In-Depth Notes on Series Circuits and Problem Solving Steps

Rules of a Series Circuit

  • Voltage Drops: Voltage drops around the circuit are divided in proportion to the ohmic value of each component.
  • Resistances: Resistances add directly.
    • Example: R<em>total=R</em>1+R2R<em>{total} = R</em>1 + R_2
  • Current: All current flows through all parts of the circuit.
    • Therefore, the amperage on any part of the circuit is the same as the total amperage.

Example Problem

Given:

  • $R_1 = 50$ ohms
  • $R_2 = 100$ ohms
  • Power Supply = 120V
Steps to Solve the Circuit:
  1. Calculate Total Resistance:

    • R<em>total=R</em>1+R2=50extohms+100extohms=150extohmsR<em>{total} = R</em>1 + R_2 = 50 ext{ ohms} + 100 ext{ ohms} = 150 ext{ ohms}
  2. Calculate Total Current:

    • Use Ohm's Law: I=VRI = \frac{V}{R}
    • Itotal=120V150extohms=0.8AI_{total} = \frac{120V}{150 ext{ ohms}} = 0.8 A
  3. Calculate Total Watts:

    • Use the power formula: P=VimesIP = V imes I
    • Ptotal=120Vimes0.8A=96WP_{total} = 120V imes 0.8A = 96W
  4. Calculate Voltage Across Each Resistor:

    • For $R_1$:
      • V<em>1=I</em>totalimesR1=0.8Aimes50extohms=40VV<em>1 = I</em>{total} imes R_1 = 0.8A imes 50 ext{ ohms} = 40V
    • For $R_2$:
      • V<em>2=I</em>totalimesR2=0.8Aimes100extohms=80VV<em>2 = I</em>{total} imes R_2 = 0.8A imes 100 ext{ ohms} = 80V
Summary of Results:
  • Total Resistance: Rtotal=150extohmsR_{total} = 150 ext{ ohms}
  • Total Current: Itotal=0.8AI_{total} = 0.8 A
  • Total Power: Ptotal=96WP_{total} = 96W
  • Voltage across $R1$: V</em>1=40VV</em>1 = 40V
  • Voltage across $R2$: V</em>2=80VV</em>2 = 80V