Mississippi Academic Assessment Program Practice Test - Mathematical Ratios, Expressions, and Statistics

Rate Calculation for Test Completion

Problem 21 examines proportional relationships and rates of work. The specific scenario involves a student named Ryan who has completed part of a test within a specified time frame. According to the data provided, Ryan finished 1818 of his test in a duration of 2525 of an hour. The objective is to determine the total workload completed within a standardized unit of time (11 hour) given that Ryan maintains a constant rate of work.

To solve this, we define the rate of work as the amount of work completed divided by the time taken to complete it. Using the values provided, the rate is expressed as follows:

Rate=1825\text{Rate} = \frac{18}{25}

Assuming the rate stays the same, we apply this value to find the progress made in 11 hour. Multiplying the rate by the target time (11) yields the same value: 1825\frac{18}{25} of the test finished per hour. The options listed for this specific problem include the values 2020, 12561256, 1313, and 3535. Based on the verbatim data, the calculation is defined by the relationship between the workload of 1818 units and the time investment of 2525 units of an hour.

Evaluating Linear Algebraic Expressions with Substitution

Problem 22 focuses on the evaluation of the algebraic expression (x+60)(x + 60). The exercise requires matching specific input values for the variable xx with their corresponding results after the transformation of adding 6060. The targeted output values provided for matching are 10-10, 1010, 5050, and 8080.

The input values for xx presented in the transcript are x=40x = 40, x=80x = -80, x=1000000x = 1000000, and x=400000x = -400000. Additionally, a value of 800-800 is mentioned. To find the value of the expression for any given xx, one must substitute the value of xx into the term (x+60)(x + 60). For example, if we were matching to the headers, a value of x=70x = -70 would yield 10-10, a value of x=50x = -50 would yield 1010, a value of x=10x = -10 would yield 5050, and a value of x=20x = 20 would yield 8080. Although the listed row values in the transcript (40,80,1000000,40000040, -80, 1000000, -400000) are distinct from these typical solutions, the procedural requirement is to select a box to correctly match the value produced by evaluating the expression (x+60)(x + 60).

Comparative Statistical Analysis of Fish Lengths

Problem 23 details a survey conducted by Dave, who recorded the lengths of fish in two different locations: Pond A and Pond B. The data represents the length of fish measured in inches. The results are categorized separately for each pond to allow for comparative analysis of the fish populations.

The recorded data for Pond A includes the following measurements in inches: 66, 1515, 55, 1010, 1111, 1212, 99, and 55. The recorded data for Pond B includes measurements of 11, 2020, 120120, and a sequence of additional values including 1111, 1212, 99, 55, 1717, and 2121.

Based on these results, a student would typically analyze measures of center, such as the mean or median, and measures of variability, such as the range or mean absolute deviation, to compare the two ponds. The transcript mentions conclusions regarding the general length of fish in Pond B compared to Pond A and how the length of fish in Pond A varies. Specifically, the data for Pond B contains an extreme value (120120 inches), which would significantly impact the mean length compared to Pond A, where the values are more tightly clustered between 55 and 1515 inches.