Kinetic Molecular Theory (KMT) Notes

Kinetic Molecular Theory (KMT)

Kinetic Molecular Theory (KMT)

  • A model that attempts to explain gas behavior.

  • Postulates of the KMT:

    • Gases are mostly empty space; the volume of the particles is negligible.
    • Gas particles are in constant random motion. Pressure is due to the collisions of the gas particles with the container walls.
    • Gas particles neither attract nor repel each other.
    • The average kinetic energy of a gas sample is proportional to the Kelvin temperature.

    KEAVE=(3/2)RTKE_{AVE} = (3/2)RT where R=8.3145J/KmolR = 8.3145 J/K \cdot mol

Path of One Particle in a Gas

  • Gases are in constant random motion.
  • Pressure=Force of CollisionsAreaPressure = \frac{Force \ of \ Collisions}{Area}

Boyle's Law

  • PV=constantPV = constant
  • at constant n and T
  • Volume is decreased.

Avogadro's Law

  • V=constant(n)V = constant(n)
  • at constant P and T
  • Gas cylinder- Moles of gas increase.
  • Increase volume to return to original pressure.

P vs n

  • at constant V and T

Kinetic Energy of Gases

  • KE=energy due to motion:KE=12mv2KE = energy \ due \ to \ motion: KE = \frac{1}{2}mv^2 where m = mass and v = velocity
  • From KMT, average KE directly proportional to T: (KE)Ave=(3/2)RT(KE)_{Ave} = (3/2)RT where R=8.3145J/KmolR = 8.3145 J/K \cdot mol

Average Kinetic Energy

  • (KE)Ave=(3/2)RT(KE)_{Ave} = (3/2)RT and KE=12mv2KE = \frac{1}{2}mv^2\ *
  • Why talk about the average KE? Molecules possess many different KE’s; easiest to talk about average.
  • Why do we have a distribution of KE? Molecules possess many different velocities at a specific temperature.
  • Why is (KE)Ave(KE)_{Ave} directly proportional to T? As T increases, the average velocity of the gas molecules increases, which causes the average KE to increase.

Velocity Distribution at STP for an O2O_2 Gas Sample

  • Relative number of O2O_2 molecules with given velocity.
  • Molecular velocity (m/s)

Velocity Distributions at Different Temps

  • Relative number of N2N_2 molecules with given velocity

Charles's Law

  • V=constant(T)V = constant(T)
  • at constant n and P
  • Temperature is increased.

P vs T

  • at constant n and V
  • Temperature is increased.

Relative Velocities of Gas Particles

  • Compare the average velocity of a sample of H<em>2H<em>2 molecules to a sample of O</em>2O</em>2 molecules at some constant temperature? Which has the faster average velocity, or do the two different gas samples have the same average velocity?
  • Answer: the sample of the smaller H2H_2 molecules must have the faster average velocity. In general, at constant temperature, the lighter the gas molecules, the faster the average velocity.

Relative Molecular Speed Distribution of H<em>2H<em>2 and UF</em>6UF</em>6

  • Percentage of molecules.

Question on Velocity Distributions

  • If the gases represented in the following plot are He, H<em>2OH<em>2O, N</em>2N</em>2, O<em>2O<em>2, and H</em>2H</em>2, which curve represents the molecular speed distribution for N2(g)N_2(g)?

KMT Question

  • Consider two gases, A and B, in identical containers of equal volume. Both containers are at the same temperature and pressure.

    • A: mass = 0.34 g
    • B: mass = 0.48 g
  • How many of the following five statements are true?

    • I. The number of molecules of A is equal to the number of molecules of B. True
    • II. The molar mass of A is greater than the molar mass of B. False
    • III. Both samples have the same average kinetic energy. True
    • IV. The molecules of A have the same average velocity as the molecules of B. False
    • V. The molecules of A collide with the container walls more frequently than the molecules of B. True

Relative Velocities Question

  • How much faster, on average, are H<em>2H<em>2 molecules as compared to O</em>2O</em>2 molecules (at some nonzero Kelvin temperature)?

Calculating Relative Velocities

  • Graham (1830) – postulated that the average velocity of a molecule is inversely proportional to the square root of the molar mass (M).
  • v=average velocity=3RTMv = average \ velocity = \sqrt{\frac{3RT}{M}}
  • For two gases:
    v<em>1v</em>2=M<em>2M</em>1\frac{v<em>1}{v</em>2} = \sqrt{\frac{M<em>2}{M</em>1}}

Measuring Relative Velocities

  • Diffusion - rate that gases mix
  • Effusion - rate that gases pass through a tiny hole
  • Both quantities are directly proportional to the average velocity of the gas.

Effusion of Gas into Evacuated Chamber

Diffusion Rates of NH3NH_3 and HClHCl Molecules Through Air

  • NH<em>3(g)+HCl(g)NH</em>4Cl(s)NH<em>3(g) + HCl(g) \rightarrow NH</em>4Cl(s)

Real Gases

  • Some assumptions of the kinetic molecular theory are oversimplifications of real gas properties.
  • The two assumptions that don’t always hold true for real gases are:
    • Gas particles do experience intermolecular attractions. Effect? P that we measure (real) is less than the P if the gas is ideal.
    • Gas particles have a real volume that may not be negligible. Effect? V of a container (real) is not the actual V of empty space available for the gas particles to move about.

Effect of Intermolecular Forces

VAN DER WAALS EQUATION FOR REAL GASES

  • “a” and “b” are constants that are experimentally determined for each gas.
  • “a” is directly related to the strength of the intermolecular forces.
  • “b” is directly related to molecular size.

When Does a “Real” Gas Behave Most “Ideal”?

  • The best conditions for ideal behavior are at high temperatures and low pressures. Why?
    • At high temperatures, the gas particles are moving very fast. This minimizes the effect of intermolecular forces between gas particles.
    • At low pressure, there is a lot of empty space between gas particle. This minimizes the effect of volume of gas particles.

Low Pressure vs High Pressure

  • Low Pressure - lots of space between molecules. Volume of container taken up by the volume of the molecules themselves is minimal.
  • Higher Pressure – gas particles are more crowded. The volume of the container taken up by the volume of the molecules themselves is much more pronounced.