Kinematics in Two Dimensions: Lecture 7 Notes

LECTURE 7: KINEMATICS IN TWO DIMENSIONS

EXAM I Important Announcements

  • Date/Time: Wednesday, October 1, 2025, 2:153:102:15-3:10pm (class period).

  • Location: PHY-001 (the normal classroom, Physics Lecture Hall on Busch Campus). All students will take the exam at this location.

  • Arrival Time: Students should plan to arrive no later than 2:002:00pm. No extra time will be given for late arrivals.

  • Materials to Bring: Pencil/pen, a calculator, and Rutgers Student ID.

  • Material Covered: Chapters 131-3 and related lectures, recitations/workshops/quizzes, and homeworks.

  • Format: 1010 multiple-choice questions.

  • Duration: 5555-minute class period.

  • Rules: Closed book/note. An equation sheet will be provided within the exam.

  • Related Resources: Exam information, Exam 11 Announcement, Exam 11 Important Information Page, Practice Exam 11, and Equation Sheet for Exam 11 are available on Canvas.

  • Lecture 8: Will be an exam review, focusing on problems from the practice exam.

Study Suggestions
  • Read Chapters 131-3 of the textbook and work on additional problems at the end of each chapter.

  • Review lecture slides provided in Canvas weekly.

  • Refer back to relevant homeworks, recitation/workshop materials, and quizzes to review work and address any past difficulties.

  • Work on the provided practice exam using only the provided equation sheet. The practice exam's cover page will mimic the actual exam.

  • Attend instructors' office hours for guidance.

Kinematics in Two Dimensions

  • This lecture covers solving problems related to motion in a plane.

  • Key topics include Projectile Motion and Relative Motion.

  • Relevance: Linear motion introduces basic concepts, but most real-world motion occurs in two or three dimensions (e.g., curved trajectories of balls, cars turning, planetary orbits, electron spirals in magnetic fields). Two-dimensional motion is ubiquitous.

Vector Kinematics in 2 (or 3) Dimensions
  • Displacement: A vector, denoted as Δr=r<em>fr</em>i\Delta \vec{r} = \vec{r}<em>f - \vec{r}</em>i.

  • Velocity and Acceleration: Also vectors, expressible in component form:

    • Velocity: v=v<em>x+v</em>y+vz\vec{v} = \vec{v}<em>x + \vec{v}</em>y + \vec{v}_z

    • Acceleration: a=a<em>x+a</em>y+az\vec{a} = \vec{a}<em>x + \vec{a}</em>y + \vec{a}_z

  • Problem Solving Strategy: Because displacement, velocity, and acceleration are vectors, any 22 (or 33) dimensional problem can be solved by treating it as two (or three) 11-dimensional problems in perpendicular directions (e.g., x and y).

Motion in Two Dimensions
  • A particle moving along a curved path in the xyxy-plane has its position located by a position vector r\vec{r}.

  • A graph of yy versus xx provides an actual picture of the trajectory, not an abstract representation of motion.

Projectile Motion

  • Definition: Two-dimensional free-fall motion under the exclusive influence of gravity.

  • Projectile: An object moving in two dimensions solely under Earth's gravity.

  • Trajectory: Follows a parabolic path, assuming air resistance is negligible.

  • Motion Characteristics:

    • Horizontal Direction: Uniform motion (ax=0a_x = 0).

    • Vertical Direction: Constant acceleration, ay=g\vec{a}_y = -g. Projectiles are in free-fall.

Projectile Motion is Parabolic
  • To demonstrate parabolic trajectory, yy is written as a function of xx. The resulting form is: y=ax+bx2y = ax + bx^2 which is the equation of a parabola.

Understanding Projectile Motion
  • Projectile motion can be understood by analyzing the horizontal and vertical motions independently.

Poll Question & Reasoning
  • Scenario: From the same height and at the same time, one ball is dropped, and another is fired horizontally.

  • Question: Which ball will hit the ground first?

  • Answer: They both hit at the same time.

  • Reasoning: The horizontal motion does not affect the vertical motion. Both balls experience the same constant downward acceleration due to gravity (gg) and start with zero initial vertical velocity (assuming the fired ball is launched purely horizontally). Therefore, their vertical motion, and thus the time to hit the ground, is identical.

    • This concept is often demonstrated with a