Characterizations of Invertible Matrices and the Invertible Matrix Theorem

Overview of the Role of Pivots in Invertibility

  • The fundamental characterization of an n×nn \times n matrix AA centers on its pivot positions. These pivots determine the behavior of the matrix in linear systems and transformations.
  • For any square matrix AA of size n×nn \times n, each of the following statements is true if and only if a specific pivot condition is met:
  • Pivot in Every Column of AA:
    • The equation Ax=0A\mathbf{x} = \mathbf{0} has only the trivial solution.
    • The columns of AA are linearly independent.
    • The linear transformation T(x)=AxT(\mathbf{x}) = A\mathbf{x} is one-to-one.
  • Pivot in Every Row of AA:
    • The equation Ax=bA\mathbf{x} = \mathbf{b} has a solution for every b\mathbf{b} in Rn\mathbb{R}^n.
    • The columns of AA span Rn\mathbb{R}^n.
    • The linear transformation T(x)=AxT(\mathbf{x}) = A\mathbf{x} is onto.
  • Special Case for Square Matrices (m=nm = n):
    • For a square matrix, having a pivot in every column is logically equivalent to having a pivot in every row. If one of these conditions holds, both must hold.

The Invertible Matrix Theorem (IMT)

  • The Invertible Matrix Theorem provides a comprehensive list of properties that are logically equivalent for an n×nn \times n matrix AA. If any one of these statements is true for a particular matrix AA, then they are all true. Conversely, if one is false, they are all false.
  • The Equivalent Statements:
    • (a) The matrix AA is an invertible matrix.
    • (b) The matrix AA is row equivalent to the n×nn \times n identity matrix InI_n.
    • (c) The matrix AA has nn pivot positions.
    • (d) The equation Ax=0A\mathbf{x} = \mathbf{0} has only the trivial solution.
    • (e) The columns of AA form a linearly independent set.
    • (f) The linear transformation T(x)=AxT(\mathbf{x}) = A\mathbf{x} is one-to-one.
    • (g) The equation Ax=bA\mathbf{x} = \mathbf{b} has at least one solution for each b\mathbf{b} in Rn\mathbb{R}^n.
    • (h) The columns of AA span Rn\mathbb{R}^n.
    • (i) The linear transformation T(x)=AxT(\mathbf{x}) = A\mathbf{x} maps onto Rn\mathbb{R}^n.
    • (j) There exists an n×nn \times n matrix CC such that CA=ICA = I.
    • (k) There exists an n×nn \times n matrix DD such that AD=IAD = I.
    • (l) The transpose matrix ATA^T is an invertible matrix.

Logic and Proof Structure of the IMT

  • The proof of the Invertible Matrix Theorem typically follows a "circle of implications" where several statements are linked in a chain (e.g., (a)    (b)    (c)    (a)(a) \implies (b) \implies (c) \dots \implies (a)).
  • Specific Logical Links:
    • Statement (k) is linked because the inverse matrix itself works as the matrix DD.
    • Statements (g), (h), and (i) are known to be equivalent for any matrix, connecting them as a block to the theorem.
    • Statements (d), (e), and (f) are also equivalent for any matrix AA, connecting them as a separate block.
    • The transpose (AT)(A^T) link is established by the property that if AA is invertible, then (AT)1=(A1)T(A^T)^{-1} = (A^{-1})^T.

Implications and Disjoint Classes of Matrices

  • The Invertible Matrix Theorem divides the set of all possible n×nn \times n matrices into two distinct, disjoint classes:
    • Invertible (Nonsingular) Matrices: These meet all the criteria listed in the IMT.
    • Noninvertible (Singular) Matrices: These fail all the criteria listed in the IMT.
  • Properties of Singular Matrices: A singular n×nn \times n matrix will:
    • Not be row equivalent to the identity matrix InI_n.
    • Have fewer than nn pivot positions.
    • Have columns that are linearly dependent.
    • Fail to span Rn\mathbb{R}^n.
  • If a matrix AA is invertible, it is also true that its inverse A1A^{-1} is invertible, with (A1)1=A(A^{-1})^{-1} = A.

Practical Application and Constraints of the IMT

  • Example Application: To determine if a matrix is invertible, one can perform row reduction. If a 3×33 \times 3 matrix is reduced and found to have three pivot positions, it is invertible by statement (c) of the IMT.
  • Constraint - Square Matrices Only: The Invertible Matrix Theorem applies exclusively to square matrices.
    • For example, if a 4×34 \times 3 matrix (non-square) has linearly independent columns, the IMT cannot be used to make conclusions about the existence of solutions for Ax=bA\mathbf{x} = \mathbf{b}. The theorem does not bridge column independence and the existence of solutions for non-square matrices.

Invertible Linear Transformations

  • Matrix multiplication corresponds directly to the composition of linear transformations. When matrix AA is invertible, it describes a transformation that can be "undone."
  • Definition of an Invertible Transformation: A linear transformation T:RnRnT: \mathbb{R}^n \rightarrow \mathbb{R}^n is invertible if there exists a function S:RnRnS: \mathbb{R}^n \rightarrow \mathbb{R}^n such that:
    1. S(T(x))=xS(T(\mathbf{x})) = \mathbf{x} for all x\mathbf{x} in Rn\mathbb{R}^n.
    2. T(S(x))=xT(S(\mathbf{x})) = \mathbf{x} for all x\mathbf{x} in Rn\mathbb{R}^n.
  • Theorem 9: Let T:RnRnT: \mathbb{R}^n \rightarrow \mathbb{R}^n be a linear transformation and let AA be its standard matrix. TT is invertible if and only if AA is an invertible matrix.
  • In this case, the inverse transformation SS is unique and is represented by the matrix A1A^{-1}, where S(x)=A1xS(\mathbf{x}) = A^{-1}\mathbf{x}.

Proof of Theorem 9

  • Part 1: If TT is invertible, then AA is invertible:
    • Assume TT is invertible. By the definition of an inverse function, TT must map onto Rn\mathbb{R}^n.
    • Proof: For any b\mathbf{b} in Rn\mathbb{R}^n, let x=S(b)\mathbf{x} = S(\mathbf{b}). Then T(x)=T(S(b))=bT(\mathbf{x}) = T(S(\mathbf{b})) = \mathbf{b}, showing every b\mathbf{b} is in the range.
    • Since TT is onto, statement (i) of the Invertible Matrix Theorem implies matrix AA is invertible.
  • Part 2: If AA is invertible, then TT is invertible:
    • Conversely, if AA is invertible, we define a transformation S(x)=A1xS(\mathbf{x}) = A^{-1}\mathbf{x}.
    • By the properties of matrix inverses: S(T(x))=A1(Ax)=Ix=xS(T(\mathbf{x})) = A^{-1}(A\mathbf{x}) = I\mathbf{x} = \mathbf{x}.
    • Similarly: T(S(x))=A(A1x)=Ix=xT(S(\mathbf{x})) = A(A^{-1}\mathbf{x}) = I\mathbf{x} = \mathbf{x}.
    • This satisfies both conditions of an invertible transformation.