AP Physics C Exam Review Notes
College Board Resources
- College board practice (index 1 to 33)
- Links to College Board videos:
- https://www.youtube.com/watch?v=ZzwzMV9Nz8w&list=PLoGgviqq48467T6PU5a6QwxNgUb5SgI9V&index=1
- https://www.youtube.com/watch?v=n3QYjaF8Zn0&list=PLoGgviqq48467T6PU5a6QwxNgUb5SgI9V&index=33
Exam Preparation Books
- The Princeton Review: AP Physics C Prep, 2023 (2 full-length practice tests).
- McGraw Hill: 5 Steps to a 5, AP Physics C, 2023 (3 practice exams).
- Barron's AP Physics C Premium, 2023 (4 full-length practice tests).
Guiding Principle: Motion Graphs
- Relationship between position, velocity, and acceleration graphs.
- Slope:
- Position-time graph: slope gives velocity.
- Velocity-time graph: slope gives acceleration.
- Area:
- Velocity-time graph: area gives displacement.
- Acceleration-time graph: area gives change in velocity.
Constant Acceleration Graphs (1D)
- Typical graphs for constant acceleration (a ≠ 0).
- For free fall, a = g (= 10 m/s^2).
Constant Acceleration Motion Graphs (a = 0)
- Examples:
- Toy cars (a > 0).
- Free fall (a > 0).
- Car on slope (a > 0).
Instantaneous Velocity (Calculus)
- Instantaneous velocity is the rate of change of position in time.
- v = \frac{dx}{dt} (x and v are vectors).
- Instantaneous velocity is the slope (tangent) of the position-time graph at that time.
Guiding Principle: Projectile Motion
- Horizontal and vertical motions are independent.
- Horizontal motion: constant velocity.
- Vertical motion: constant acceleration g.
Projectile Motion Equations
- Horizontal equations can be derived from vertical equations by setting acceleration g = 0.
- Vertical equations:
- v{yf} = v{yi} + g\Delta t
- \Delta y = \frac{1}{2}(v{yi} + v{yf})\Delta t
- \Delta y = v_{yi}\Delta t + \frac{1}{2} g(\Delta t)^2
- v{yf}^2 = v{yi}^2 + 2g\Delta y
- Horizontal equations:
- v{xf} = v{xi}
- \Delta x = v_{xi}\Delta t
Projectile Motion: Resolve Components
- Resolve velocity into x and y components:
- v_x = v \cos{\Theta}
- v_y = v \sin{\Theta}
Guiding Principle: Problem Solving (Forces and Motion)
- Use the given motion to justify the force(s).
- Steps:
- Identify objects.
- Draw Free Body Diagram (FBD) of the object.
- Identify contact forces + weight.
- Solve the algebra.
Nature of Friction
- Static friction: keeps increasing until the object moves.
- Kinetic friction: stays the same when the object is moving.
- Kinetic friction is lower than the maximum static friction.
Guiding Principle: Circular Motion
- When an object is in circular motion, there must be a centripetal force.
- Uniform circular motion means angular acceleration α = 0.
- Kinematics equations become:
- \omegaf = \omegai
- \Delta \theta = \omega_i(\Delta t)
- These equations are similar to projectile motion equations in the x (horizontal) direction.
Guiding Principle: Work and Energy
- Work changes total mechanical energy E.
- W = \Delta E
- Valid for systems with conservative forces.
- E{total} = K{trans} + K{rot} + Ug + U_s = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 + mgy + \frac{1}{2}kx^2
System Perspectives: Energy
- Object-gravity system:
- External force: gravity.
- Work done by gravity: W = mg\Delta y.
- GPE: none.
- System energy: E = K.
- Work-energy theorem: W = \Delta E
- Object + Earth system (object not in orbit):
- External force: none.
- Work done by gravity: none.
- GPE: mg\Delta y.
- System energy: E = K + U_g.
- Work-energy theorem: W = \Delta E = 0
- Note: Potential energy (PE) requires an interaction between more than one object. A system of one object has no internal structure and cannot have PE.
Graph Representation: Energy
- Plot F_{\parallel} vs. displacement.
- Work done by force = area under the graph.
Work Done by Perpendicular Force?
- Example: uniform circular motion without gravity.
- Instantaneous displacement \Delta x is in the same direction as tangential speed v.
- Centripetal force is perpendicular to \Delta x at any time.
- Tangential speed v is constant.
- Therefore \Delta K = 0.
- From work-energy principle, W = \Delta K = 0.
- Work done by a perpendicular force is zero.
- Perpendicular force only changes the direction of motion.
Work and Force in 2D (and 3D)
- W = (F)(d) when the force is parallel to the displacement d.
- W = 0 when the force is perpendicular to the displacement d.
- Resolve a force into parallel and perpendicular components.
- Only the parallel component (F \cos{\theta}) does work.
- Therefore:
- W = Fd \cos{\theta} (F, d are + magnitudes).
- W = F{\parallel}d (F{\parallel} can be + or -).
- where F_{\parallel} = F \cos{\theta}.
- W = F \cdot d (vector dot product).
Comparison of Two Guiding Principles
- Impulse and Momentum:
- J = \Delta p
- \Delta p = 0 or p = constant.
- Work and Energy:
- W = \Delta E
- \Delta E = 0 or E = constant.
Energy Conservation
- Special case when no work is done.
- \Delta E = \Delta K + \Delta U_g = 0
- Therefore E = K + U_g = constant
- Total mechanical energy E is conserved.
- Total mechanical energy E is constant.
Momentum
- Force is change of momentum in time.
- F = \frac{\Delta p}{\Delta t} = \frac{dp}{dt}
Impulse and Force Graph
- J = \Delta p
- F = \frac{dp}{dt} (slope formula).
- J = \int F dt (area formula).
Problem Solving Strategy (Energy)
- Motion variables:
- Which motion variables are used in energy calculations? x, v
- Which motion variables are not used in energy calculations? t, a
- In general, see if you can solve the problem using energy. It is usually easier. If not, try Newton’s laws.
- Acceleration (a):
- a = \frac{\Delta v}{\Delta t}
- x axis = time (t), y axis = velocity (v)
- Velocity (v):
- v = \frac{\Delta x}{\Delta t}
- x axis = time (t), y axis = position (x)
- Force (F):
- F = \frac{\Delta p}{\Delta t}
- x axis = time (t), y axis = momentum (p)
- Torque (\tau):
- \tau = \frac{\Delta L}{\Delta t}
- x axis = time (t), y axis = angular momentum (L)
- Impulse (J):
- J = F\Delta t
- x axis = time (t), y axis = force (F)
- Work (W):
- W = F\Delta x
- x axis = displacement (x), y axis = force (F)
- \Delta p = F\Delta t
- x axis = time (t), y axis = force (F)
- \Delta L = \tau \Delta t
- x axis = time (t), y axis = torque (\tau)
System Perspective (Momentum)
- A closed (isolated) system is one in which there is no net external force.
- An open system is one in which there is a net external force.
System Perspective (Energy)
- A closed (isolated) system is one in which there is no work done.
- An open system is one in which there is work done on/by the system.
- Path independence in closed systems.
Guiding Principle: Rotational Motion
- Use what you learned in linear motion.
- Skills and contents are similar.
Guessmology Table
- Linear motion vs. Rotational motion:
- Displacement: x -> \theta
- Velocity: v -> \omega
- Acceleration: a -> \alpha
- Inertia: m -> I
- Newton’s 2nd law: F = ma -> \tau = I\alpha
- Work: W = F_{\parallel}d -> W = \tau \theta
- Kinetic energy: K = \frac{1}{2} mv^2 -> K = \frac{1}{2} I \omega^2
- Momentum: p = mv -> L = I\omega
Guessmology Table (cont.)
- Linear motion vs. Rotational motion:
- Guiding principle unit 4: W = \Delta E (same for both)
- Guiding principle unit 5: J = \Delta p, \Delta p = F \Delta t -> \Delta L = \tau \Delta t
Kinematics Equations Comparison
- Problem solving strategy:
- Variables given?
- Variables asked?
- Choose equation (note: last equation not in equation sheet)
- What’s missing?
- no displacement:
- Rotation: \omegaf = \omegai + \alpha \Delta t
- Linear: vf = vi + a\Delta t
- no final velocity:
- Rotation: \Delta \theta = \omega_i(\Delta t) + (\frac{1}{2})\alpha(\Delta t)^2
- Linear: \Delta x = v_i(\Delta t) + (\frac{1}{2})a(\Delta t)^2
- no time:
- Rotation: \omegaf^2 = \omegai^2 + 2\alpha(\Delta \theta)
- Linear: vf^2 = vi^2 + 2a(\Delta x)
- no acceleration:
- Rotation: \Delta \theta = \frac{1}{2}(\omegaf + \omegai)(\Delta t)
- Linear: \Delta x = (\frac{1}{2})(vf + vi)(\Delta t)
Keywords
- Linear Motion vs. Rotational Motion:
- Linear displacement -> Angular displacement
- Linear velocity -> Angular velocity
- Linear acceleration -> Angular acceleration
- Mass -> Rotational inertia
- Work -> Work
- Translational kinetic energy -> Rotational kinetic energy
- Linear momentum -> Angular momentum
Rigid Object Equilibrium
- For point object in equilibrium: \vec{F}_{net} = 0
- For rigid object in equilibrium: \tau{net} = 0 and \vec{F}{net} = 0
- There is no rotation. You can choose the pivot point anywhere.
Rolling and Slipping (Sliding)
- Rolling means there is no slipping:
- s = r\theta
- v_T = r\omega
- a_T = r\alpha
- Static friction
- If there is slipping (sliding):
- s \neq r\theta
- v_T \neq r\omega
- a_T \neq r\alpha
- Kinetic friction
Guiding Principle: SHM
- A linear restoring force that is proportional to displacement.
- Restoring force F = -kx
Summary: SHM
- x = A \cos(\omega t) position
- v_x = -A\omega \sin(\omega t) velocity
- a_x = -A\omega^2 \cos(\omega t) acceleration
- a_x = -\omega^2 x
- \omega angular frequency
- A amplitude
- f = \frac{\omega}{2\pi} frequency
- T = \frac{1}{f} period
SHM (Calculus)
- v = \frac{dx}{dt}
- a = \frac{dv}{dt} = \frac{d^2x}{dt^2}
- F = ma = m \frac{d^2x}{dt^2}
- Linear restoring force F = -kx
- Substitute: m \frac{d^2x}{dt^2} + kx = 0
- Substitute \frac{k}{m} = \omega^2 (k and m are positive)
- \frac{d^2x}{dt^2} + \omega^2 x = 0 (2nd order differential equation in x)
- Solution:
- x = A \cos(\omega t + \varphi) or x = a \cos(\omega t) + b \sin(\omega t)
- (A, \varphi) or (a, b) are constants of integration
Orbit Physics
- True for orbits around an infinite mass e.g.
- Planet around Sun
- Satellites around earth
- For planets and satellites in circular orbit
- centripetal force = gravitational force
- For planets and satellites in elliptical orbit
- Angular momentum is conserved
- Energy is conserved