Crane Chemistry Equillibrium

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Last updated 12:35 AM on 6/9/26
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25 Terms

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Equilibrium is reached when …

rate of forward reaction = rate of reverse reaction

concentrations of reactants and products are constant

<p>rate of forward reaction = rate of reverse reaction</p><p>concentrations of reactants and products are constant</p><img src="https://assets.knowt.com/user-attachments/18d9265e-c614-4f34-afff-400dfcf481b8.png" data-width="100%" data-align="center" alt=""><p></p>
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Law of Mass Action

For reaction: e A + f B →← g C + h D

Equilibrium expression:

K = ([C]^g [D]^h) / ([A]^e * [B]^f)

K = equilibrium constant

Brackets unit is mol/L (M) (Molarity)

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Magnitude of K

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K>1

more products at equilibrium

Equilibrium lies to the right

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K=1

No! check your math

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K < 1

more reactants at equilibrium

equilibrium lies to the left

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Calculating Kp from Kc

Kp = Kc (RT)∆n

where:

R = 0.0821

T = temperature in kelvin

∆n = moles of products - moles of reactants

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Homogeneous Equilibria

all reactants / products are in one phase

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Heterogeneous Equilibria

reactants / products are in more than one phase

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Solids and liquids are

not included in K calculations

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Manipulating K

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Swapping products and reactants

take the reciprocal of K

example:

PCl5(s) →/← PCl3(L) + Cl2(g) ——- Kc=0.0239

turns into

PCl3(L) + Cl2(g) →/← PCl5(s) ——- Kc= 1 / 0.0239

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Changing Coefficients

put K to the coefficient power

example:

PCl5(s) →/← PCl3(L) + Cl2(g) ——- Kc= 0.0239

turns into

2PCl5(s) →/← 2PCl3(L) + 2Cl2(g) ——- Kc = 0.0239²

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Adding reactions

multiply k’s

example:

2CO2(g) + H2O(g) →← 2O2(g) + CH2CO(g)

K = 6.1 E8

CH4(g) + 2O2(g) →← CO2(g) + 2H2O(g)

K = 1.2 E14

6.1E8 * 1.2 E14 = 7.3 E22

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Reaction Quotient (Q)

To determine if a reaction is at equilibrium, compare Q to a given K

For reaction: e A + f B →← g C + h D

Q = ([C]^g [D]^h) / ([A]^e * [B]^f)

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Q = K

reaction is at equilibrium

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Q < K

too many reactants, reaction must go forward / shift right

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Q > K

too many products, must go in reverse / shift left

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Lechatelier’s Principle

if a stress is applied to a system at equilibrium, the position of teh equilibrium will shift to alleviate that stress

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3 ways to apply stress

change in amount

change in pressure (volume)

change in temperature

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Change in Amount

1N2(g) + 3H2(g) →/← 2NH3(g)

add N2 - shifts right

add NH3 - shifts left

remove N2 - shifts left

remove NH3 - shifts right

if a component is added, the equilibrium shifts to lower the concentration of that component

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Change in Pressure (Volume)

1N2(g) + 3H2(g) →/← 2NH3(g)

  1. add an inert gas - no effect

  2. change the volume of the container

    1. Increase pressure → shifts toward the side with fewer moles of gas

      1. in the reaction above, would shift right

    2. Decrease pressure → shifts toward the side with more moles of gas

      1. in the reaction above, would shift left

    3. If both sides have equal moles of gas → no shift

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Change in Temperature

1N2(g) + 3H2(g) →/← 2NH3(g) + 92 KJ

if heat is a product, it is exothermic (heat is produced) [like in the reaction above]

if heat is a reactant, it is endothermic (heat is required)

for exothermic:

  1. If you add heat, it shifts left

  2. If you remove heat, it shifts right

for endothermic:

  1. if you add heat, it shifts right

  2. if you remove heat, it shifts left

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ICE Charts

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Approximation Method

First, check that the K value is E-3 or smaller

If that is true, you can ignore subtracting the x from the reactants at equillibrium

Then, calculate x

Lastly, use this formula to check

x / |initial| *100% < 5%