = pK_a.
Quiz #4: Acetate Ion and Acetic Acid Concentration
Task: To create a buffer with a pH of 4.00 using acetic acid (Ka = 1.8 imes 10^{-5}), the calculation yields necessary concentrations ratios between acetate and acetic acid.
Buffer Capacity
Definition: Effectiveness of a buffer to resist pH changes upon addition of acid or base, dependent on concentrations of HA and A−.
Most effective range: Buffer is best at pH values within ±1 unit of the pKa of its conjugate acid.
Example: For acetic acid with pKa = 4.75, optimal buffer range = 3.75 ≤ pH ≤ 5.75.
Problem Solving for Buffer pH
Task: Calculate the pH of the following solutions:
(a) 0.150 mol acetic acid and 0.195 mol sodium acetate in 1.0 L.
(b) After adding 0.0300 mol NaOH to part (a).
(c) After adding 0.0300 mol NaOH to 1.0 L of pure water.
SECTION 17.3 TITRATIONS OF STRONG ACIDS AND STRONG BASES
Learning Goals: Compare and analyze titration curves of strong acids and bases, and calculate pertinent properties at various points on curves.
Nature of Titration Process
General Definition: Mixing two solutions in the presence of an indicator to determine reactivity.
Titrant and Analyte Dynamics: A known concentration solution (titrant) is added to an unknown concentration solution (analyte).
Indicator Role: Key for determining stoichiometric equivalence point in titration.
Strong Acid–Strong Base Titration Reaction Mechanism
Overall Reaction:
HX + MOH
ightarrow MX + H_2O
Titration Curve Analysis:
Identification of four distinct regions:
Region A: Initial pH based on HCl concentration.
Region B: Between initial pH and equivalence; not all acid neutralized.
Region C: Equivalence point reached; all acid neutralized.
Region D: Added base results in excess, determining pH.
Quiz: Titrating Strong Acid with Strong Base
Question: Given HCl titrated with KOH, determine pH at key points: before, mid-way, at equivalence, and post equivalence.
Weak Acid and Strong Base Titration Curves
Characteristics:
Initial pH Higher: Due to weak acid partial dissociation.
Rising pH Near Equivalence: Poor resistance to pH changes until closer to pKa.
Equivalence Point Greater than 7: Because weak acids do not release H+ as strongly.
Quiz #2: Weak Acid–Strong Base Characteristics
Question: Identify which weak acids have the highest and lowest pH at equivalence when titrated by NaOH.
Calculating pH in Weak Acid–Strong Base Titrations
Initial pH (Region A): Apply K_a to find pH from weak acid solution using minor ionization together with ice table and expressions.
Between Initial pH and Equivalence (Region B): Determine pH via Henderson–Hasselbalch due to buffer formation.
At the Equivalence Point (Region C):
Focus on conjugate base remaining; calculate pH as basic salt again using K_b relationships (conversion with Kw).
Excess Hydroxide Past Equivalence: Require concentration excess to find new pH.
Quiz Solutions in Weak Acid–Strong Base Context:
Region Solutions: Examples for each phase of titration illustrated methodically for steady reference.
SECTION 17.4 TITRATIONS OF WEAK ACIDS AND WEAK BASES
Comparison with strong acids demonstrates unique behavior in strength, context, and pH implications throughout the titration journey, affecting selection and interpretation of equivalence and curves accordingly.
SECTION 17.5 INDICATORS IN ACID-BASE TITRATIONS
Essential in detecting reaction endpoints.
The behavior of acid–base indicators changes through specific pH ranges, impacting their effectiveness in different scenarios.
SECTION 17.6 THE SOLUBILITY PRODUCT CONSTANT, Ksp
Contrast solubility with Ksp with potential examples for clarity on practical classroom and laboratory models.
Solubility and Molar Solubility Calculations
Discrete comparisons using ksp mechanics to extract outcomes effectively underpinning academic outcomes by importance and pedagogical approach.