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define an isotope
isotopes are atoms of the same element with the same number of protons AND electrons but different number of neutrons
describe basic atomic structure (sub atomic particles, their relative charge and mass)
atoms are made of sub- atomic particles- protons, neutrons and electrons
electrons orbit the nucleus in orbitals (regiosn around the nucleus which take up most of the volume of the atom)- relative mass is 1/2000 or 1/1836. relative charge is -1
protons and neutrons are located in the nucleus. Nucleus makes up most of the mass. protons relative charge- +1, relative mass- 1. neutrons relative charge- 0, relative mass- 1.
what is the ‘A’ symbol
mass number- number of protons and neutrons in the nucleus
what is the ‘Z’ symbol
atomic number - the number of protons in the nucleus
also the number of electrons but ONLY in neutral atoms
different isotopes of an element have the same ‘what’ number but a differet ‘what’ number
different mass number, but the same atomic number
define an ion
an ion is a charged atom - one that has lost or gained electrons.
negative ions have more electrons than protons
positive ions have more protons than electrons
define relative atomic mass
relative atomic mass, Ar, is the weighted mean mass of an atom of an element compared with 1/12 mass of carbon-12
RAM takes into account the isotopes present in a sample of an element and the relative abundance of the isotopes
relative atmic mass is an average- so usually not a whole number
how can relative atomic mass be calculated
using mass spectrometry- a mass spectrum is obtained- showing the isotopes present in a sample and their abundances. The positive ions of isotopes are shown as a mass/charge ratio, m/z. Provided that the ionic charge is +1, m/z is the same as the mass of the ion.the relative abundances show the different proportions of each isotope in the sample.
how can the relative atomic mass be calculated as a weighted mean mass
(mass no x abundance)+ (mass no x abundance) all /100
define relative isotopic mass
the mass of an atom of an isotope of an element compared with 1/12 of the mass of an atom of carbon-12
define relative formula mass
the average mass of a formula unit, compared to 1/12 of the mass of an atom of carbon-12.
it’s used for giant ionic/ covalent compounds
to find the relative formula mass just add up the Ar of all the ions in the formula unit
define relative molecular mass
the average mass of a molecule compared to 1/12 of the mass of an atom of carbon-12
used for ismple molecular compounds eg ethene
to find the relative molecular mass, just add up the Ar values of all the atoms in the molecule
USES THE SYMBOL Mr
recall the formula for nitrate and carbonate
NO(3-) and CO*3(2-)
recall the formula for sulfate, hydroxide and ammonium ions
SO*4(2-) and OH(-) and NH*4(+)
recall the formula for zinc and silver ions
Zn (2+) and Ag(+)
describe the steps of writing an ionic equation
write the formula of the reactants and the products in an unbalenced reaction and WRITE STATE SYMBOLS
balence the equation
write out all of the ions present, only split up (aq)
remember to take in account stoichiometry
cancel out spectator ions
leaving you with your ionic equation
define dissacociation
the process of splitting ionic compounds into their respective ions
why do we use carbon-12 as a standard for measuring relatie atomic masses (off spec- only for understanding)
Carbon-12 is chosen as the standard for atomic mass due to its stability, abundance, and the fact that its atomic mass is defined as exactly 12 atomic mass units (amu), making it a reliable reference point for measuring other elements.
one mole of a substance contains the same number of particles as there are atoms in exactly ‘-’g of ‘-’
12g of carbon-12
name avodagros constant
6.022 × 10²³ mol^-1 - the number of particles per mol of particles
define molar mass or Mr and units
Molar mass is the mass in grams of 1 mole of a substance and is given the unit of g mol-1
define ammount of a substance
Amount of substance refers to the quantity used to count particles in a substance
It is represented by the symbol n in equations
The unit of amount of substance is the mole (mol)
give the formula for an ammount of a substance/ aka mol equation
ammount,n,= mass,m/molar mass,M or mol= mass/RAM
what is the molar mass the same as (ie what other labels)
same as relative atomic mass, relative formular mass, relative molecular mass
how to calculate the number of particles
by multiplying the ammount in moles by the avogadros constant
ie number of particles = n(mol) x 6.02 × 10²³
Np = n x A
define molar gas volume
This is the volume of 1 mole of a gas at a given temperature and pressure.
All gases have this same volume. At room pressure (1atm) and room temperature 25oC
the molar gas volume is 24 dm3 mol–
how many mg in one gram
1000 mg =1g
how many g in 1kg
1000 g =1kg
how many kg in one tonne
1000kg = 1 tonne
equation for molar gas volume
vol= mol x 24 v= n x Vm
n = number of moles of gas (mol)
V = volume of gas (dm3)
Vm = molar volume (dm3 mol-1) - 24dm³ mol-1
define empirical formula
the SIMPLEST whole number ratio of atoms of each element present in the compound- eg molecular formula of butane is C4H10 however this can be simplified to C2H5
define molecular formula
the number and TYPE of atoms in each element in a molecule eg empirical formula of butane is C2H5, molecular formula is C4H10
steps to calulate empirical formula
can be calculated from the percentage composition, by mass or mass of the elements in the compound
find the mass and RAM then CALCULATE MOLES
using the moles, find the smallest value and divide all other values by this
you should have near whole numbers, if not then must scale up to simplest whole number ratio
what is the Mr symbol
relative molecular mass
what are amu/u units for
atomic masses
what is the Ar symbol
relative atomic mass
define atomic number and mass number
number of protons/electrons (only neutral atoms) ATOMIC NUMBER
number of protons and neutrons- MASS NUMBER
ammonia and ammonium
NH3 and NH4^+
how to calculate molecular formulae
only found if the empirical formula and the relative molecular mass are known
find the relative molecular mass (Mr)
find the empirical formula mass
Molecular mass/empirical formula mass to find a scale factor
then multiply the empirical formula values by the scale factor to find the molecular formula
define a hydrated salt
a hydrated compound is crystalline and contains water molecules
define anhydrous salt
an anhydrous salt has no water molcules from crystallisation
define water of crystallisation
refers to the water molecules that are bonded into the crystalline structure of a hydrated compound
in the formul, the ammount of water is shown after a dot
A compound has an empirical formula of CH and a molar mass of 78.0 g mol-1.
Determine its molecular formula.
Step 1: Calculate empirical formula mass
C: 12.0 g mol-1
H: 1.0 g mol-1
Empirical formula mass = 12.0 + 1.0 = 13.0 g mol-1
Step 2: Divide molecular mass by empirical formula mass
Step 3: Determine the number of empirical units per molecule
The compound contains 6 empirical units per molecule.
Step 4: Write the molecular formula
The molecular formula is C6H6.
name the following: CuSO4(s) and CuSO4 . 5H2O (s)
anhydrous copper (II) sulfate and hydrated copper (II) sulfate
hydrated copper (II) sulfate contains 5 moles of water of crystallisation per mole of the hydrated salt.
The formula of a hydrated ionic compound can be experimentally determined from the mass loss on heating using the following steps:
Heat the hydrated salt to remove water, leaving anhydrous salt.
Calculate moles of water lost and anhydrous salt remaining. - via mass measure
+ Mr
Find the mole ratio of salt to water.
Express this ratio in the formula as a whole number.
describe steps for heating to a constant mass
use this to check that the water of crystallisation has been fully removed
the hydrated salt is heated and weighed
the salt is heated again and reweighed
continue until the mass no longer changes
you can then assume all of the water of crystallisation has been removed
Calculate the formula of a hydrated magnesium sulfate, MgSO4•xH2O, given that heating 24.6 g of the hydrated salt leaves 12.0 g of anhydrous MgSO4.
Step 1: Calculate mass of water lost
Mass of water lost = Initial mass Final mass = 24.6 - 12.0 = 12.6 g
Step 2: Calculate moles of anhydrous MgSO4
mass/Mr 12/120.3 = 0.100 mol
Step 3: Calculate moles of water lost
mass/Mr 12.6/18 -=0.700 mol
Step 4: Determine the simplest H2O : MgSO4 mole ratio
H2O : MgSO4 = 0.700 : 0.100 = 7 : 1
x = 7
Step 5: Write the molecular formula
The molecular formula is MgSO4•7H2O.
describe why different isotopes of the same element react in the same way (2)
neutrons have no impact on the chemical reactivity
reactions only involve electrons, yet isotopes have the same number of electrons in the same arangement
how to calculate numer of neutrons
mass number - atomic number
what charge do ionic compounds have overall
neutral
what does (aq) mean
aqueous/ dissolved in water
under what circumstances does a percipitation reaction occur (understanding only)
two solutions containing ions are mixed to form as percipitate
what units does relative atomic mass use
none
the relative isotopic mass is the same as which number
mass number
what two assumptions are made when calculating mass number
contribution of the electron is neglected
mass of both proton and neutron is taken as 1.0 u
uses of mass spectrometry
identify unknown compounds
find relative abundance of each isotope of an element
determine structural infomation
simple explanation of how a mass spectrometer works
the sample is made into positive ions
pass through the apparatus and are seperated according to mass to charge ratio
a computer will analyse the data and produces the mass spectrum
how is the group number related to the number of electrons
group number = number of electrons in the outer shell
what are molecular ions
covalently bonded atoms that lose or gain electrons
what is the equation for concentation and define the two ways of measuring concentration
conc = mol / vol
volume is in dm³
1000cm³ = 1 dm³
concentration is the ammount in mol of dissolved substance in 1.00 dm³ of solution
units is mol dm^-3
alternative way is the mass of dissolved substance in grams of 1 dm³ of solution. This ‘mass concentration has the units of g dm^-3
define molar gas volume and what happens to this value when temp increases or decreases
molar gas volume is the volume per mole of as gas at a stated temp and pressure
molar gas vol increases as temp increases
molar gas volume decreases as temp decreases
at room temp and pressure (RTP), 1.00 mol of any gas occupies a vol of ‘-’ and has a molar gas vol of ‘-’
24 dm ³ and 24dm³ mol^-1
the gas doesnt matter- 1 mol of any mass occupies 24 dm ³ at RTP - although the number of moles and volume are the same, the masses are different and the gases have different densities
what is the ideal gas equation and give all the units
pV= nRT
p = pressure in Pa
V= volume in m³
n = ammount (in mol)
R = gas constant (given)= 8.314 J mol^-1 K^-1
T = temperature (in K)
convert the units: 1kPa to Pa
1000Pa
convert C to kelvin
to convert to Kelvin, add 273
convert cm³ to metres cubed
1cm³ = 10^-6 m³ or 0.000001
convert cm³ to dm³
1cm³ = 0.001 dm ³
convert dm³ to metres³
1 dm³= 0.001m³ or 1 × 10^-3
1dm³ is the same as how many cm³ and how many litres
1000cm³ and 1 litre
what do balencing numbers show
the ratio of the moles invloved in the chemical reaction. This ratio is called stoichiometry
how to calculate atom economy
the percentage proportion of reactants that are converted into useful products - indicating efficiency
atom economy = sum of molar masses desired product / sum of molar masses of all products x 100
or RFM desired/ RFM total x100
ALWAYS BALENCE EQUATION
Calculate the atom economy for the production of ethanol (C2H5OH) from the fermentation of glucose (C6H12O6). The balanced chemical equation is:
C6H12O6 ➔ 2C2H5OH + 2CO2
Step 1: Calculate Mr of desired product
Mr of C2H5OH = 2(12.0) + 6(1.0) + 16.0 = 46.0
Step 2: Multiply by reaction stoichiometry
Since the equation produces 2 moles of C2H5OH the total Mr for C2H5OH = 2 × 46.0 = 92.0
Step 2: Calculate ΣMr of all reactants
Mr of C6H12O6 = 6(12.0) + 12(1.0) + 6(16.0) = 180.0
Step 4: Equation
% atom economy = Mr desired products/ Mr of all reactants x100
Step 5: Substitution and correct evaluation
92/ 180 ×100 = 51.1
This calculation shows that 51.1% of the reactant atoms are incorporated into the desired product, indicating a moderate atom economy for this reaction
why is the atom economy of additon reactions always 100%
because there is a single product
why is the atom economy of substitution reactions always less than 100
%
In a substitution reaction, some atoms are substituted between reactants, generating at least two products - the desired product and an unavoidable by-product. For example, chloromethane reacts with potassium hydroxide in a substitution reaction:
CH3Cl + KOH ➔ CH3OH + KCl
Here the desired product is methanol, but potassium chloride is also produced as waste. The atom economy will be less than 100%.
name 3 reasons regarding the enviro importance of a high atom economy
Reactions with higher atom economies are more sustainable and better for the environment because:
Less waste is generated, reducing disposal impacts.
Raw materials are used more efficiently, preserving limited resources.
Less energy intensive conditions are often required.
name 3 reasons regarding the econ importance of a high atom economy
Economic: High atom economy also has financial advantages:
Reduced costs for separating products from waste.
Lower raw material demands decrease expenses.
Energy costs for heating and pressurising reactions are minimised.
give the equation for percentage yield and definition
The theoretical yield of a chemical reaction is the maximum mass of product that could be produced, assuming the reaction goes to completion with no loss of product.
% yield = actual yield / predicted yield x100
how to calculate theoretical yield
To calculate the theoretical yield, follow these steps:
Use a balanced chemical equation to find the mole ratio between reactants and products.
Calculate the moles of the limiting reagent present.
Determine the mass of product that these moles of limiting reagent could produce, using the mole ratio.
For example, in the reaction:
C2H5OH + [O] ➔ CH3CHO + H2O
The C2H5OH : CH3CHO mole ratio is 1 : 1.
So if 0.300 mol (13.8 g) of C2H5OH is present and [O] is in excess, the theoretical yield of CH3CHO is 0.300 mol (13.2 g).
5 reasons why the actual yield is always less than the predicted
The actual yield is always lower than the theoretical yield because of several factors:
reaction may be at equilibrium
reactants may be impure
side reactions could occur
reactants or products may be left on apparatus/ when transferring
loss of products during separation and purification
state avogadros law
under the same temp and pressure, one mole of any gas would occupy the same volume
name the ideal ways in which gases behave (5)
they are in continuous motion
no intermolecular forces experienced
exert pressure when they collide with another or the container
no kinetic energy is lost in collisions
when temp increases, kinetic energy of the gases also increases
(not sure if need to know) 1 atmos pressure is equal to how many pascal
1 atm= 101325 Pa
does 100% yield mean 100% atom economy
no because even if all the reactants are converted into products, not all the products of the reaction will be the required products
define element
a group of atoms which have the same number of protons