AP Physics C Exam Review Notes

College Board Resources

  • College board practice (index 1 to 33)
  • Links to College Board videos:
    • https://www.youtube.com/watch?v=ZzwzMV9Nz8w&list=PLoGgviqq48467T6PU5a6QwxNgUb5SgI9V&index=1
    • https://www.youtube.com/watch?v=n3QYjaF8Zn0&list=PLoGgviqq48467T6PU5a6QwxNgUb5SgI9V&index=33

Exam Preparation Books

  • The Princeton Review: AP Physics C Prep, 2023 (2 full-length practice tests).
  • McGraw Hill: 5 Steps to a 5, AP Physics C, 2023 (3 practice exams).
  • Barron's AP Physics C Premium, 2023 (4 full-length practice tests).

Guiding Principle: Motion Graphs

  • Relationship between position, velocity, and acceleration graphs.
  • Slope:
    • Position-time graph: slope gives velocity.
    • Velocity-time graph: slope gives acceleration.
  • Area:
    • Velocity-time graph: area gives displacement.
    • Acceleration-time graph: area gives change in velocity.

Constant Acceleration Graphs (1D)

  • Typical graphs for constant acceleration (a0a ≠ 0).
  • For free fall, a=ga = g (=10m/s2= 10 m/s^2).

Constant Acceleration Motion Graphs (a=0a = 0)

  • Examples:
    • Toy cars (a > 0).
    • Free fall (a > 0).
    • Car on slope (a > 0).

Instantaneous Velocity (Calculus)

  • Instantaneous velocity is the rate of change of position in time.
  • v=dxdtv = \frac{dx}{dt} (x and v are vectors).
  • Instantaneous velocity is the slope (tangent) of the position-time graph at that time.

Guiding Principle: Projectile Motion

  • Horizontal and vertical motions are independent.
  • Horizontal motion: constant velocity.
  • Vertical motion: constant acceleration g.

Projectile Motion Equations

  • Horizontal equations can be derived from vertical equations by setting acceleration g=0g = 0.
  • Vertical equations:
    • v<em>yf=v</em>yi+gΔtv<em>{yf} = v</em>{yi} + g\Delta t
    • Δy=12(v<em>yi+v</em>yf)Δt\Delta y = \frac{1}{2}(v<em>{yi} + v</em>{yf})\Delta t
    • Δy=vyiΔt+12g(Δt)2\Delta y = v_{yi}\Delta t + \frac{1}{2} g(\Delta t)^2
    • v<em>yf2=v</em>yi2+2gΔyv<em>{yf}^2 = v</em>{yi}^2 + 2g\Delta y
  • Horizontal equations:
    • v<em>xf=v</em>xiv<em>{xf} = v</em>{xi}
    • Δx=vxiΔt\Delta x = v_{xi}\Delta t

Projectile Motion: Resolve Components

  • Resolve velocity into x and y components:
    • vx=vcosΘv_x = v \cos{\Theta}
    • vy=vsinΘv_y = v \sin{\Theta}

Guiding Principle: Problem Solving (Forces and Motion)

  • Use the given motion to justify the force(s).
  • Steps:
    • Identify objects.
    • Draw Free Body Diagram (FBD) of the object.
    • Identify contact forces + weight.
    • Solve the algebra.

Nature of Friction

  • Static friction: keeps increasing until the object moves.
  • Kinetic friction: stays the same when the object is moving.
  • Kinetic friction is lower than the maximum static friction.

Guiding Principle: Circular Motion

  • When an object is in circular motion, there must be a centripetal force.

Uniform Circular Motion

  • Uniform circular motion means angular acceleration α=0α = 0.
  • Kinematics equations become:
    • ω<em>f=ω</em>i\omega<em>f = \omega</em>i
    • Δθ=ωi(Δt)\Delta \theta = \omega_i(\Delta t)
  • These equations are similar to projectile motion equations in the x (horizontal) direction.

Guiding Principle: Work and Energy

  • Work changes total mechanical energy E.
  • W=ΔEW = \Delta E
    • Valid for systems with conservative forces.
  • E<em>total=K</em>trans+K<em>rot+U</em>g+Us=12mv2+12Iω2+mgy+12kx2E<em>{total} = K</em>{trans} + K<em>{rot} + U</em>g + U_s = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 + mgy + \frac{1}{2}kx^2

System Perspectives: Energy

  • Object-gravity system:
    • External force: gravity.
    • Work done by gravity: W=mgΔyW = mg\Delta y.
    • GPE: none.
    • System energy: E=KE = K.
    • Work-energy theorem: W=ΔEW = \Delta E
  • Object + Earth system (object not in orbit):
    • External force: none.
    • Work done by gravity: none.
    • GPE: mgΔymg\Delta y.
    • System energy: E=K+UgE = K + U_g.
    • Work-energy theorem: W=ΔE=0W = \Delta E = 0
  • Note: Potential energy (PE) requires an interaction between more than one object. A system of one object has no internal structure and cannot have PE.

Graph Representation: Energy

  • Plot FF_{\parallel} vs. displacement.
  • Work done by force = area under the graph.

Work Done by Perpendicular Force?

  • Example: uniform circular motion without gravity.
  • Instantaneous displacement Δx\Delta x is in the same direction as tangential speed v.
  • Centripetal force is perpendicular to Δx\Delta x at any time.
  • Tangential speed v is constant.
  • Therefore ΔK=0\Delta K = 0.
  • From work-energy principle, W=ΔK=0W = \Delta K = 0.
  • Work done by a perpendicular force is zero.
  • Perpendicular force only changes the direction of motion.

Work and Force in 2D (and 3D)

  • W=(F)(d)W = (F)(d) when the force is parallel to the displacement d.
  • W=0W = 0 when the force is perpendicular to the displacement d.
  • Resolve a force into parallel and perpendicular components.
  • Only the parallel component (FcosθF \cos{\theta}) does work.
  • Therefore:
    • W=FdcosθW = Fd \cos{\theta} (F, d are + magnitudes).
    • W=F<em>dW = F<em>{\parallel}d (F</em>F</em>{\parallel} can be + or -).
      • where F=FcosθF_{\parallel} = F \cos{\theta}.
    • W=FdW = F \cdot d (vector dot product).

Comparison of Two Guiding Principles

  • Impulse and Momentum:
    • J=ΔpJ = \Delta p
    • Δp=0\Delta p = 0 or p = constant.
  • Work and Energy:
    • W=ΔEW = \Delta E
    • ΔE=0\Delta E = 0 or E = constant.

Energy Conservation

  • Special case when no work is done.
  • ΔE=ΔK+ΔUg=0\Delta E = \Delta K + \Delta U_g = 0
  • Therefore E=K+Ug=constantE = K + U_g = constant
  • Total mechanical energy E is conserved.
  • Total mechanical energy E is constant.

Momentum

  • Force is change of momentum in time.
  • F=ΔpΔt=dpdtF = \frac{\Delta p}{\Delta t} = \frac{dp}{dt}

Impulse and Force Graph

  • J=ΔpJ = \Delta p
  • F=dpdtF = \frac{dp}{dt} (slope formula).
  • J=FdtJ = \int F dt (area formula).

Problem Solving Strategy (Energy)

  • Motion variables:
    • t, x, v, a
  • Which motion variables are used in energy calculations? x, v
  • Which motion variables are not used in energy calculations? t, a
  • In general, see if you can solve the problem using energy. It is usually easier. If not, try Newton’s laws.

Comparison of Graphs: Slope Formula

  • Acceleration (a):
    • a=ΔvΔta = \frac{\Delta v}{\Delta t}
    • x axis = time (t), y axis = velocity (v)
  • Velocity (v):
    • v=ΔxΔtv = \frac{\Delta x}{\Delta t}
    • x axis = time (t), y axis = position (x)
  • Force (F):
    • F=ΔpΔtF = \frac{\Delta p}{\Delta t}
    • x axis = time (t), y axis = momentum (p)
  • Torque (\tau):
    • τ=ΔLΔt\tau = \frac{\Delta L}{\Delta t}
    • x axis = time (t), y axis = angular momentum (L)

Comparison of Graphs: Area Formula

  • Impulse (J):
    • J=FΔtJ = F\Delta t
    • x axis = time (t), y axis = force (F)
  • Work (W):
    • W=FΔxW = F\Delta x
    • x axis = displacement (x), y axis = force (F)
  • Δp=FΔt\Delta p = F\Delta t
    • x axis = time (t), y axis = force (F)
  • ΔL=τΔt\Delta L = \tau \Delta t
    • x axis = time (t), y axis = torque (\tau)

System Perspective (Momentum)

  • A closed (isolated) system is one in which there is no net external force.
  • An open system is one in which there is a net external force.

System Perspective (Energy)

  • A closed (isolated) system is one in which there is no work done.
  • An open system is one in which there is work done on/by the system.
  • Path independence in closed systems.

Guiding Principle: Rotational Motion

  • Use what you learned in linear motion.
  • Skills and contents are similar.

Guessmology Table

  • Linear motion vs. Rotational motion:
    • Displacement: x -> θ\theta
    • Velocity: v -> ω\omega
    • Acceleration: a -> α\alpha
    • Inertia: m -> I
    • Newton’s 2nd law: F=maF = ma -> τ=Iα\tau = I\alpha
    • Work: W=FdW = F_{\parallel}d -> W=τθW = \tau \theta
    • Kinetic energy: K=12mv2K = \frac{1}{2} mv^2 -> K=12Iω2K = \frac{1}{2} I \omega^2
    • Momentum: p=mvp = mv -> L=IωL = I\omega

Guessmology Table (cont.)

  • Linear motion vs. Rotational motion:
    • Guiding principle unit 4: W=ΔEW = \Delta E (same for both)
    • Guiding principle unit 5: J=ΔpJ = \Delta p, Δp=FΔt\Delta p = F \Delta t -> ΔL=τΔt\Delta L = \tau \Delta t

Kinematics Equations Comparison

  • Problem solving strategy:
    • Variables given?
    • Variables asked?
    • Choose equation (note: last equation not in equation sheet)
  • What’s missing?
    • no displacement:
      • Rotation: ω<em>f=ω</em>i+αΔt\omega<em>f = \omega</em>i + \alpha \Delta t
      • Linear: v<em>f=v</em>i+aΔtv<em>f = v</em>i + a\Delta t
    • no final velocity:
      • Rotation: Δθ=ωi(Δt)+(12)α(Δt)2\Delta \theta = \omega_i(\Delta t) + (\frac{1}{2})\alpha(\Delta t)^2
      • Linear: Δx=vi(Δt)+(12)a(Δt)2\Delta x = v_i(\Delta t) + (\frac{1}{2})a(\Delta t)^2
    • no time:
      • Rotation: ω<em>f2=ω</em>i2+2α(Δθ)\omega<em>f^2 = \omega</em>i^2 + 2\alpha(\Delta \theta)
      • Linear: v<em>f2=v</em>i2+2a(Δx)v<em>f^2 = v</em>i^2 + 2a(\Delta x)
    • no acceleration:
      • Rotation: Δθ=12(ω<em>f+ω</em>i)(Δt)\Delta \theta = \frac{1}{2}(\omega<em>f + \omega</em>i)(\Delta t)
      • Linear: Δx=(12)(v<em>f+v</em>i)(Δt)\Delta x = (\frac{1}{2})(v<em>f + v</em>i)(\Delta t)

Keywords

  • Linear Motion vs. Rotational Motion:
    • Linear displacement -> Angular displacement
    • Linear velocity -> Angular velocity
    • Linear acceleration -> Angular acceleration
    • Mass -> Rotational inertia
    • Work -> Work
    • Translational kinetic energy -> Rotational kinetic energy
    • Linear momentum -> Angular momentum

Rigid Object Equilibrium

  • For point object in equilibrium: Fnet=0\vec{F}_{net} = 0
  • For rigid object in equilibrium: τ<em>net=0\tau<em>{net} = 0 and F</em>net=0\vec{F}</em>{net} = 0
  • There is no rotation. You can choose the pivot point anywhere.

Rolling and Slipping (Sliding)

  • Rolling means there is no slipping:
    • s=rθs = r\theta
    • vT=rωv_T = r\omega
    • aT=rαa_T = r\alpha
    • Static friction
  • If there is slipping (sliding):
    • srθs \neq r\theta
    • vTrωv_T \neq r\omega
    • aTrαa_T \neq r\alpha
    • Kinetic friction

Guiding Principle: SHM

  • A linear restoring force that is proportional to displacement.
  • Restoring force F=kxF = -kx

Summary: SHM

  • x=Acos(ωt)x = A \cos(\omega t) position
  • vx=Aωsin(ωt)v_x = -A\omega \sin(\omega t) velocity
  • ax=Aω2cos(ωt)a_x = -A\omega^2 \cos(\omega t) acceleration
  • ax=ω2xa_x = -\omega^2 x
  • ω\omega angular frequency
  • A amplitude
  • f=ω2πf = \frac{\omega}{2\pi} frequency
  • T=1fT = \frac{1}{f} period

SHM (Calculus)

  • v=dxdtv = \frac{dx}{dt}
  • a=dvdt=d2xdt2a = \frac{dv}{dt} = \frac{d^2x}{dt^2}
  • F=ma=md2xdt2F = ma = m \frac{d^2x}{dt^2}
  • Linear restoring force F=kxF = -kx
  • Substitute: md2xdt2+kx=0m \frac{d^2x}{dt^2} + kx = 0
  • Substitute km=ω2\frac{k}{m} = \omega^2 (k and m are positive)
  • d2xdt2+ω2x=0\frac{d^2x}{dt^2} + \omega^2 x = 0 (2nd order differential equation in x)
  • Solution:
    • x=Acos(ωt+φ)x = A \cos(\omega t + \varphi) or x=acos(ωt)+bsin(ωt)x = a \cos(\omega t) + b \sin(\omega t)
    • (A, φ\varphi) or (a, b) are constants of integration

Orbit Physics

  • True for orbits around an infinite mass e.g.
    • Planet around Sun
    • Satellites around earth
  • For planets and satellites in circular orbit
    • centripetal force = gravitational force
  • For planets and satellites in elliptical orbit
    • Angular momentum is conserved
    • Energy is conserved