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What are the differences between these two sine waves?
-amplitude and therefore intensity?
-frequency therefore resolution and penetration are different too
-wavelength
-period
What’s the similarities between these two sine waves? How are they different?
-amplitude is the same
-frequency is the same
-period is the same
-they are out of phase with each other. If they are added together the net result is zero
The ultrasound beam is created by _______ each emitted from their own source.
-many waves
The point sources of ultrasound waves are called _____ _______.
-Huygens’ sources
The _____ in a probe is the Hugens’ Source.
-crystals
Each wave emitted from Huygens’ sources are referred to as ______ ______.
-Huygen’s wavelets
The divergence of the wavelets depends on the _____ of the source.
-size
What was the analogy for wavelets divergence?
-throwing a small pebble into a body of water. Small ripples will travel quickly
-throwing a large log into a body of water. This will make a big splash but the waves won’t travel as quickly as the ripples do
The spreading of the beam as it travels from the source is referred to as ______.
-divergence
The ______ the source of sound the less divergence there is.
-larger
-think of pebble vs log analogy
What occurs after a beam with planar wave fronts passes through a small aperture (opening)?
-diffraction
Are divergence and diffraction the same?
-no
Are divergence and diffraction the same?
-no
How would you define Huygen’s Principle?
-each point source creates its own sound wave/beam
-multiple wavelets from many sources form a new wave-front
-little waves will interfere and create a new wave front
How is Hugens’ Principle related to the design of probes?
-probes have an array of crystals mounted on the transducer face
-each crystal emits its own wavelets, and they all add together to create a larger beam (wavefront)
What does interference refer to?
-when 2 or more waves interact. Adds the motion of one wave to the other
What are the 2 types of interference?
1) Constructive
2) Destructive
What kind of beams are the best for getting through the body tissues so we can differentiate structures the best?
-short skinny beams (Skinny legends)
When two waves are _____, this results in constructive interference.
-in phase
During constructive interference the contributions of each wave result in an ______ in amplitude and intensity.
-increase
During destructive interference, the contributions of each wave results in a _______ in amplitude and intensity.
-decrease
When two waves are ______, this results in destructive interference.
-out of phase
What is the result of two out of phase waves with the same amplitudes?
-cancel out so net result is zero
What is the result of two waves that are neither in or out of phase? This is how ______ signals are detected in ultrasound.
-beat frequency
-Doppler
What is responsible for the natural focusing of the beam?
-interference
These types of waves occur when two waves propagate in the same medium but in opposite directions. What happens when they are added together?
-standing waves
-certain points the amplitude is zero, at other points the amplitude is doubled
The weakening of sound as it travels is referred to _______.
-attenuation
How can attenuation affect our image?
1) limits our imaging depth
2) Must be compensated for (TGCs)
3) Can be useful in diagnosis
The ____ and _____ are relative units of measurement expressing the loudness (intensity level) of sound waves.
-bel (B)
-decibel (dB)
1 Bel is = to how many dB?
-10 dB
Hearing threshold is = to how many dB?
-0
A whisper is = to how many dB?
-30
Normal conversation is = to how many dB?
-60
A lawn mower is = to how many dB?
-90
A concert is = to how many dB?
-115
Pain is = to how many dB?
-130
The ____ uses dB to express the number of shades of gray displayed on the monitor.
-dynamic range
Another way to describe dynamic range is the?
-amount of contrast
-the higher the dynamic range the more black and white the image will be
What 2 parameters use decibels to express the amount of amplification required to optimize the returning echoes?
-TGC and gain
What is the forumla to calculate Bels?
Bel = log(newi/originali)
Since 1 Bel = 10 dB how can we rewrite the Bel formula?
dB = 10log (newi/originali)
What else can the Bel/decibel formula be used to describe?
-power and voltage
What is the formula to calculate power by using dB?
-dB = 10log (newP/originalP)
What is the formula to calculate voltage by using dB?
- dB = 20log (newV/originalV)
What do we need to remember to change when using the power/voltage dB equation?
-it is 10log for power and 20log for voltage
A __ dB drop is = to 1/2 the original intensity.
-3dB
A ___ dB drop is = to 0.1 of the original intensity.
-10dB
If the power is at 100% (100W), what is the dB = to?
-0dB
If the power is at 50W, what is the dB = to? Keep in mind 100W is = to 0dB.
- Negative 3dB
The power output of an amplifier is 100mW while the input power is 0.1 mW, what is the amplifier gain in decibels?
dB = 10 log(NewP/OriginalP)
dB = 10log(100mW/0.1mW)
dB = 10log(1000)
dB = 10(3)
dB = 30
An electric attenuator has a power output of 0.01mW with an input power of 100mW. What is the attenuation in decibels?
dB = 10log(NewP/OriginalP)
dB = 10log (0.01mW/100mW)
dB = 10log (0.0001)
dB = 10(-4)
dB = -40
The amount of attenuation that occurs with each one-centimeter travels is known as the _______.
-attenuation coefficient
In soft tissue there is _____ of attenuation for every 1 cm travelled per 1MHz. Therefore, in soft tissue the attenuation coefficient is = to _______.
-0.5dB
-1/2frequency
What is the formula to calculate the total attenuation?
- Tatt = Att. Coef. X Path length (cm)
What is the formula for total attenuation in soft tissue?
- Tatt = 1/2f x path length (cm)
Calculate the decibel loss back at the probe for a 2.5 MHz ultrasound beam imaging to a depth of 6cm in soft tissue.
TAtt = ½ f x path length (cm)
Tatt = ½ (2.5MHz) x 12 cm
Tatt = 1.25MHz x 12 cm
Tatt = 15 dB
Now plug -15dB into dB = 10log(Inew/IOG)
-15 dB = 10 log(Inew/100mW/cm2)
-1.5 dB = log (Inew/100)
0.032 = Inew/100
3.2 mW/cm2 = Inew
Calculate the intensity back at the probe for a 3 MHz ultrasound beam imaging to a depth of 5 cm in soft tissue and an original intensity of 50 mW/cm2.
Tatt =½ f x path length (cm)
Tatt = ½ (3 MHz) x 10 cm
Tatt = 1.5MHz x 10 cm
Tatt = 15 dB
Now plug -15dB into dB = 10log(Inew/IOG)
-15 dB = 10 log(Inew/50mW/cm2)
-1.5 dB = log (Inew/50)
0.032 = Inew/50
1.6 mW/cm2 = Inew
The distance sound must travel in a material to reduce the intensity to half its original value is known as the ___________.
-half-value layer
The half-value layer is = to how many dB?
-3dB
What can vary attenuation?
-nature of the tissue (dead or alive)
-frequency
-depth
What are 5 reasons we have attenuation? hint: WARRS
1)absorption
2)reflection
3)refraction
4)scatter
5)wave-front divergence
The conversion of sound energy to heat and is the dominant factor in attenuation accounting for approximately 80% is known as _______.
-absorption
What are 3 factors that effect absorption?
1)viscosity
2)relaxation time on molecules
3)frequency
The ease in which molecules can slide past one another is _______.
-viscosity
Increased viscosity provides greater ______, more _____ and therefore increased _______.
-resistance
friction
-attenuation
_____ is how sound energy is converted to heat.
-friction
When a mechanical force is applied to a molecule it will vibrate. The time it takes to come to rest is the called the _______________.
-relaxation time
What happens if molecules can’t come to rest before the next compression phase? What does this cause?
-more energy us required to reverse its direction.
-heat
Since relaxation time is relatively constant in soft tissues, what is more likely to influence the amount of absorption?
-frequency
If frequency is increased, then there is ____ time available for molecules to recover during the relaxation phase. What is the result?
-less
-more absorption
What are the 2 types of reflection?
1)specular
2)non-specular
When a sound beam hits a large, smooth surface this is referred to as ________.
-specular reflection
What is a good example of a specular reflector?
-the diaphragm
The intensity of the reflected sound depends on 2 things:
1)angle of incidence
2)acoustic impedance (stopping) of two media
The angle of incidence will equal the ________.
-angle of reflection
When would a reflection potentially not return to the probe?
-when reflections of sound have non-perpendicular incidence
What helps improve reflection?
-perpendicular incidence
How fast sound moves through a medium will depend on the medium’s ____ and ____.
-density
-stiffness
Acoustic impedance is also known as _______.
-characteristic impedance
Characteristic Impedance describes the relationship between _______ and the speed of particle vibrations in a sound wave (Speed propagation).
-acoustic pressure
What is the formula for impedance?
impedance (Z) = density (p) x velocity (c)
What are the units of impedance?
-Rayls (Z)
Z _______ with increasing density/velocity.
-increases
The larger the Z value difference at the interface of 2 media the _____ the reflection.
-bigger
The amount of sound that reflects at an interface is called the ________.
-intensity reflection coefficient (IRC)
How can we calculate the IRC?
IRC = reflected intensity (Ir)/Incident intensity (Ii)
Or
IRC = (Z2-Z1/Z2+Z1)2
If we know the amount of sound that is reflected then we can calculate the amount ______. This is known as the _____________.
-transmitted
-intensity transmission coefficient (ITC)
What’s the formula for ITC?
ITC = 1 – IRC
The more sound reflected, the _____ transmitted.
-less
What happens if the impedance is equal across the interface?
-no reflection will occur
Calculate the amount of sound reflected (IRC) at a bone/soft tissue interface. Bone Z = 7.8 x 10 ^6 Rayls, ST Z= 1.63 x 10^6 Rayls.
IRC = (Z2-Z1/Z2+Z1)2 x 100
IRC = (7.8 x 10 ^6 - 1.63 x 10^6 / 7.8 x 10 ^6 + 1.63 x 10^6)2 x 100
IRC = (6.17/9.43)2 x 100
IRC = 0.42 x 100
IRC = 43% reflected
IF IRC is 43%, calculate the percent of sound transmitted (ITC).
ITC = 1-IRC
ITC = 1 – 0.43
ITC = 0.57 or 57%
Determine the amount of reflected sound (IRC) at an air/ST interface. Air Z = 0.0004 x 10 ^6 Rayls, ST Z= 1.63 x 10^6 Rayls.
IRC = (Z2-Z1/Z2+Z1)2 x 100
IRC = (0.0004 x 10 ^6 - 1.63 x 10^6 / 0.0004 x 10 ^6 + 1.63 x 10^6)2 x 100
IRC = (-1.6296/1.6304)2 x 100
IRC = 0.999x 100
IRC = 99.9% reflected
Why does reflection occur?
-a difference of Z values across an interface
True/False, it is possible for 2 tissues to have different sound velocities but have the same Z value?
-true, this is why we need gel when we look at the reflection from air
What’s the difference between reflection and refraction?
-reflection looked at the sound returning to the probe from an interface
-refraction deals with the sound that is transmitted across the interface
Sound obeys what law?
-Snell’s Law of optics
What is Snell's Law?
Sin θi/ Sin θt = vi/vt
What happens if the velocities across the interface are equal?
- then no refraction will occur (if V1 = V2)
What happens if the velocity of the first medium is greater than the second?
- sound will bend towards the normal (fast to slow, to the normal I go)
- think of car analogy, it turns towards the slower tire