Inductors Notes

Inductors

Inductor Basics

  • An inductor is a device designed with large self-inductance, useful in circuits, especially AC circuits.
  • Achieving large inductance:
    • Use many turns of wire (like a solenoid) to create a concentrated magnetic field.
    • Amplify the field by adding a ferromagnetic material like iron oxide.
  • Examples include toroidal coils, cylindrical coils with adjustable iron slugs, and laminated iron frame coils.
    • Lamination prevents eddy currents.

Self-Inductance Calculation

  • Consider a cylindrical solenoid with an iron core, characterized by magnetic permeability μ\mu.
  • The magnetic field inside the solenoid is given by B=μnIB = \mu n I, where:
    • nn is the number of turns per unit length (NL\frac{N}{L}).
    • II is the current.
  • Magnetic flux is ϕ=BA=μNLIA\phi = B \cdot A = \mu \frac{N}{L} I A.
  • Self-inductance LL is calculated as: L=NϕI=N2μAlL = \frac{N \phi}{I} = \frac{N^2 \mu A}{l}.

Inductor Behavior in Circuits

  • Symbol for an inductor: a loop of wire.
  • Induced EMF opposes the rate of change of current (Faraday's Law).
  • If current is increasing, the induced EMF opposes this increase, leading to a voltage drop.
  • If current is decreasing, the induced EMF reinforces the decrease, leading to a voltage increase.

Inductors in Series

  • Total inductance for inductors in series (assuming no mutual inductance) is the sum of individual inductances: L<em>total=L</em>1+L<em>2+L</em>3+L<em>{total} = L</em>1 + L<em>2 + L</em>3 + …
  • The EMFs are additive when inductors are in series.

Inductors in Parallel

  • Total inductance for inductors in parallel is calculated by summing the inverse of individual inductances:
    1L<em>total=1L</em>1+1L<em>2+1L</em>3+\frac{1}{L<em>{total}} = \frac{1}{L</em>1} + \frac{1}{L<em>2} + \frac{1}{L</em>3} + …
  • The voltage across inductors in parallel is the same.

Energy Storage in an Inductor

  • The energy is stored in a magnetic field.
  • The power required to increase the current is P=EMFIP = -EMF \cdot I.
  • Total energy stored in an inductor: U=12LI2U = \frac{1}{2} L I^2
  • Alternative formulas:
    • U=N2ϕ22LU = \frac{N^2 \phi^2}{2L}
    • U=12INϕU = \frac{1}{2} I N \phi

Magnetic Energy Density

  • For a solenoid, the total magnetic energy is U=12B2μ0AlU = \frac{1}{2} \frac{B^2}{\mu_0} A l.
  • The magnetic energy density is um=UVolume=12B2μu_m = \frac{U}{Volume} = \frac{1}{2} \frac{B^2}{\mu}.
  • Total energy density with both electric and magnetic fields: u<em>total=u</em>m+u<em>e=12ϵ</em>0E2+12B2μu<em>{total} = u</em>m + u<em>e = \frac{1}{2} \epsilon</em>0 E^2 + \frac{1}{2} \frac{B^2}{\mu}.