Chi-Square Test
Chi-Square Test Explained
Example Scenario: Plant Phenotypes
- A plant with tall and short phenotypes is used to demonstrate the Chi-Square test.
- The expected Mendelian ratio is 3:1 (75% tall, 25% short).
Observed vs. Expected Values
- Observed Values: Actual counts from the garden.
- Example: 58 tall plants, 22 short plants (total 80 plants).
- Expected Values: Calculated based on the expected ratio.
- If 80 plants are observed with a 3:1 ratio:
- Tall: 0.75×80=60
- Short: 0.25×80=20
- The Chi-Square formula is: χ2=∑E(O−E)2, where:
- O = Observed value
- E = Expected value
- ∑ = Summation across all categories
Calculation
- For Tall Plants:
- (O−E)2=(58−60)2=(−2)2=4
- E(O−E)2=604=0.0667
- For Short Plants:
- (O−E)2=(22−20)2=(2)2=4
- E(O−E)2=204=0.2
- Chi-Square Value:
- χ2=0.0667+0.2=0.2667
Degrees of Freedom
- Degrees of freedom (df) = Number of categories - 1
- In this example: df = 2 (tall, short) - 1 = 1
Using the Chi-Square Table
- A chi-squared table is used to determine the p-value.
- A significance level (alpha) of 0.05 is commonly used.
- With df = 1 and alpha = 0.05, the critical value from the table is 3.841.
Interpretation
- Compare the calculated Chi-Square value (0.2667) to the critical value (3.841).
- If the Chi-Square value is less than the critical value, accept the hypothesis.
- If the Chi-Square value is greater than the critical value, reject the hypothesis.
- In this case: 0.2667 < 3.841, so we accept the hypothesis.
Conclusion
- The difference between observed and expected values is small enough to be explained by random chance.
- There is no significant evidence to reject the expected 3:1 Mendelian ratio.