Physics for Engineers - Fundamental Concepts and Measurements

Foundations of Physics and Engineering

  • Physics is defined as one of the most fundamental sciences and serves as the foundation for all engineering and technology.

  • The nature of physics is that of an experimental science, following a specific progression:

    • 1. Observe

    • 2. Patterns

    • 3. Theories

    • 4. Laws

Systematic Problem-Solving in Physics

  • To solve physics problems effectively, a four-step process is utilized:

    • 1. Identify the relevant concepts.

    • 2. Set up the problem.

    • 3. Execute the solution.

    • 4. Evaluate your answer.

Units and Measurements

  • Measurements of physical quantities are expressed in terms of units, which function as standardized values.

  • A physical quantity is any number which describes a physical phenomenon quantitatively.

  • Quantities are categorized into two types:

    • 1. Basic/Fundamental quantities: These do not depend on other quantities and are used to fully describe other quantities. Examples include length and mass.

    • 2. Derived quantities: These are expressed as an algebraic combination of basic or fundamental quantities. Examples include area and volume.

Major Systems of Units

  • There are two primary systems used in measurement:

    • 1. SI units: Short for the French Système International d’Unités, commonly referred to as the metric system.

    • 2. English units: Also known as the customary or imperial system. This system is sometimes referred to as the foot–pound–second (fpsfps) system.

SI Base Units (International System of Quantities)

  • The SI system is built upon seven fundamental base units:

    • Length: meter (mm)

    • Mass: kilogram (kgkg)

    • Time: second (ss)

    • Electrical Current: Ampere (AA)

    • Thermodynamic Temperature: Kelvin (KK)

    • Amount of Substance: mole (molmol)

    • Luminous Intensity: Candela (cdcd)

SI Derived Units

  • Specific derived quantities and their corresponding SI units include:

    • Force, weight: Newton (NN), equivalent to kg×m×s2kg \times m \times s^{-2}

    • Work, Energy, Heat: Joule (JJ), equivalent to N×mN \times m

    • Pressure: Pascal (PaPa), equivalent to N/m2N/m^{2}

    • Power, Radiant Flux: Watt (WW), equivalent to J/sJ/s

    • Electric Charge: Coulomb (CC), equivalent to A×sA \times s

    • Voltage: Volt (VV), equivalent to W/AW/A

    • Magnetic Flux: Weber (WbWb), equivalent to V×sV \times s

    • Inductance: Henry (HH), equivalent to Wb/AWb/A

    • Capacitance: Farad (FF), equivalent to C/VC/V

    • Resistance: Ohm (Ω\Omega), equivalent to V/AV/A

Metric Prefixes

  • Metric prefixes are used to denote powers of 10:

    • yotta- (YY): 102410^{24}

    • zetta- (ZZ): 102110^{21}

    • exa- (EE): 101810^{18}

    • peta- (PP): 101510^{15}

    • tera- (TT): 101210^{12}

    • giga- (GG): 10910^{9}

    • mega- (MM): 10610^{6}

    • kilo- (kk): 10310^{3}

    • hecto- (hh): 10210^{2}

    • deka- (dada): 10110^{1}

    • deci- (dd): 10110^{-1}

    • centi- (cc): 10210^{-2}

    • milli- (mm): 10310^{-3}

    • micro- (μ\mu): 10610^{-6}

    • nano- (nn): 10910^{-9}

    • pico- (pp): 101210^{-12}

    • femto- (ff): 101510^{-15}

    • atto- (aa): 101810^{-18}

    • zepto- (zz): 102110^{-21}

    • yocto- (yy): 102410^{-24}

English Unit Equivalents

  • The following mappings relate metric units to English (Imperial) units:

    • Length: meter (mm) vs Foot (ftft)

    • Mass: kilogram (kgkg) vs Slugs

    • Temperature: C^{\circ}C vs Degree Fahrenheit (F^{\circ}F)

    • Force: Newton (NN) vs Pound Force (lblb)

    • Volume: Liter (LL) or m3m^{3} vs Gallon (galgal)

    • Area: Hectare (haha) vs Acre

    • Pressure: Pascal (PaPa) vs lb/in2lb/in^{2} (psipsi)

  • Specific conversion factors:

    • 1m=3.28ft1\,m = 3.28\,ft

    • 2.54cm=1in2.54\,cm = 1\,in

    • 1km=1.609mile1\,km = 1.609\,mile

    • 1kg=0.0685Slugs1\,kg = 0.0685\,Slugs

    • 1kg=2.2046lb1\,kg = 2.2046\,lb

    • 3.785L=1gal3.785\,L = 1\,gal

    • 1ha=2.47acres1\,ha = 2.47\,acres

    • 1kPa=0.145psi1\,kPa = 0.145\,psi

  • Traditional English conversions:

    • 1ft=12in1\,ft = 12\,in

    • 1yd=3ft1\,yd = 3\,ft

    • 1mile=5280ft1\,mile = 5280\,ft

    • 1gal=4quarts1\,gal = 4\,quarts

    • 1quart=2pints1\,quart = 2\,pints

    • 1pint=16oz1\,pint = 16\,oz

Uncertainty and Accuracy

  • Uncertainty is defined as the maximum difference between the measured value and the true value.

  • Accuracy describes how close a measurement is to the true value.

  • Examples of accuracy and uncertainty notation:

    • 40.86±0.09cm40.86 \pm 0.09\,cm

    • 1.879(25)kg1.879(25)\,kg

    • 63ohms±10%63\,ohms \pm 10\%

Precision vs Accuracy

  • Accuracy: Describes how close your measurements are to the true value.

  • Precision: Measures how close your measured values are to each other.

Significant Figures and Rounding

  • Significant figures refer to the number of meaningful digits in a value.

  • Rules for Significant Figures:

    • 1. Non-zero digits are always significant.

    • 2. Any zeros between two significant figures are significant.

    • 3. A final zero or trailing zeros are significant only in the decimal portion.

  • Significant Figure Count Examples:

    • 5.64cm5.64\,cm: 3 significant figures

    • 6008m6008\,m: 4 significant figures

    • 0.99g0.99\,g: 2 significant figures

    • 0.430in0.430\,in: 3 significant figures

    • 5000yd5000\,yd: 1 significant figure

    • 5000.0m5000.0\,m: 5 significant figures

    • 0.00350mm0.00350\,mm: 3 significant figures

    • 0.002lb0.002\,lb: 1 significant figure

  • Operations with Significant Figures:

    • Multiplication and Division: The result can have no more significant figures than the factor with the fewest significant figures. Example: 0.453×3.36.592=0.230.453 \times \frac{3.3}{6.592} = 0.23

    • Addition and Subtraction: The number of significant figures is determined by the term with the largest uncertainty (i.e., the fewest digits to the right of the decimal point). Example: 34.678+45.871.32=9.234.678 + 45.8 - 71.32 = 9.2

  • Rounding Off Numbers:

    • 1. If the digit to be dropped is less than 5, the number is written without the digit (e.g., 78.37478.374 becomes 78.3778.37).

    • 2. If the digit to be dropped is exactly 5, the nearest even number is used for the preceding digit (e.g., 78.37578.375 becomes 78.3878.38; 78.38578.385 becomes 78.3878.38).

    • 3. If the digit to be dropped is greater than 5, the preceding digit is increased by 1 (e.g., 78.38678.386 becomes 78.3978.39).

Scientific Notation

  • Scientific notation is used to express very large or very small numbers concisely.

  • Examples:

    • 355,000,000=3.55×108=355×106355,000,000 = 3.55 \times 10^{8} = 355 \times 10^{6}

    • 200=2×102200 = 2 \times 10^{2}

    • 4×106=0.0000044 \times 10^{-6} = 0.000004

Unit Conversion Factors and Processes

  • Unit conversion is the process of changing a measurement from one unit to another while maintaining the same quantity. This is performed by multiplying or dividing by a conversion factor.

  • Detailed Conversion Table:

    • Length:

      • 1m=100cm=1000mm=106μm=109nm1\,m = 100\,cm = 1000\,mm = 10^{6}\,\mu m = 10^{9}\,nm

      • 1km=1000m=0.6214mi1\,km = 1000\,m = 0.6214\,mi

      • 1m=3.281ft=39.37in1\,m = 3.281\,ft = 39.37\,in

      • 1cm=0.3937in1\,cm = 0.3937\,in

      • 1in=2.540cm1\,in = 2.540\,cm

      • 1ft=30.48cm1\,ft = 30.48\,cm

      • 1yd=91.44cm1\,yd = 91.44\,cm

      • 1mi=5280ft=1.609km1\,mi = 5280\,ft = 1.609\,km

      • 1A˚=1010m=108cm=101nm1\,\text{\AA} = 10^{-10}\,m = 10^{-8}\,cm = 10^{-1}\,nm

      • 1nauticalmile=6080ft1\,nautical\,mile = 6080\,ft

      • 1lightyear=9.461×1015m1\,light-year = 9.461 \times 10^{15}\,m

    • Volume:

      • 1liter=1000cm3=103m3=0.03531ft3=61.02in31\,liter = 1000\,cm^{3} = 10^{-3}\,m^{3} = 0.03531\,ft^{3} = 61.02\,in^{3}

      • 1ft3=0.02832m3=28.32liters=7.477gallons1\,ft^{3} = 0.02832\,m^{3} = 28.32\,liters = 7.477\,gallons

      • 1gallon=3.788liters1\,gallon = 3.788\,liters

    • Area:

      • 1cm2=0.155in21\,cm^{2} = 0.155\,in^{2}

      • 1m2=104cm2=10.76ft21\,m^{2} = 10^{4}\,cm^{2} = 10.76\,ft^{2}

      • 1in2=6.452cm21\,in^{2} = 6.452\,cm^{2}

      • 1ft2=144in2=0.0929m21\,ft^{2} = 144\,in^{2} = 0.0929\,m^{2}

    • Time:

      • 1min=60s1\,min = 60\,s

      • 1h=3600s1\,h = 3600\,s

      • 1d=86,400s1\,d = 86,400\,s

      • 1y=365.24d=3.156×107s1\,y = 365.24\,d = 3.156 \times 10^{7}\,s

    • Angle:

      • 1rad=57.30=180π1\,rad = 57.30^{\circ} = \frac{180^{\circ}}{\pi}

      • 1=0.01745rad=π180rad1^{\circ} = 0.01745\,rad = \frac{\pi}{180}\,rad

      • 1revolution=360=2πrad1\,revolution = 360^{\circ} = 2\pi\,rad

      • 1rev/min(rpm)=0.1047rad/s1\,rev/min\,(rpm) = 0.1047\,rad/s

    • Speed:

      • 1m/s=3.281ft/s1\,m/s = 3.281\,ft/s

      • 1ft/s=0.3048m/s1\,ft/s = 0.3048\,m/s

      • 1mi/min=60mi/h=88ft/s1\,mi/min = 60\,mi/h = 88\,ft/s

      • 1km/h=0.2778m/s=0.6214mi/h1\,km/h = 0.2778\,m/s = 0.6214\,mi/h

      • 1mi/h=1.466ft/s=0.4470m/s=1.609km/h1\,mi/h = 1.466\,ft/s = 0.4470\,m/s = 1.609\,km/h

      • 1furlong/fortnight=1.662×104m/s1\,furlong/fortnight = 1.662 \times 10^{-4}\,m/s

    • Acceleration:

      • 1m/s2=100cm/s2=3.281ft/s21\,m/s^{2} = 100\,cm/s^{2} = 3.281\,ft/s^{2}

      • 1cm/s2=0.01m/s2=0.03281ft/s21\,cm/s^{2} = 0.01\,m/s^{2} = 0.03281\,ft/s^{2}

      • 1ft/s2=0.3048m/s2=30.48cm/s21\,ft/s^{2} = 0.3048\,m/s^{2} = 30.48\,cm/s^{2}

      • 1mi/hs=1.467ft/s21\,mi/h \cdot s = 1.467\,ft/s^{2}

    • Mass:

      • 1kg=103g=0.0685slug1\,kg = 10^{3}\,g = 0.0685\,slug

      • 1g=6.85×105slug1\,g = 6.85 \times 10^{-5}\,slug

      • 1slug=14.59kg1\,slug = 14.59\,kg

      • 1u=1.661×1027kg1\,u = 1.661 \times 10^{-27}\,kg

      • 1kgweight at globe surface=2.205lbwhere  g=9.80m/s21\,kg\,\text{weight at globe surface} = 2.205\,lb\,\text{where}\;g = 9.80\,m/s^{2}

    • Force:

      • 1N=105dyn=0.2248lb1\,N = 10^{5}\,dyn = 0.2248\,lb

      • 1lb=4.448N=4.448×105dyn1\,lb = 4.448\,N = 4.448 \times 10^{5}\,dyn

    • Pressure:

      • 1Pa=1N/m2=1.450×104lb/in2=0.0209lb/ft21\,Pa = 1\,N/m^{2} = 1.450 \times 10^{-4}\,lb/in^{2} = 0.0209\,lb/ft^{2}

      • 1bar=105Pa1\,bar = 10^{5}\,Pa

      • 1lb/in2=6895Pa1\,lb/in^{2} = 6895\,Pa

      • 1lb/ft2=47.88Pa1\,lb/ft^{2} = 47.88\,Pa

      • 1atm=1.013×105Pa=1.013bar=14.7lb/in2=2117lb/ft21\,atm = 1.013 \times 10^{5}\,Pa = 1.013\,bar = 14.7\,lb/in^{2} = 2117\,lb/ft^{2}

      • 1mmHg=1torr=133.3Pa1\,mm\,Hg = 1\,torr = 133.3\,Pa

    • Energy:

      • 1J=107ergs=0.239cal1\,J = 10^{7}\,ergs = 0.239\,cal

      • 1cal=4.186J1\,cal = 4.186\,J

      • 1ftlb=1.356J1\,ft \cdot lb = 1.356\,J

      • 1Btu=1055J=252cal=778ftlb1\,Btu = 1055\,J = 252\,cal = 778\,ft \cdot lb

      • 1eV=1.602×1019J1\,eV = 1.602 \times 10^{-19}\,J

      • 1kWh=3.600×106J1\,kWh = 3.600 \times 10^{6}\,J

    • Mass-Energy Equivalence:

      • 1kg=8.988×1016J1\,kg = 8.988 \times 10^{16}\,J

      • 1u=931.5MeV1\,u = 931.5\,MeV

      • 1eV=1.074×109u1\,eV = 1.074 \times 10^{-9}\,u

    • Power:

      • 1W=1J/s1\,W = 1\,J/s

      • 1hp=746W=550ftlb/s1\,hp = 746\,W = 550\,ft \cdot lb/s

      • 1Btu/h=0.293W1\,Btu/h = 0.293\,W

Dimensional Analysis

  • Dimension refers to a physical property described by words: time, length, or mass. This property remains the same regardless of units.

  • Dimensional analysis is the study of relationships between physical quantities by identifying these fundamental dimensions.

  • Dimensional Symbols:

    • Length: LL

    • Time: TT

    • Mass: MM

    • Electrical Current: II

    • Thermodynamic Temperature: θ\theta

    • Amount of Substance: NN

    • Luminous Intensity: JJ

  • Principles of Dimensional Consistency:

    • 1. For addition and subtraction, quantities must have identical dimensional units.

    • 2. For division and multiplication, quantities may have different dimensional units.

    • 3. For an equation to hold true, it must have the same dimensional units on both sides.

    • 4. Note: Constants and angles (e.g., cos(θ),sin(θ),tan(θ),1,2,12,43,exp,π,ln,log\cos(\theta), \sin(\theta), \tan(\theta), 1, 2, \frac{1}{2}, \frac{4}{3}, \exp, \pi, \ln, \log) have dimensional units equal to 11.

Dimensional Formulas for Standard Quantities

  • Displacement: M0LT0M^{0}LT^{0}

  • Area: L×L=L2L \times L = L^{2} (M0L2T0M^{0}L^{2}T^{0})

  • Volume: L×L×L=L3L \times L \times L = L^{3} (M0L3T0M^{0}L^{3}T^{0})

  • Velocity/Speed: L/T=LT1L/T = LT^{-1} (M0LT1M^{0}LT^{-1})

  • Momentum: MLT1MLT^{-1}

  • Acceleration: LT2LT^{-2} (M0LT2M^{0}LT^{-2})

  • Force: MLT2MLT^{-2}

  • Impulse: MLT1MLT^{-1}

  • Work / Energy / Torque: ML2T2ML^{2}T^{-2}

  • Power: ML2T3ML^{2}T^{-3}

  • Density (mass/volumemass/volume): ML3T0ML^{-3}T^{0}

  • Pressure (F/AF/A) / Stress / Young's Modulus: ML1T2ML^{-1}T^{-2}

  • Angular Displacement: M0L0T0M^{0}L^{0}T^{0}

  • Angular Velocity: M0L0T1M^{0}L^{0}T^{-1}

  • Angular Acceleration: M0L0T2M^{0}L^{0}T^{-2}

  • Moment of Inertia: ML2T0ML^{2}T^{0}

  • Angular Momentum: ML2T1ML^{2}T^{-1}

  • Frequency: M0L0T1M^{0}L^{0}T^{-1}

  • Strain: M0L0T0M^{0}L^{0}T^{0}

  • Surface Tension / Force Constant (spring): ML0T2ML^{0}T^{-2}

  • Coefficient of Viscosity: ML1T1ML^{-1}T^{-1}

  • Gravitational Constant (GG): M1L3T2M^{-1}L^{3}T^{-2}

  • Gravitational Potential: M0L2T2M^{0}L^{2}T^{-2}

  • Temperature (θ\theta): M0L0T0θ+1M^{0}L^{0}T^{0}\theta^{+1}

  • Heat: ML2T2ML^{2}T^{-2}

  • Specific Heat: M0L2T2θ1M^{0}L^{2}T^{-2}\theta^{-1}

  • Latent Heat: M0L2T2M^{0}L^{2}T^{-2}

  • Coefficient of Thermal Conductivity: MLT3θ1MLT^{-3}\theta^{-1}

  • Universal Gas Constant (RR): ML2T2θ1ML^{2}T^{-2}\theta^{-1}

  • Mechanical Equivalent of Heat (JJ): M0L0T0M^{0}L^{0}T^{0}

  • Charge (QQ): M0L0TAM^{0}L^{0}TA

  • Current (II): M0L0T0AM^{0}L^{0}T^{0}A

  • Electric Potential (VV): ML2T3A1ML^{2}T^{-3}A^{-1}

  • Electric Permittivity (ϵ0\epsilon_{0}): M1L3T4A2M^{-1}L^{-3}T^{4}A^{2}

  • Intensity of Electric Field (EE): MLT3A1MLT^{-3}A^{-1}

  • Capacitance (CC): M1L2T4A2M^{-1}L^{-2}T^{4}A^{2}

  • Dielectric Constant: M0L0T0M^{0}L^{0}T^{0}

  • Resistance (RR): ML2T3A2ML^{2}T^{-3}A^{-2}

  • Conductance: M1L2T3A2M^{-1}L^{-2}T^{3}A^{2}

  • Specific Resistance / Resistivity (ρ\rho): ML3T3A2ML^{3}T^{-3}A^{-2}

  • Conductivity: M1L3T3A2M^{-1}L^{-3}T^{3}A^{2}

  • Magnetic Induction (BB): MT2A1MT^{-2}A^{-1}

  • Magnetic Flux (ϕ\phi): ML2T2A1ML^{2}T^{-2}A^{-1}

  • Magnetic Intensity (HH): M0L1T0AM^{0}L^{-1}T^{0}A

  • Magnetic Permeability: MLT2A2MLT^{-2}A^{-2}

  • Coefficient of Self/Mutual Inductance: ML2T2A2ML^{2}T^{-2}A^{-2}

  • Electric Dipole Moment (pp): M0LTAM^{0}LTA

  • Magnetic Dipole Moment (MM): M0L2AT0M^{0}L^{2}AT^{0}

Sample Mathematical Problems

  • Sample Problem 1 (Rest Energy Calculation):

    • Formula: E=mc2E = mc^{2}

    • Given: electron mass m=9.11×1031kgm = 9.11 \times 10^{-31}\,kg

    • Required answer precision: 3 significant figures.

    • Unit: Joules (JJ).

  • Sample Problem 2 (Density Calculation):

    • Formula: Density=massvolumeDensity = \frac{mass}{volume}

    • Given: mass = 1.80kg1.80\,kg, volume = 6.0×104m36.0 \times 10^{-4}\,m^{3}

    • Task: Find density in units of kg/m3kg/m^{3}.

  • Uncertainty: Defined as the maximum difference between the measured value and the true value. Examples of notation include:

    • 40.86extcm±0.09extcm40.86 \, ext{cm} \pm 0.09 \, ext{cm}

    • 1.879(25)extkg1.879(25) \, ext{kg}

    • 63extohms±10%63 \, ext{ohms} \pm 10\%

  • Accuracy: Describes how close measurements are to the true value. This includes examples like:

    • A thermometer reads 98.6ext°F98.6 \, ext{°F} for your body temperature, which is accurate if the true temperature is also 98.6ext°F98.6 \, ext{°F}.

  • Precision: Measures how close repeated measurements are to each other. An example would be:

    • If you measure the length of a table five times and get 100.0extcm,100.1extcm,100.0extcm,99.9extcm,100.1extcm100.0 \, ext{cm}, 100.1 \, ext{cm}, 100.0 \, ext{cm}, 99.9 \, ext{cm}, 100.1 \, ext{cm}, this indicates high precision, even if the true length is 101extcm.101 \, ext{cm}.


Uncertainty Problems
  1. A scale reads 12.4kg±0.1kg12.4 \, kg \pm 0.1 \, kg. What is the true value if the measurement is accurate?

    • Solution: The range of true values is:

      • Calculate lower limit: 12.40.1=12.3kg12.4 - 0.1 = 12.3 \, kg

      • Calculate upper limit: 12.4+0.1=12.5kg12.4 + 0.1 = 12.5 \, kg

      • Answer: True value could be between 12.3kg12.3 \, kg and 12.5kg12.5 \, kg.

  2. A thermometer reads 37.0C±0.2C37.0 \, ^{\circ}C \pm 0.2 \, ^{\circ}C. What is the range of possible true temperatures?

    • Solution:

      • Lower limit: 37.00.2=36.8C37.0 - 0.2 = 36.8 \, ^{\circ}C

      • Upper limit: 37.0+0.2=37.2C37.0 + 0.2 = 37.2 \, ^{\circ}C

      • Answer: Between 36.8C36.8 \, ^{\circ}C and 37.2C37.2 \, ^{\circ}C.

  3. A measurement is reported as 5000m±50m5000 \, m \pm 50 \, m. Is this a precise measurement?

    • Solution:

      • Uncertainty in 5000m5000 \, m is significant compared to its magnitude.

      • Answer: No, it is not precise due to a significant uncertainty relative to the measurement.

  4. An engineer measures a component length to be 150mm±2mm150 \, mm \pm 2 \, mm. Is the uncertainty acceptable?

    • Solution:

      • Uncertainty is small compared to the measurement size.

      • Answer: Yes, the uncertainty is acceptable for engineering applications.

  5. The measured distance is 75.50m±0.5m75.50 \, m \pm 0.5 \, m. Is this measurement accurate?

    • Solution:

      • Accuracy check requires comparison with true value; true value should be around 75.50m75.50 \, m.

      • Answer: Accuracy can only be evaluated against a standard; if known, check within the uncertainty range.

  6. An instrument has an uncertainty of 0.01kg0.01 \, kg. If it measures 35.5kg35.5 \, kg, what is the potential range of error?

    • Solution:

      • Range is 35.50.01=35.49kg35.5 - 0.01 = 35.49 \, kg to 35.5+0.01=35.51kg35.5 + 0.01 = 35.51 \, kg.

      • Answer: From 35.49kg35.49 \, kg to 35.51kg35.51 \, kg.

  7. A length of 25.0cm±0.2cm25.0 \, cm \pm 0.2 \, cm is recorded. If the true length is 24.8cm24.8 \, cm, classify if the measurement is accurate.

    • Solution:

      • Check if 24.8cm24.8 \, cm falls within 25.0±0.225.0 \pm 0.2.

      • Range: 24.8cm24.8 \, cm falls in between 24.8cm24.8 \, cm and 25.2cm25.2 \, cm.

      • Answer: Yes, the measurement is accurate since 24.8cm24.8 \, cm is within the uncertainty range.

  8. An electronic balance gives readings of 200.0g±0.05g200.0 \, g \pm 0.05 \, g. How would you assess its precision?

    • Solution:

      • Compare uncertainty against measurement; small uncertainty signifies high precision.

      • Answer: The measurement is precise due to a small uncertainty relative to the whole.

  9. A reading of 1.5L±0.1L1.5 \, L \pm 0.1 \, L indicates good precision. True?

    • Solution:

      • Good precision is characterized by low uncertainty.

      • Answer: Yes, it is precise; accuracy cannot be confirmed without a reference.

  10. A height of 1.72m±0.03m1.72 \, m \pm 0.03 \, m is recorded. Is the uncertainty magnitude reasonable for such a measurement?

    • Solution:

      • Evaluate if 0.03m0.03 \, m is acceptable for 1.72m1.72 \, m.

      • Answer: Yes, the uncertainty is appropriate given the certainty of the measuring device.

Accuracy and Precision Problems
  1. If a dart lands on the bullseye, what can you say about your accuracy and precision?

    • Solution:

      • Definitions: Accurate = close to true value; precise = closely grouped measurements.

      • Answer: Both accuracy and precision are high.

  2. All darts hit close together but not on the bullseye indicate:

    • Solution:

      • Close together = precise; not on target = not accurate.

      • Answer: High precision, low accuracy.

  3. A student repeatedly measures 10cm10 \, cm but gets a range from 9.0cm9.0 \, cm to 11.0cm11.0 \, cm. Classify the measurement's precision.

    • Solution:

      • Measure the spread of results.

      • Answer: Low precision due to a wide spread.

  4. If several measurements of a known length yield an average shorter than expected, what does this indicate about accuracy?

    • Solution:

      • Average is less than true = measurement is inaccurate.

      • Answer: The measurement is inaccurate.

  5. A gauge consistently gives 15.0mm15.0 \, mm when measuring a part that is 15.5mm15.5 \, mm indicates:

    • Solution:

      • Consistency = precise; difference from true value = inaccurate.

      • Answer: High precision, low accuracy.

  6. A set of measurements lands all over a range but averages correctly reflects the true value. What does this indicate?

    • Solution:

      • Wide distribution means low precision; average being correct indicates high accuracy.

      • Answer: Low precision, high accuracy.

  7. Measuring devices, which yield varying results but one average value, indicate:

    • Solution:

      • Variability means low precision; validity of average relates to accuracy.

      • Answer: Low precision and could be inaccurate as well.

  8. Five measurements yield results of 10.5m,10.6m,10.5m,10.7m,10.5m10.5 \, m, 10.6 \, m, 10.5 \, m, 10.7 \, m, 10.5 \, m. Assess precision and accuracy without a reference.

    • Solution:

      • Close together indicates precision; reference needed for accuracy.

      • Answer: Good precision; accuracy cannot be determined.

  9. If a thermometer reads consistently 20C20 \, ^{\circ}C for an ice-water mix, what is its accuracy?

    • Solution:

      • Check against known melting point of ice.

      • Answer: Accurate for the ice-water mixture.

  10. If measurement variability remains within 0.01m0.01 \, m around a standard but is incorrect, what could be inferred?

    • Solution:

      • Good precision but being consistently off means inaccurate.

      • Answer: Good precision but low accuracy.

Significant Figures Problems
  1. How many significant figures are in 0.0042m0.0042 \, m?

    • Solution:

      • Identify non-zero digits = 4 and 2.

      • Answer: 2 significant figures (4 and 2).

  2. Calculate the result of 3.00J÷2.0g3.00 \, J \div 2.0 \, g. How many significant figures should the answer have?

    • Solution:

      • Perform division: 3.00J÷2.0g=1.5J/g3.00 \, J \div 2.0 \, g = 1.5 \, J/g.

      • Consider significant figures: minimum between 3 and 2.

      • Answer: Answer should have 2 significant figures. Result: 1.5J/g1.5 \, J/g.

  3. What is the significant figure count for 0.000560.00056?

    • Solution:

      • Identify non-zero digits = 5 and 6; leading zeros are not counted.

      • Answer: 2 significant figures (5 and 6).

  4. The number 5.6005.600 has how many significant figures?

    • Solution:

      • Count all: non-zero digits and trailing zeros due to decimal confirm count.

      • Answer: 4 significant figures (5, 6, and two trailing zeros).

  5. Round 78.3978.39 to 3 significant figures.

    • Solution:

      • Round: Observe the fourth digit (3), so it remains.

      • Answer: 78.478.4.

  6. Evaluate how many significant figures are in 3300m3300 \, m if there is no decimal.

    • Solution:

      • Trailing zeros without decimal do not count as significant.

      • Answer: 2 significant figures (3 and 3).

  7. Calculate 12.2+3.412.2 + 3.4. How many significant figures should the answer use?

    • Solution:

      • Perform addition: 12.2+3.4=15.612.2 + 3.4 = 15.6.

      • Determine by the number with least decimal places (1 decimal).

      • Answer: 15.615.6 with 1 decimal place.

  8. If 0.00530.0053 is multiplied by 12001200, how many significant figures will the result have?

    • Solution:

      • Calculate: 0.0053×1200=6.360.0053 \times 1200 = 6.36.

      • Minimal significant figures from numbers involved.

      • Answer: 2 significant figures; provides a result of 6.46.4.

  9. What is 0.004500.00450 rounded to 3 significant figures?

    • Solution:

      • Zeros after a decimal point count when they follow significant figures.

      • Answer: 0.004500.00450 retains 3 significant figures.

  10. In 5000050000, how many significant figures should we consider if it's ambiguous?

    • Solution:

      • Without clarification, analyze significant nature of zeros.

      • Answer: Not determined without clarification; can be considered 1 or 5 significant figures.

Unit Conversion Problems
  1. Convert 10km10 \, km to meters.

    • Solution:

      • Use conversion: 10km×1000m/km=10000m10 \, km \times 1000 \, m/km = 10000 \, m.

      • Answer: 10000m10000 \, m.

  2. How many liters are in 5.0gallons5.0 \, gallons?

    • Solution:

      • Conversion: 5.0×3.785L/gallon=18.93L5.0 \times 3.785 \, L/gallon = 18.93 \, L.

      • Answer: 18.93L18.93 \, L.

  3. Convert 20in20 \, in to centimeters.

    • Solution:

      • Change: 20in×2.54cm/in=50.8cm20 \, in \times 2.54 \, cm/in = 50.8 \, cm.

      • Answer: 50.8cm50.8 \, cm.

  4. Change 45lbs45 \, lbs to kilograms.

    • Solution:

      • Convert: 45lbs×0.4536kg/lb=20.41kg45 \, lbs \times 0.4536 \, kg/lb = 20.41 \, kg.

      • Answer: 20.41kg20.41 \, kg.

  5. If a velocity of 60mi/h60 \, mi/h is needed in km/h, what is the conversion?

    • Solution:

      • Velocity change: 60mi/h×1.609km/mi=96.56km/h60 \, mi/h \times 1.609 \, km/mi = 96.56 \, km/h.

      • Answer: 96.56km/h96.56 \, km/h.

  6. Convert 150m150 \, m to feet.

    • Solution:

      • Perform conversion: 150m×3.281ft/m=492.13ft150 \, m \times 3.281 \, ft/m = 492.13 \, ft.

      • Answer: 492.13ft492.13 \, ft.

  7. How many milliliters are in 3.0L3.0 \, L?

    • Solution:

      • Convert: 3.0L×1000mL/L=3000mL3.0 \, L \times 1000 \, mL/L = 3000 \, mL.

      • Answer: 3000mL3000 \, mL.

  8. Transform 30g30 \, g to ounces.

    • Solution:

      • Change: 30g×1oz28.35g=1.06oz30 \, g \times \frac{1 \, oz}{28.35 \, g} = 1.06 \, oz.

      • Answer: 1.06oz1.06 \, oz.

  9. Convert 5.0yards5.0 \, yards to meters.

    • Solution:

      • Use conversion: 5.0yards×0.9144m/yard=4.57m5.0 \, yards \times 0.9144 \, m/yard = 4.57 \, m.

      • Answer: 4.57m4.57 \, m.

  10. If you have 100F100 \, ^{\circ}F, what is it in degrees Celsius?

    • Solution:

      • Apply formula: $$^{\circ}C = (^{\circ}F - 32) \times