ARITHMETIC SEQUENCE AND ALGEBRA
writing algebraic form of Arethemetic sequence [ nth term }
6,10,14
Xn = dn + (f-d)
Xn = 4n + ( 6-4)
Xn = 4n + 2
finding d and f in algebraic form
if , Xn = an + b
common differ d = a
first term f = a+b
SUM(Sn)
Sn = n/2 ( f + Xn )
n = no. of terms
f = first term
Xn = last term
10 , 14 , 18 sum of ten terms
Sn = n/2 (f+Xn )
= 10 /2 ( 10 + 46 )
= 5×56
=280
Algebraic form of the sum
Sn = d/2 n2 + ( f - d/2 ) n
5,9,13 ……algebric form of sum
= 4/2 n2 + (5 - 4/2 ) n
=2 n2 + 3n
Sn = a n2 + b n
d = 2 a
f = a+ b