Random Processes for Electrical Engineering - Tutorial 4 Notes

Mahindra University Ecole Centrale School of Engineering

Course Information

  • Program: B. Tech.
  • Branch: ECE (Electronics and Communication Engineering)
  • Year: II
  • Semester: II
  • Subject: Random Processes for Electrical Engineering (EC2204)
  • Tutorial Number: 4

Tutorial Questions

Question 1
  • Problem Statement: Consider a discrete random process defined as:
    • y[n]=x[n]x[n1]y[n] = x[n] - x[n - 1]
    • where x[n]x[n] is a Wide-Sense Stationary (WSS) process.
  • Task: Find the Power Spectral Density (PSD) of the process y[n]y[n].
    • Approach for Solution:
    1. Since x[n]x[n] is WSS, it has a constant mean and its autocorrelation function depends only on the time difference.
    2. Using the properties of linear combinations of WSS processes, the autocorrelation function of y[n]y[n] can be derived by:
      • Ry[m]=E[y[n]y[n+m]]R_y[m] = E[y[n]y[n+m]] where y[n]=x[n]x[n1]y[n] = x[n] - x[n-1].
    3. The PSD can be obtained using:
      • S_y(f) = ext{DFT}igrace R_y[m]igrace
Question 2
  • Problem Statement: Consider a random process defined as:
    • X(t)=Aextcos(2t+heta)X(t) = A ext{cos}(2t + \boldsymbol{ heta})
    • where:
    • AA is uniformly distributed over the interval 0 < a < 1
    • hetaheta is uniformly distributed over the interval 0 < heta < 2 ext{π}
  • Task: Verify if X(t)X(t) is WSS and find its PSD.
    • Approach for Solution:
    1. WSS Verification:
      • Check if the mean E[X(t)]E[X(t)] is constant:
        • E[X(t)]=E[A]E[extcos(2t+heta)]E[X(t)] = E[A]E[ ext{cos}(2t+ heta)] (since A and θ are independent).
      • Calculate the mean as:
        • E[A]=12E[A] = \frac{1}{2} (as the mean of a uniform distribution over $(0, 1)$)
        • E[extcos(2t+heta)]=0E[ ext{cos}(2t + heta)] = 0 (over one period of a cosine function with uniformly distributed phase)
      • Therefore, E[X(t)]=0E[X(t)] = 0, which is constant.
    2. Finding PSD:
      • Using the definition of Power Spectral Density and applying the properties of the cosine function:
        • Utilize the formula for the autocorrelation function, and derive:
        • SX(f)=A22[extδ(f1)+extδ(f+1)]S_X(f) = \frac{A^2}{2}[ ext{δ}(f - 1) + ext{δ}(f + 1)]
Question 3
  • Problem Statement: Consider a WSS random process X(t)X(t) with the following power spectral density (PSD):
    • SX(f)=11+f2S_X(f) = \frac{1}{1 + f^2}
  • Task: Determine if the PSD is physically realizable and justify the answer.
    • Justification Approach:
    1. A PSD is physically realizable if it satisfies the requirement of being non-negative and integrable.
    2. Non-negativity: Since f2f^2 is always non-negative, 1+f^2 > 0
      ightarrow S_X(f) is non-negative.
    3. Integrability: Check if:
      • extIntegrability:extIntegrateSX(f)ext{Integrability: } ext{Integrate } S_X(f) over the entire frequency range.
      • Evaluate:
        extArea=11+f2,ext{Area} = \frac{1}{1+f^2}, which converges as $f$ approaches infinity.
      • Hence, it is integrable and thus physically realizable.
Question 4
  • Problem Statement: Given X(t)X(t) is a zero-mean Gaussian process, find the PSD of Y(t)=X2(t)Y(t) = X^2(t).
    • Approach for Solution:
    1. X(t)X(t) being zero-mean guarantees that the transformation to Y(t)Y(t) involves calculations of expectations.
    2. Use the formula for the PSD of a nonlinear transformation:
    • If Y(t)=X2(t),Y(t) = X^2(t), then utilize:
      • SY(f)=SX(0)+SX(0)2S_Y(f) = S_X(0) + \frac{S_X'(0)}{2} where SX(0)S_X'(0) is the derivative of the PSD of XX evaluated at zero frequency.
    1. Calculate:
      • SY(f)=ext(relatedvaluesofSX(f)extandtheirderivatives)S_Y(f) = ext{(related values of } S_X(f) ext{ and their derivatives)}