Chapter 8: Introduction to Linear Momentum and Collisions
8.1 Linear Momentum and Force
Learning Objectives: By the end of this section, students will be able to:
• Define linear momentum.
• Explain the relationship between momentum and force.
• State Newton’s second law of motion in terms of momentum.
• Calculate momentum given mass and velocity.Linear Momentum:
Linear momentum is defined as the product of a system’s mass multiplied by its velocity.
Symbolically expressed as:
p=m×v
where:p = momentum
m = mass
v = velocity
Linear momentum is directly proportional to both mass and velocity; therefore, greater mass or velocity results in greater momentum.
Momentum is a vector quantity with the same direction as the velocity.
The SI unit for momentum is kg·m/s.
Example 8.1: Calculating Momentum: A Football Player and a Football
(a) Calculate momentum of a 110-kg football player running at 8.00 m/s.
Solution:
p = m imes v = 110 ext{ kg} imes 8.00 ext{ m/s} = 880 ext{ kg·m/s}(b) Compare with momentum of a 0.410-kg football thrown at 25.0 m/s.
Solution:
p = 0.410 ext{ kg} imes 25.0 ext{ m/s} = 10.25 ext{ kg·m/s}Discussion:
Despite the ball having greater velocity, the player’s higher mass results in a significantly greater momentum. Consequently, the player’s motion remains largely unaffected by catching the ball.
Momentum and Newton’s Second Law:
Newton recognized the significance of momentum, referring to it as the “quantity of motion.”
Newton’s second law of motion in relation to momentum is defined as:
F_{net}=\frac{\operatorname{changeinmomentum}}{t}
F_{net} = net external force
The change in momentum can be tracked over time to understand dynamics.
Deriving Newton's Second Law:
Change in momentum ({Δ}p) is defined as:
Δp = pfinal-pinitialIf mass is constant:
F_{net}=m\times aThe second law in terms of momentum is versatile for systems where mass changes (like rockets), maintaining its relevance across scenarios.
Making Connections:
The relation between force and momentum aids in understanding dynamics in atomic and subatomic spheres.
8.2 Impulse
Learning Objectives: At the end of this section, students will be able to:
• Define impulse.
• Describe effects of impulses in everyday situations.
• Determine average effective force with graphical representation.
• Calculate average force and impulse using mass, velocity, and time.Impulse:
Impulse is the change in momentum defined as:
Impulse=F_{net}\times tThe effect of a force on an object varies with the duration it acts, highlighting the significance of impulse in modifying momentum.
Example 8.2: Calculating Force: Venus Williams’ Racquet
During the 2007 French Open, Venus Williams hit a tennis ball at 58 m/s.
Mass of the ball: 0.057 kg; contact time: 5.0 ms.
Strategy: Use momentum change to derive average force exerted by the racquet.
Change in momentum can be determined from initial velocity (near zero) and final velocity (58 m/s).
Average Force Calculation:
F_{avg}=\frac{changeinmomentum}{t} .
Given that impulse equals change in momentum, larger forces acting over brief durations have pronounced effects.
Discussion:
The applications of impulse reduce the forces in impacts (e.g., seatbelt force vs. stopping distance).
Making Connections: The effects of impulse materialize in varied contexts of daily life and physics.
8.3 Conservation of Momentum
Learning Objectives: By the end of this section, students will be able to:
• Describe conservation of momentum principle.
• Derive an expression for conservation of momentum.
• Explain conservation of momentum through examples and applications.Principle of Conservation of Momentum:
Momentum is conserved in a closed system when no net external force is acting on it.
Example: Consider a football player colliding with a goalpost.
Forces act that will cause the player to bounce back, but overall momentum is conserved by considering Earth’s recoil (neglectable in practical terms due to its massive scale).
Making Connections:
A practical takeaway is catching a ball while moving your hands with the ball reduces the force of the catch, demonstrating conservation principles.
8.4 Elastic Collisions in One Dimension
Learning Objectives: At the end of this section, students will be able to:
• Understand elastic collisions in one dimension.
• Define internal kinetic energy.
• Derive expressions for energy conservation in elastic collisions.Elastic Collision:
An elastic collision is characterized where both momentum and internal kinetic energy remain conserved.
Internal kinetic energy is defined as the total kinetic energy possessed by all objects within a system.
Example 8.4: Calculating Velocities in Elastic Collisions:
Two objects’ masses are considered to find their final velocities post-collision.
Conservation equations help solve for unknown velocities.
Internal Kinetic Energy: The total kinetic energy before a collision equals the total after in elastic situations, thus deriving essential formulas for predicting outcomes.
Making Connections: Demonstrates applicable concepts to real-world examples like billiard games.
8.5 Inelastic Collisions in One Dimension
Learning Objectives: By the end of this section, students will be able to:
• Define inelastic collision.
• Explain perfect inelastic collisions and their characteristics.Inelastic Collision:
Defined where internal kinetic energy does not remain constant.
Perfect inelastic collisions occur when colliding objects stick together.
Example 8.5: Analyzing a puck and goalie scenario
Conservation of momentum allows for recoil velocity calculations and kinetic energy loss analysis after the collision.
Discussion:
Impacts in sports illustrate momentum and energy conservation principles vividly.
8.6 Collisions of Point Masses in Two Dimensions
Learning Objectives: By the end of this section, you will be able to:
• Analyze two-dimensional collisions and derive momentum conservation expressions in both axes.Two-Dimensional Collision:
Consider object collisions where their resulting speeds and angles are analyzed in terms of momentum conservation principles.
Resolve motion components parallel to axes.
Example 8.7: Calculating Final Velocity from Scattering
Measuring momentum in two dimensions allows for an understanding of unseen velocities post-collision.
8.7 Introduction to Rocket Propulsion
Learning Objectives: Students will be able to:
• Explain principles of rocket propulsion based on Newton’s third law.
• Derive rocket acceleration expressions, discussing affecting factors.Rocket Propulsion:
Rockets operate on ejected mass producing equal opposite reactions prompting acceleration.
Key factors: exhaust velocity, mass ejection rate, rocket mass overall.
Example 8.8: Initial Acceleration of a Moon Launch
Calculates a Saturn V's acceleration using relevant data pertaining to dry mass and thrust-force ratios.
Conclusions from Findings:
The understanding of momentum principles further elucidates rocket mechanics.