Polynomial Reduction and Addition Methods

Reduction of Algebraic Expressions

To write an algebraic expression in its reduced form, terms with identical variable combinations and exponents, known as like terms, must be grouped together and combined through addition or subtraction.

Consider the algebraic expression:

2x+5x−2x2+x2+42x + 5x - 2x^2 + x^2 + 4

The step-by-step reduction procedure involves grouping the like terms according to their variable components and powers.

First, combine the quadratic terms involving x2x^2:

−2x2+x2=−1x2-2x^2 + x^2 = -1x^2

Next, combine the linear terms involving xx:

2x+5x=7x2x + 5x = 7x

The constant term 44 remains unchanged as there are no other constant terms to combine with it.

Combining these reduced components yields the final simplified polynomial expression:

−x2+7x+4-x^2 + 7x + 4

Addition of Polynomials via Grouping

Polynomial addition can be performed by grouping corresponding like terms from each given polynomial.

Consider the sum of the following two polynomials:

(3x2+5x−2)+(2x2−x+4)(3x^2 + 5x - 2) + (2x^2 - x + 4)

To execute the addition procedure, organize and group the terms with matching degrees:

Group and sum the quadratic terms:

3x2+2x2=5x23x^2 + 2x^2 = 5x^2

Group and sum the linear terms:

5x−x=4x5x - x = 4x

Group and sum the constant terms:

−2+4=2-2 + 4 = 2

Combining these individual sums results in the final combined polynomial:

5x2+4x+25x^2 + 4x + 2

Vertical Addition of Polynomials

An alternative method for adding polynomials is vertical alignment, where like terms are arranged in columns above one another and then added sequentially term by term.

Consider the sum of the multi-variable polynomials:

(−3a2b+4ab2−12a+12)+(4a2b−3ab2+12a−15)(-3a^2b + 4ab^2 - 12a + 12) + (4a^2b - 3ab^2 + 12a - 15)

To perform vertical addition, place the first polynomial on top and align the second polynomial underneath such that like terms occupy the same vertical columns.

Aligning the terms gives the first polynomial:

−3a2b+4ab2−12a+12-3a^2b + 4ab^2 - 12a + 12

Added to the second polynomial:

+(4a2b−3ab2+12a−15)+(4a^2b - 3ab^2 + 12a - 15)

Adding each column vertically yields the following individual term additions:

−3a2b+4a2b=a2b-3a^2b + 4a^2b = a^2b

4ab2−3ab2=ab24ab^2 - 3ab^2 = ab^2

−12a+12a=0-12a + 12a = 0

12−15=−312 - 15 = -3

Summing the results across all columns produces the combined expression:

a2b+ab2+0−3a^2b + ab^2 + 0 - 3

Therefore, the final simplified sum of the polynomials is:

a2b+ab2−3a^2b + ab^2 - 3