Intorduction of Thermal Resistance

Heat Transfer Fundamentals

Heat Transfer Modes

  • Heat transfer occurs through three primary modes:
    • Conduction: Transfer of heat through materials due to temperature difference without movement.
    • Convection: Transfer of heat through fluid movement; requires close contact between the fluid and solid surface.
    • Radiation: Transfer of heat through electromagnetic waves; does not require a medium.
  • Definitions of Resistance:
    • Each mode of heat transfer has an associated resistance that can be analyzed.

Key Equations and Concepts

  • General Convection Equation:

    • The heat transfer through convection can be expressed as:
      Q=himesAimes(TsTextsurrounding)Q = h imes A imes (T_{s} - T_{ ext{surrounding}})
    • Where:
    • QQ = Heat transfer
    • hh = Heat transfer coefficient
    • AA = Area
    • TsT_{s} = Surface temperature
    • TextsurroundingT_{ ext{surrounding}} = Surrounding temperature
  • Stefan-Boltzmann Law for Radiation:

    • The radiation heat transfer is given as:
      Q=extStefanBoltzmannconstantimesAimes(Ts4Textsurroundings4)Q = ext{Stefan-Boltzmann constant} imes A imes (T_{s}^4 - T_{ ext{surroundings}}^4)
    • Importance of Temperature Difference:
    • This equation highlights that the radiation varies with the fourth power of temperature.

Thermal Resistance Expressions for Conduction, Convection, and Radiation

  • The resistances can be derived for conduction, convection, and radiation, denoted as:

    • For Conduction:
    • Rextcond=LkAR_{ ext{cond}} = \frac{L}{kA}
    • Where LL = Thickness of material, kk = Thermal conductivity
    • For Convection:
    • Rextconv=1hAR_{ ext{conv}} = \frac{1}{hA}
    • For Radiation:
    • The resistance for radiation involves deriving the expression:
    • Rextrad=extcombinedfactorsR_{ ext{rad}} = ext{combined factors}
  • Composite Systems:

    • In composite materials, the total resistance is the sum of individual resistances.
    • For a heat transfer system including convection and conduction,
    • The overall heat transfer can be expressed as:
      Q=TexthotTextcoldRexttotalQ = \frac{T_{ ext{hot}} - T_{ ext{cold}}}{R_{ ext{total}}}
    • Where Rexttotal=Rextconv1+Rextcond1+Rextcond2+Rextcond3+Rextconv2R_{ ext{total}} = R_{ ext{conv1}} + R_{ ext{cond1}} + R_{ ext{cond2}} + R_{ ext{cond3}} + R_{ ext{conv2}}

Practical Applications and Examples

  • Example with Ducts/Walls:

    • Understanding heat transfer in windows with different configurations to minimize heat loss.
    • For instance, evaluating single versus double pane windows (thicknesses and materials).
    • Inner temperature: 25°C and outer temperature: -10°C.
    • Calculate temperature difference: extDeltaT=25(10)=35°Cext{Delta }T = 25 - (-10) = 35°C
  • Resistance Calculations:

    • Calculate resistances for each configuration:
    • Resistance for single-pane glass:
      Rextsingle=LextsinglekAR_{ ext{single}} = \frac{L_{ ext{single}}}{k A}
    • For double-pane glass use:
      Rextdouble=LextdoublekA+4imesextairthicknesskextairAR_{ ext{double}} = \frac{L_{ ext{double}}}{kA}+\frac{4 imes ext{air thickness}}{k_{ ext{air}}A}
  • Thermal Conductivity Considerations:

    • Use of materials like copper for cooking (high conductivity) vs. aluminum for thermal barrier (low conductivity).

Subjective Reflection and Conclusion

  • The importance of considering thermal resistance and designing effective thermal barriers to minimize heat loss.

  • Homework Assignments:

    • Complete given exercises on heat transfer, with follow-up discussions scheduled individually.
  • Assessment Guidance:

    • Completion and understanding of practical applications can aid in future exams and group projects.
    • Encourage participation in discussions and evaluations, reflecting truths and improving knowledge.