Definition: Internal resistance occurs in real-life circuits as batteries are not ideal; they have their own resistance.
Analogy: Think of it as some voltage being 'eaten away' by the battery’s internal resistance.
Visual Representation: A zoomed-in view of a battery can be depicted with an electromotive force (EMF, ε) and internal resistance (r).
EMF Definition: Measured in volts, it represents the potential difference a battery tries to deliver (not a force in Newtons).
Analogy: Imagine a battery trying to give out 10 pieces of chocolate, with internal resistance consuming some (resulting in a lower output).
The relationship involving EMF, current (I), and resistances in a circuit:[ ε = I(R + r) ]
This breaks down to:
EMF (ε): Battery's output
I: Current in amperes
R: External resistance
r: Internal resistance
Example Setup: A circuit with 10 identical 5-ohm resistors in parallel.
Calculating Equivalent Resistance:
Formula: [ 1/R_P = (1/R + 1/R + ... + 1/R) ] for 10 resistors.
Result:
[ 1/R_P = 10 * (1/5) = 2 ]
Therefore, [ R_P = 0.5 \text{ ohms} ]
Given:
Internal resistance (r) = 0.1 ohms
EMF (ε) = 6 volts
Finding Circuit Current (I):
Formula rearrangement:[ I = \frac{ε}{R + r} ]
Calculation:[ I = 6}/{0.5 + 0.1} = {6}/{0.6} = 10 { A} ]
To find the potential difference (V) across the battery’s terminals:
Formula: [ V = IR ]
Using current (I = 10 A) and external resistance (R = 0.5 ohms):[ V = 10 * 0.5 = 5 V]
The internal resistance and EMF relationship are crucial for understanding real circuit behavior, leading to adjustments in expected voltage outputs.