Unit 2 Quiz

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109 Terms

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<p>The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.</p><p>Site of modification and packaging of proteins and lipids prior to export from the cell</p>

The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.

Site of modification and packaging of proteins and lipids prior to export from the cell

C (Golgi apparatus)

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Which of the following is evidence that eukaryotes and prokaryotes share a common ancestor?

All eukaryotes and prokaryotes contain ribosomes.

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Organelles such as mitochondria and the endoplasmic reticulum have membranes that compartmentalize reactions and other metabolic processes. To function properly, the organelles must move substances across their membranes.

Which of the following statements describes a feature shared by mitochondria and the endoplasmic reticulum that increases the efficiency of their basic functions?

They have highly folded membranes.

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All eukaryotic cells contain at least one Golgi complex, typically located in the cytoplasm and near the endoplasmic reticulum.

Which of the following best describes a process that occurs within the Golgi complex?

Enzymatic modification of newly synthesized integral membrane proteins

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Which of the following organelles modifies and packages for secretion the materials produced by the ribosomes?

The Golgi apparatus

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Liver cells manufacture glycoproteins, while adipose cells store fat. Which of the following subcellular structures is likely to be more prominent in liver cells than in adipose cells?

Golgi apparatus

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Contains hydrolytic enzymes associated with the intracellular digestion of macromolecules

Lysosome

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Prokaryotic and eukaryotic cells generally have which of the following features in common?

Ribosomes

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<p>The figure below illustrates a eukaryotic cell. Which of the following best describes how the three structures indicated by the arrows work together?</p>

The figure below illustrates a eukaryotic cell. Which of the following best describes how the three structures indicated by the arrows work together?

To synthesize and isolate proteins for secretion or for use in the cell

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Cells contain smaller components called organelles that are necessary for a cell’s survival. Organelle functions have often been compared to components of larger systems.

Which of the following functional differences between the rough and smooth endoplasmic reticulum (ER) is explained by the structural differences between them?

Rough ER can synthesize and package proteins for export, and smooth ER cannot.

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Which two cellular organelles in eukaryotes have both electron transport systems and chemiosmotic mechanisms?

Chloroplasts and mitochondria

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Which of the following processes is most likely to occur as a result of an animal cell receiving a signal to initiate apoptosis?

Lysosomes will release digestive enzymes into the cytosol.

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<p>The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.</p><p>Site of glucose synthesis</p>

The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.

Site of glucose synthesis

B (Chloroplast)

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The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.

 

The figure shows a three dimensional diagram of a plant cell. A compartment labeled A is a small oval-shaped compartment near the cell membrane. It has an inner membrane that folds over on itself creating a layered structure inside the compartment. Compartment B is a medium-sized oval-shaped compartment filled with small, discreet ovals that are packed tightly and stacked, filling the compartment. There is a dark, round compartment in the cell that is partially surrounded by a maze-like structure with black dots all over the surface. C is a maze-like structure above this structure with no black dots. D is the black line that is the innermost circle surrounding the entire cell. E is a very large circular compartment that takes up about one-third of the cell diagram.

Site of conversion of chemical energy of glucose to ATP


A (Mitochondria)

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A cell is treated with a drug that prevents the formation of new lysosomes. The cell continues to transcribe the genes that code for the hydrolytic enzymes that are normally found in lysosomes and continues to translate the mRNAs for those proteins on membrane-bound ribosomes.

The hydrolytic enzymes are most likely to accumulate in which of the following cellular structures?

Golgi complex

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Which of the following statements is true about the Krebs (citric acid) cycle and the Calvin (light-independent) cycle?

They both are carried out by enzymes located within an organelle matrix.

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Which of the following claims is scientifically accurate and consistent with an observation that a decrease in lysosome production within a cell leads to a decline in mitochondrial activity?

Fewer lysosomes will be available to break down macromolecules to provide the necessary nutrients for cellular respiration.

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The organelle that is a major producer of ATP and is found in both heterotrophs and autotrophs is the

mitochondrion

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Which of the following best explains how the extensive folding of the inner mitochondrial membrane benefits a eukaryotic cell?

It increases the area available for proteins involved in energy transfer.

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Muscle cells have high ATP demands. Which of the following is a scientific claim about how the structure of the mitochondria in muscle cells should be different than it is in other cells because of the high energy demands of mitochondria?


The inner membrane of the mitochondria in muscle cells should have more folds to increase the surface area, allowing more ATP to be synthesized.

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The function of which of the following organelles directly requires oxygen?


Mitochondrion


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For following group of questions first study the description of the situation or data and then choose the one best answer to each question following it and fill in the corresponding oval on the answer sheet.

In the first step of an experiment, rat liver cells were exposed for 5 minutes to amino acids labeled with a radioactive isotope. The cells were then washed to stop any further incorporation of radioactive amino acids. The cells were sampled periodically thereafter, and the radioactivity of a certain protein (protein X) was measured in various cell components, as shown below.

The figure shows a table with 8 columns and 5 rows. The title of the table is Radioactive Counts (Protein X). The top row contains the column labels, from left to right; column one, Sampling Time (minutes); the following seven columns are sub columns under Cell Component. They are; column 2, Endoplasmic Reticulum; column 3, Golgi Apparatus; column 4, Cytoplasm; column 5, Nucleus; column 6, Mitochondria; column 7, Lysosomes; column 8, Extracellular Space. From top to bottom, the data is as follows; Row 2; Sampling Time, 5; Endoplasmic Reticulum, 980; Golgi Apparatus, 20; Cytoplasm, 20; Nucleus, 4;  Mitochondria, 2; Lysosomes, 6; Extracellular Space, 2. Row 3; Sampling Time, 20; Endoplasmic Reticulum, 135; Golgi Apparatus, 760; Cytoplasm, 20; Nucleus, 3;  Mitochondria, 5; Lysosomes, 120; Extracellular Space, 9. Row 4; Sampling Time, 45; Endoplasmic Reticulum, 50; Golgi Apparatus, 195; Cytoplasm, 4; Nucleus, 6;  Mitochondria, 2; Lysosomes, 800; Extracellular Space, 3. Row 5; Sampling Time, 120; Endoplasmic Reticulum, 15; Golgi Apparatus, 30; Cytoplasm, 8; Nucleus, 6;  Mitochondria, 8; Lysosomes, 975; Extracellular Space, 4.

Which of the following correctly shows the order in which protein X moves through the cell?


Endoplasmic reticulumGolgi apparatuslysosomes


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For following group of questions first study the description of the situation or data and then choose the one best answer to each question following it and fill in the corresponding oval on the answer sheet.

In the first step of an experiment, rat liver cells were exposed for 5 minutes to amino acids labeled with a radioactive isotope. The cells were then washed to stop any further incorporation of radioactive amino acids. The cells were sampled periodically thereafter, and the radioactivity of a certain protein (protein X) was measured in various cell components, as shown below.

The figure shows a table with 8 columns and 5 rows. The title of the table is Radioactive Counts (Protein X). The top row contains the column labels, from left to right; column one, Sampling Time (minutes); the following seven columns are sub columns under Cell Component. They are; column 2, Endoplasmic Reticulum; column 3, Golgi Apparatus; column 4, Cytoplasm; column 5, Nucleus; column 6, Mitochondria; column 7, Lysosomes; column 8, Extracellular Space. From top to bottom, the data is as follows; Row 2; Sampling Time, 5; Endoplasmic Reticulum, 980; Golgi Apparatus, 20; Cytoplasm, 20; Nucleus, 4;  Mitochondria, 2; Lysosomes, 6; Extracellular Space, 2. Row 3; Sampling Time, 20; Endoplasmic Reticulum, 135; Golgi Apparatus, 760; Cytoplasm, 20; Nucleus, 3;  Mitochondria, 5; Lysosomes, 120; Extracellular Space, 9. Row 4; Sampling Time, 45; Endoplasmic Reticulum, 50; Golgi Apparatus, 195; Cytoplasm, 4; Nucleus, 6;  Mitochondria, 2; Lysosomes, 800; Extracellular Space, 3. Row 5; Sampling Time, 120; Endoplasmic Reticulum, 15; Golgi Apparatus, 30; Cytoplasm, 8; Nucleus, 6;  Mitochondria, 8; Lysosomes, 975; Extracellular Space, 4.

In graphing the data from this experiment, the sampling time would be shown on the x-axis because


sampling time is the independent variable

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A mutation in the upland cotton plant causes the development of chloroplasts with a single outer membrane and no internal membranes. Which of the following would most likely be observed in chloroplasts of cotton plants with this mutation?


They would be unable to generate the ATP and NADPH needed to make sugars, because these processes occur on membranes within the chloroplast.


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The figure presents a rough endoplasmic reticulum. The left side of the figure is labeled “Y” and three lines connect the label to three dots on the surface of the endoplasmic reticulum.

The figure above represents a rough endoplasmic reticulum. Which of the following best describes the role of the structure labeled Y?


Structure Y is the location where proteins are synthesized.


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Researchers have proposed a model of the process by which a newly synthesized protein is transported to the plasma membrane and secreted into the extracellular space. The model is represented in Figure 1.

Figure 1 presents a diagram of a cell. The following parts are labeled: nucleus, endoplasmic reticulum, ribosomes, cytosol, and new protein in transport vesicle. The transport vesicle containing a new protein is shown in two positions: a start point and an end point. It starts out adjacent to the endoplasmic reticulum, and an arrow is drawn upward from the transport vesicle toward an unlabeled component. The unlabeled component appears to be a series of stacked flat sacs. A second arrow is drawn upward from this unlabeled component toward the plasma membrane, where the transport vesicle with new protein is shown at its end point just inside the plasma membrane.

Figure 1. A model of the intracellular transport of a newly synthesized secreted protein

Based on the model, the newly synthesized protein is transported directly from the endoplasmic reticulum to which of the following?


The Golgi complex

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The figure shows a table with 2 columns and 5 rows. The top row contains the column labels, from left to right; column 1, Cellular Shape; column 2, Ratio of Surface Area to Volume. From top to bottom the data is as follows; Row 2; Cellular Shape, Cube; Ratio of Surface Area to Volume, 1.7. Row 3; Cellular Shape, Regular Tetrahedron; Ratio of Surface Area to Volume, 0.5. Row 4; Cellular Shape, Cylinder; Ratio of Surface Area to Volume, 0.9. Row 5; Cellular Shape, Sphere; Ratio of Surface Area to Volume, 0.6.

In an experiment, the efficiency of oxygen exchange across the plasma membrane is being assessed in four artificial red blood cells. The table above lists some properties of those artificial cells. Other conditions being equal, which artificial cell is predicted to be the most efficient in exchanging oxygen with the environment by diffusion?

The cuboidal cell


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A student peeled the skins from grapes, exposing cells with membranes that are only permeable to water and small diffusible solutes. The student measured the mass of the peeled grapes. The student then placed each peeled grape into one of five solutions. After 24 hours, the student removed the peeled grapes from the solutions, measured their final mass, and calculated the percent change in mass (Table 1).

TABLE 1. PERCENT CHANGE IN MASS OF PEELED GRAPES IN SOLUTIONS

Solution

Concentration of Solution(weight/volume)

Percent Change in Mass

Distilled water

0%

   13.48%

NaCl

20%

−23.39%

Tap water

0.8%

    9.46%

Grape juice

2.1%

    2.8%

Grape soda

13%

−15.00%

In a second experiment (Table 2), the student placed a peeled grape into a solution containing both small diffusible solutes and solutes to which the membrane is impermeable (nondiffusible solutes).

TABLE 2. CONCENTRATION OF SOLUTES IN SECOND EXPERIMENT

Location

Concentration of Small Diffusible Solutes

Concentration of Nondiffusible Solutes

Inside grape

0.4⁢M

1.2M

In solution

1.6M

0.8M

Which of the following best explains why larger grapes have a different rate of water absorption per gram of mass than smaller grapes do?


The rate is slower because smaller grapes have a larger surface-area-to-volume ratio than the larger grapes do.


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Researchers propose a model to explain variation in phytoplankton cell sizes in a marine environment. They base their model on the idea that smaller cells absorb nutrients more efficiently. The researchers predict that the mean diameter of phytoplankton cells will change by 50 micrometers for every 5-kilometer increase in distance from the shore because of a gradual decrease in nutrient availability. To test their model, the researchers determine that the phytoplankton cells found closest to shore have a mean diameter of 900 micrometers.

Based on the model, what will be the mean diameter of the phytoplankton cells that are found 25 kilometers from shore?


650 micrometers


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Simple cuboidal epithelial cells line the ducts of certain human exocrine glands. Various materials are transported into or out of the cells by diffusion. (The formula for the surface area of a cube is 6 X S2, and the formula for the volume of a cube is S3, where S = the length of a side of the cube.)

Which of the following cube-shaped cells would be most efficient in removing waste by diffusion?


A cube with side length of 10 micrometers.

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The primary function of the kidney is to exchange molecules across a membrane between the blood and the urine. One type of kidney cell has a basic rectangular shape, except for a single surface, which is lined with tiny, finger-like projections that extend into the surrounding extracellular space.

Which of the following best explains the advantage these projections provide the cell?


The projections increase the surface area–to-volume ratio of the cell, which allows for more efficient nutrient exchange with the environment.


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A spherical bacterial cell has a radius of 3�m. The human egg cell has a radius of 100�m.

Which statement correctly indicates the cell that is able to more efficiently exchange materials with the external environment and provides a correct explanation?


The bacterial cell, because it has the largest surface-to-volume ratio.


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A student calculated the average surface area-to-volume ratio of four different types of human epithelial cells. The results are shown in the table below.

Cell Type

Surface Area-to-Volume Ratio

Simple squamous

9

Simple cuboidal

6

Simple columnar

4

Simple spherical

3

Based on the data, which type of cell would be best suited for the lining the alveoli of the lungs, where diffusion of carbon dioxide and oxygen must occur very rapidly?


Simple squamous cells


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Two different models of a living cell are represented in the figure.

The figure presents three-dimensional models of cell A and cell B. Cell A is a rectangular solid with height 25 micrometers, width 6 micrometers, and length 4 micrometers. Cell B is a cylinder with height 25 micrometers and radius 3 micrometers.

Of the two cells represented in the figure, which would likely be more efficient at exchanging substances with the surrounding environment?


Cell A, because it has the larger surface-area-to-volume ratio.


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Which of the following describes the most likely location of cholesterol in an animal cell?


Embedded in the plasma membrane


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The figure shows a diagram of a portion of a phospholipid bilayer. The upper, middle, and lower areas of the bilayer are labeled 1, 2, and 3, respectively. Areas 1 and 3 show the heads of the phospholipids adjacent to water molecules. Area 2 shows the fatty acid tails of the phospholipids, pointing to the center of the membrane, away from the phospholipid heads at the membrane surfaces.

Which of the following best describes the numbered areas?


Areas 1 and 3 are polar, since the membrane molecules are aligned with water molecules.


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The model below shows the structure of a portion of a plasma membrane in an animal cell.

The model shows the structure of a portion of a plasma membrane in an animal cell. None of the parts are labeled, but the model includes a phospholipid bilayer that contains some embedded proteins. The phospholipids are arranged with their heads oriented toward the external and internal membrane surfaces and their fatty acid tails oriented toward the center of the membrane.

Which statement best explains the orientation of the phospholipid molecules in this model?


The hydrophilic phosphate groups of the phospholipid molecules are attracted to the aqueous internal and external environments.


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A model of the plasma membrane showing several biological molecules, including a transmembrane protein, is shown in Figure 1.

The figure shows a diagram of a phospholipid bilayer with an embedded transmembrane protein. The protein is coiled into a helical shape where it is buried between the membrane lipids. Polar areas of the protein are labeled on the portions of the protein that stick out from the two membrane surfaces. Nonpolar areas of the protein are labeled on the coiled portion that is buried between the membrane lipids.

Figure 1. Phospholipid bilayer with transmembrane protein

Which statement best explains why correct protein folding is critical in the transmembrane protein shown above?


Interactions of the hydrophobic and hydrophilic amino acids help to anchor the protein in the membrane.


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Aquaporins are channel proteins that facilitate the transport of water across the cell membrane. One group of researchers hypothesizes that without functional aquaporins, no water will be able to enter the cell. A different group proposes an alternative hypothesis, stating that even with nonfunctional aquaporins, a small amount of water will still cross the cell membrane. An experiment is set up in which plant cells with mutated (nonfunctional) aquaporins and plant cells with normally functioning aquaporins are both placed in distilled water.

Which of the following data would support the alternative hypothesis?


Cells with mutated aquaporins exhibit moderate turgor pressure and are hypertonic.


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Plant cell walls are composed of cellulose, while fungal cell walls are composed of chitin. A group of scientists hypothesize that this difference means the cell wall has largely different functions in plant cells and fungal cells. Alternatively, another group of scientists hypothesize that despite their biochemical differences, plant and fungal cell walls serve similar functions.

Which of the following observations would best support the alternative hypothesis described above?


In both plant cells and fungal cells, the cell wall surrounds the outside of the cell membrane.


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The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.

 

The figure shows a three dimensional diagram of a plant cell. A compartment labeled A is a small oval-shaped compartment near the cell membrane. It has an inner membrane that folds over on itself creating a layered structure inside the compartment. Compartment B is a medium-sized oval-shaped compartment filled with small, discreet ovals that are packed tightly and stacked, filling the compartment. There is a dark, round compartment in the cell that is partially surrounded by a maze-like structure with black dots all over the surface. C is a maze-like structure above this structure with no black dots. D is the black line that is the innermost circle surrounding the entire cell. E is a very large circular compartment that takes up about one-third of the cell diagram.

Site of transport of materials into and out of the cell


D (Cell membrane)

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Carbon dioxide most likely enters a cell through which of the following processes?


Simple diffusion through the membrane


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Certain chemicals, including sodium fluoride (NaF), are capable of inhibiting specific steps of glycolysis. Figure 1 shows the steps of the glycolysis pathway, indicating where various macromolecules enter the pathway as well as the specific reaction inhibited by NaF.

The figure shows key steps in the metabolic pathway of glucose. An arrow indicates that glucose enters a cell by crossing the cell membrane through a Glucose Transporter. A series of straight arrows indicate the steps in the pathway, starting with Glucose and ending with the Krebs Cycle. Curved arrows adjacent to some of the straight arrows indicate other reactions that occur simultaneously with the reactions indicated by the straight arrows. Starting with Glucose, an arrow points to Glucose-6-phosphate, and an adjacent curved arrow points from A T P to A D P.  An arrow points from Glucose-6-phosphate to Fructose-6-phosphate. An arrow points from Fructose-6-phosphate to Fructose-1,6-diphosphate, and an adjacent curved arrow points from A T P to A D P. Another arrow labeled Phosphofructokinase points to the arrow between Fructose-6-phosphate and Fructose-1,6-diphosphate. An arrow points from Fructose-1,6-diphosphate to Two Glyceraldehyde-3-phosphate. An arrow points from Two Glyceraldehyde-3-phosphate to Two 1,3-Diphosphoglycerate, and an adjacent curved arrow points from 2 N A D with a positive 1 charge to 2 N A D H. An arrow points from Two 1,3-Diphosphoglycerate to Two 3-Phosphoglycerate, and an adjacent curved arrow points from 2 A D P to 2 A T P. An arrow points from Two 3-Phosphoglycerate to Two 2-Phosphoglycerate. An arrow points from Two 2-Phosphoglycerate to Two Phosphoenolpyruvate, and a dashed arrow labeled “Na F Inhibits” points to this arrow between Two 2-Phosphoglycerate and Two Phosphoenolpyruvate. An arrow points from Two Phosphoenolpyruvate to Pyruvate, and an adjacent curved arrow points from 2 A D P to 2 A T P. An arrow labeled “Amino Acids Enter Here” points to the arrow between Two Phosphoenolpyruvate and Pyruvate. An arrow points from Pyruvate to Acetyl Co A, and an arrow labeled “Amino Acids and Fatty Acids Enter Here” points to the arrow between Pyruvate and Acetyl Co A. A final arrow points from Acetyl Co A  to Krebs Cycle.

Figure 1. Key steps in the metabolic pathway of glucose

Which of the following describes why a glucose transporter is needed to move glucose into the cell?


Glucose is large and polar and cannot pass through the phospholipid bilayer.


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Which of the following best explains how the phospholipid bilayer of a transport vesicle contributes to cellular functions?


The phospholipid bilayer allows the vesicle to fuse with the Golgi apparatus and the plasma membrane, allowing the exocytosis of proteins.


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Which of the following best explains how molecules such as O2 and CO2 can move across the membrane of a cell?


The majority of the cell membrane is nonpolar, which allows small, nonpolar molecules to freely cross.


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Which of the following statements is true regarding the movement of substances across cell membranes?


Ions are unable to move through the phospholipid bilayer because the nonpolar tail regions of the phospholipids are hydrophobic.


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A team of biologists develop a new drug, and one team member hypothesizes that the drug is incapable of freely passing across the plasma membrane and requires the help of membrane proteins to enter cells. Alternatively, another biologist on the team hypothesizes that the drug can diffuse passively across the plasma membrane like O2 and CO2 can.

Which of the following, if true about the drug, best supports the alternative hypothesis that the new drug will exhibit simple diffusion across plasma membranes?


The drug is a small nonpolar molecule.


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A table titled Effect of Water-Soluble Pollutants On Membrane Permeability is shown. The table has 4 columns and 5 rows. The first column is labeled Treatment Group. The second column is labeled Treatment Solution, which Concentrations are reported as percent by volume. The third column is labeled Mean Absorbance of 460 nm Light (n = 5), and the fourth column is labeled 2 times Standard Error of the Mean (2 times S E M). The rows read from left to right. The first row reads, Temperature group 1, 70% isopropanol; 30% water, 0.164, 0.032. The second row reads, Temperature group 2, 90% isopropanol; 10% water, 0.125, 0.100. The third row reads, Temperature group 3, 50% acetone; 50% water, 0.215, 0.034. The fourth row reads, Temperature group 4, 70% acetone; 30% water, 0.274, 0.018. The fifth row reads, Temperature group 5, 100% water, 0.095, 0.004.

A student formulated a hypothesis that water-soluble pollutants damage living organisms by increasing the permeability of cellular membranes. To test the hypothesis, the student investigated the effect of isopropanol and acetone on beet root cells. The vacuoles of beet root cells contain large amounts of betacyanin, a water-soluble pigment that is released into the extracellular environment as a result of increased membrane permeability.

The student prepared identical samples of beet root tissue and incubated each sample for 15 minutes in the specific solution for that group. At the end of the incubation period, the student measured the absorbance of 460 nm light for each sample. A greater concentration of betacyanin in the solution surrounding the beet root cells results in a greater absorbance of 460 nm light. The results of the experiment are shown in the table above.

Which of the following graphs is the most appropriate representation of the experimental data?


The figure shows a bar graph in the first quadrant. The horizontal axis is labeled Treatment Group and the vertical axis is labeled Absorbance of 460 nanometer light. Five vertical shaded bars appear on the graph and are labeled, from left to right One, Two, Three, Four, and Five. Seven numbers appear on the vertical axis and are labeled, from bottom to top, zero point zero zero through zero point three zero zero, in increments of zero point zero five zero. The top of each shaded bar has a vertical error bar. The heights of the vertical shaded bars and their error bars are approximately as follows: Treatment Group One: Bar height zero point one six four, with error bar from zero point one three two, to zero point one nine six. Treatment Group Two: Bar height zero point one two five, with error bar from zero point zero two five, to zero point two two five. Treatment Group Three: Bar height zero point two one five, with error bar from zero point one eight one, to zero point two four nine. Treatment Group Four Bar height zero point two seven four, with error bar from zero point two five six, to zero point two nine two. Treatment Group Five: Bar height zero point zero nine five, with error bar from zero point zero nine one, to zero point zero nine nine.

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A table titled Effect of Water-Soluble Pollutants On Membrane Permeability is shown. The table has 4 columns and 5 rows. The first column is labeled Treatment Group. The second column is labeled Treatment Solution, which Concentrations are reported as percent by volume. The third column is labeled Mean Absorbance of 460 nm Light (n = 5), and the fourth column is labeled 2 times Standard Error of the Mean (2 times S E M). The rows read from left to right. The first row reads, Temperature group 1, 70% isopropanol; 30% water, 0.164, 0.032. The second row reads, Temperature group 2, 90% isopropanol; 10% water, 0.125, 0.100. The third row reads, Temperature group 3, 50% acetone; 50% water, 0.215, 0.034. The fourth row reads, Temperature group 4, 70% acetone; 30% water, 0.274, 0.018. The fifth row reads, Temperature group 5, 100% water, 0.095, 0.004.

A student formulated a hypothesis that water-soluble pollutants damage living organisms by increasing the permeability of cellular membranes. To test the hypothesis, the student investigated the effect of isopropanol and acetone on beet root cells. The vacuoles of beet root cells contain large amounts of betacyanin, a water-soluble pigment that is released into the extracellular environment as a result of increased membrane permeability.

The student prepared identical samples of beet root tissue and incubated each sample for 15 minutes in the specific solution for that group. At the end of the incubation period, the student measured the absorbance of 460 nm light for each sample. A greater concentration of betacyanin in the solution surrounding the beet root cells results in a greater absorbance of 460 nm light. The results of the experiment are shown in the table above.

The absorbance of 460 nm light by the treatment solutions


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A table titled Effect of Water-Soluble Pollutants On Membrane Permeability is shown. The table has 4 columns and 5 rows. The first column is labeled Treatment Group. The second column is labeled Treatment Solution, which Concentrations are reported as percent by volume. The third column is labeled Mean Absorbance of 460 nm Light (n = 5), and the fourth column is labeled 2 times Standard Error of the Mean (2 times S E M). The rows read from left to right. The first row reads, Temperature group 1, 70% isopropanol; 30% water, 0.164, 0.032. The second row reads, Temperature group 2, 90% isopropanol; 10% water, 0.125, 0.100. The third row reads, Temperature group 3, 50% acetone; 50% water, 0.215, 0.034. The fourth row reads, Temperature group 4, 70% acetone; 30% water, 0.274, 0.018. The fifth row reads, Temperature group 5, 100% water, 0.095, 0.004.

A student formulated a hypothesis that water-soluble pollutants damage living organisms by increasing the permeability of cellular membranes. To test the hypothesis, the student investigated the effect of isopropanol and acetone on beet root cells. The vacuoles of beet root cells contain large amounts of betacyanin, a water-soluble pigment that is released into the extracellular environment as a result of increased membrane permeability.

The student prepared identical samples of beet root tissue and incubated each sample for 15 minutes in the specific solution for that group. At the end of the incubation period, the student measured the absorbance of 460 nm light for each sample. A greater concentration of betacyanin in the solution surrounding the beet root cells results in a greater absorbance of 460 nm light. The results of the experiment are shown in the table above.

The figure shows a model of a cell with the following structures labeled: Vacuole, Cell Wall, and Plasma Membrane.  In the figure, the vacuole is inside the plasma membrane, and the plasma membrane is inside the cell wall. A key shows that a solid dot equals a Betacyanin Molecule.

The illustration above is a model of a typical beet root cell. Based on the experimental results, which of the following best represents the effect of acetone on the permeability of cellular membranes?


The figure shows two models of a cell with a right-facing arrow between the two cells.  The cell model on the left shows 10 Betacyanin Molecules inside the Plasma Membrane. The cell model on the right shows 10 Betacyanin Molecules outside the cell wall, 5 to the right and 5 to the left of the cell.

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A table titled Effect of Water-Soluble Pollutants On Membrane Permeability is shown. The table has 4 columns and 5 rows. The first column is labeled Treatment Group. The second column is labeled Treatment Solution, which Concentrations are reported as percent by volume. The third column is labeled Mean Absorbance of 460 nm Light (n = 5), and the fourth column is labeled 2 times Standard Error of the Mean (2 times S E M). The rows read from left to right. The first row reads, Temperature group 1, 70% isopropanol; 30% water, 0.164, 0.032. The second row reads, Temperature group 2, 90% isopropanol; 10% water, 0.125, 0.100. The third row reads, Temperature group 3, 50% acetone; 50% water, 0.215, 0.034. The fourth row reads, Temperature group 4, 70% acetone; 30% water, 0.274, 0.018. The fifth row reads, Temperature group 5, 100% water, 0.095, 0.004.

A student formulated a hypothesis that water-soluble pollutants damage living organisms by increasing the permeability of cellular membranes. To test the hypothesis, the student investigated the effect of isopropanol and acetone on beet root cells. The vacuoles of beet root cells contain large amounts of betacyanin, a water-soluble pigment that is released into the extracellular environment as a result of increased membrane permeability.

The student prepared identical samples of beet root tissue and incubated each sample for 15 minutes in the specific solution for that group. At the end of the incubation period, the student measured the absorbance of 460 nm light for each sample. A greater concentration of betacyanin in the solution surrounding the beet root cells results in a greater absorbance of 460 nm light. The results of the experiment are shown in the table above.

The student analyzed the data from the investigation and concluded that the estimate of the mean of one treatment group was unreliable. Which of the following identifies the treatment group most likely to have provided an unreliable estimate of the mean, and correctly explains why the estimate appears unreliable?

Treatment group II; it has a lower than expected mean absorbance and the largest standard error of the mean.


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A table titled Effect of Water-Soluble Pollutants On Membrane Permeability is shown. The table has 4 columns and 5 rows. The first column is labeled Treatment Group. The second column is labeled Treatment Solution, which Concentrations are reported as percent by volume. The third column is labeled Mean Absorbance of 460 nm Light (n = 5), and the fourth column is labeled 2 times Standard Error of the Mean (2 times S E M). The rows read from left to right. The first row reads, Temperature group 1, 70% isopropanol; 30% water, 0.164, 0.032. The second row reads, Temperature group 2, 90% isopropanol; 10% water, 0.125, 0.100. The third row reads, Temperature group 3, 50% acetone; 50% water, 0.215, 0.034. The fourth row reads, Temperature group 4, 70% acetone; 30% water, 0.274, 0.018. The fifth row reads, Temperature group 5, 100% water, 0.095, 0.004.

A student formulated a hypothesis that water-soluble pollutants damage living organisms by increasing the permeability of cellular membranes. To test the hypothesis, the student investigated the effect of isopropanol and acetone on beet root cells. The vacuoles of beet root cells contain large amounts of betacyanin, a water-soluble pigment that is released into the extracellular environment as a result of increased membrane permeability.

The student prepared identical samples of beet root tissue and incubated each sample for 15 minutes in the specific solution for that group. At the end of the incubation period, the student measured the absorbance of 460 nm light for each sample. A greater concentration of betacyanin in the solution surrounding the beet root cells results in a greater absorbance of 460 nm light. The results of the experiment are shown in the table above.

Based on the data from the investigation, which of the following is the best scientific question about organisms living in water that is polluted with organic solvents?


Will organisms living in polluted environments exhibit detrimental effects from an increased permeability of their cellular membranes?


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The figure is titled Solution Surrounding Cell and presents the manner in which several different ions and molecules move through a cell membrane. For each ion or molecule, the relative concentration on each side of the membrane is indicated. From left to right, the diagram is labeled as follows.  The molecule is labeled “High O subscript 2” on top, and “Low O subscript 2” on bottom. An arrow is shown starting from the top and going downward through the plasma membrane. The ion is labeled “High N a superscript plus” on top, and “Low N a superscript plus” on bottom. An arrow is shown starting from the top and going downward through a channel protein. The molecule is labeled “High Glucose” on top, and “Low Glucose” on bottom. An arrow is shown starting from the top and going downward through a channel protein. The ion is labeled “High N a superscript plus” on top, and “Low N a superscript plus” on bottom. An arrow is shown starting from the bottom and going upward through a channel protein. The ion is labeled “Low K superscript plus” on top, and “High K superscript plus” on bottom. An arrow is shown starting from the top and going downward through the same channel protein as the N a superscript plus is flowing.

The manner in which several different ions and molecules move through a cell membrane is shown in the diagram above. For each ion or molecule, the relative concentration on each side of the membrane is indicated. Which of the following accurately describes one of the movements taking place?

Na+ transport out of the cell requires ATP hydrolysis.


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Figure 1 shows a model of how a channel protein influences the movement of a particle across a cell’s plasma membrane.

The figure shows a section of a cell’s plasma membrane, with a channel protein embedded in the membrane and a concentration gradient across the membrane. Extracellular Space is indicated above the plasma membrane. Intracellular Space, cytosol, is indicated below the plasma membrane. Small hexagons represent a small particle. There are about six times as many hexagons in the extracellular space as in the intracellular space, and two hexagons are shown traversing the channel in the protein.

Figure 1. A section of a cell’s plasma membrane, showing a channel protein and a concentration gradient across the membrane

An investigator wants to understand whether a newly found membrane protein is involved in membrane transport of a certain particle. Which investigation will help determine whether the new membrane protein is a channel protein involved in membrane transport?


Add more of the proteins to the plasma membrane and measure the rate of the particle movement.


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Water is constantly diffusing into the cytosol of freshwater single-celled organisms. In order to maintain the proper solute concentrations in the cytosol, contractile vacuoles pump out the excess water. An experimenter placed single-celled organisms into various saline concentrations and recorded the ATP used by the contractile vacuole. The data are shown in the graph.

The figure presents the graph of a curve in a coordinate plane. The horizontal axis is labeled “Relative Salinity of Environment.” The vertical axis is labeled “Relative Use of A T P by the Contractile Vacuole.” The curve begins close to the top and slightly to the right of the vertical axis. The curve slopes downward and to the right at an incline that gradually becomes less steep as relative salinity of the environment increases. The curve ends a bit above the horizontal axis on the right side of the coordinate plane.

Of the following, which additional investigation can be used to determine when the cells are in an isotonic solution?


Increasing the salinity of the environment a little at a time until the ATP usage reaches a minimum


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A student peeled the skins from grapes, exposing cells with membranes that are only permeable to water and small diffusible solutes. The student measured the mass of the peeled grapes. The student then placed each peeled grape into one of five solutions. After 24 hours, the student removed the peeled grapes from the solutions, measured their final mass, and calculated the percent change in mass (Table 1).

TABLE 1. PERCENT CHANGE IN MASS OF PEELED GRAPES IN SOLUTIONS

Solution

Concentration of Solution(weight/volume)

Percent Change in Mass

Distilled water

0%

   13.48%

NaCl

20%

−23.39%

Tap water

0.8%

    9.46%

Grape juice

2.1%

    2.8%

Grape soda

13%

−15.00%

In a second experiment (Table 2), the student placed a peeled grape into a solution containing both small diffusible solutes and solutes to which the membrane is impermeable (nondiffusible solutes).

TABLE 2. CONCENTRATION OF SOLUTES IN SECOND EXPERIMENT

Location

Concentration of Small Diffusible Solutes

Concentration of Nondiffusible Solutes

Inside grape

0.4⁢M

1.2M

In solution

1.6M

0.8M

Assuming a negligible pressure potential, which of the following best predicts the net movement of the small diffusible solutes and water in the second experiment (Table 2) ?


Small diffusible solutes will diffuse into the grape cells, followed by water.


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The transport of a substance across a plasma membrane of a specific organelle requires energy. The rate at which the transport takes place also depends on temperature. A scientist isolated the specific organelle and then used the following treatments to determine the conditions that will result in the maximal transport. All treatments contained the extracted organelle and were maintained at 25°C.

The data from this experiment indicate that maximal rate of transport of protein X at 25°C occurs at an ATP concentration of 1.0�m/mL.

The figure shows the following four ATP concentrations used in the experiment: 0.2 micromoles per milliliter, 1.0 micromole per milliliter, 2.0 micromoles per milliliter, and 5.0 micromoles per milliliter.

Figure 1. The four ATP concentrations used in the experiment

Which procedure should be done next to gather data needed to meet the scientist’s objective?


Incubate samples containing 1.0�m/mL of ATP at four temperatures other than 25°C.


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Simple diffusion and facilitated diffusion are related in that both


depend on a concentration gradient


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The illustration shows the active transport of hydrogen ions through a membrane protein.

The illustration shows a cell’s plasma membrane. A membrane protein is shown with the label “A T P.” Hydrogen ions, H plus, are shown on both sides of the plasma membrane, with only a couple of ions below the membrane and many ions above the membrane. An upward pointing arrow is drawn through the channel in the center of the membrane protein to indicate the active transport of hydrogen ions from the side of the membrane with a low concentration to the side with a high concentration.

Which of the following best predicts the effect of not having ATP available to supply energy to this process?



H+
ions will stop moving through the protein.


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The figure shows a cell membrane with an aquaporin protein embedded in it.

Which statement best describes the effect on water transport across the cell membrane if the aquaporin in the figure ceases to function?


Water molecules will still be able to move across the cell membrane but at a slower rate.


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If ATP breakdown (hydrolysis) is inhibited, which of the following types of movement across cell membranes is also inhibited?


Passage of a solute against its concentration gradient


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Which of the following components of the cell membrane is responsible for active transport?


Protein


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When a substance moves across the plasma membrane along a concentration gradient at a rate faster than would be expected by simple diffusion alone but without the expenditure of metabolic energy, the process is best described as


facilitated diffusion


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A student peeled the skins from grapes, exposing cells with membranes that are only permeable to water and small diffusible solutes. The student measured the mass of the peeled grapes. The student then placed each peeled grape into one of five solutions. After 24 hours, the student removed the peeled grapes from the solutions, measured their final mass, and calculated the percent change in mass (Table 1).

TABLE 1. PERCENT CHANGE IN MASS OF PEELED GRAPES IN SOLUTIONS

Solution

Concentration of Solution(weight/volume)

Percent Change in Mass

Distilled water

0%

   13.48%

NaCl

20%

−23.39%

Tap water

0.8%

    9.46%

Grape juice

2.1%

    2.8%

Grape soda

13%

−15.00%

In a second experiment (Table 2), the student placed a peeled grape into a solution containing both small diffusible solutes and solutes to which the membrane is impermeable (nondiffusible solutes).

TABLE 2. CONCENTRATION OF SOLUTES IN SECOND EXPERIMENT

Location

Concentration of Small Diffusible Solutes

Concentration of Nondiffusible Solutes

Inside grape

0.4⁢M

1.2M

In solution

1.6M

0.8M

Mercurial sulfhydryl is an inhibitor of aquaporins. Which of the following is the most likely effect of adding mercurial sulfhydryl to the distilled water solution?


The grape cells will gain water more slowly because of a lack of facilitated diffusion.


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A human kidney filters about 200 liters of blood each day. Approximately two liters of liquid and nutrient waste are excreted as urine. The remaining fluid and dissolved substances are reabsorbed and continue to circulate throughout the body. Antidiuretic hormone (ADH) is secreted in response to reduced plasma volume. ADH targets the collecting ducts in the kidney, stimulating the insertion of aquaporins into their plasma membranes and an increased reabsorption of water.

If ADH secretion is inhibited, which of the following would initially result?


The person would produce greater amounts of dilute urine.


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A human kidney filters about 200 liters of blood each day. Approximately two liters of liquid and nutrient waste are excreted as urine. The remaining fluid and dissolved substances are reabsorbed and continue to circulate throughout the body. Antidiuretic hormone (ADH) is secreted in response to reduced plasma volume. ADH targets the collecting ducts in the kidney, stimulating the insertion of aquaporins into their plasma membranes and an increased reabsorption of water.

If ADH secretion is inhibited, which of the following would initially result?


The person would produce greater amounts of dilute urine.


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A cell’s membrane potential is maintained by the movement of ions into and out of the cell. A model showing the influence of membrane proteins on the movement of sodium (Na+) and potassium (K+) ions across the plasma membrane is presented in Figure 1.

The figure presents a bilayer plasma membrane, which separates the cytosol from the extracellular region. In the cytosol, the concentration of N a plus is low, and the concentration of K plus is high. In the extracellular region, the concentration of N a plus is high, and the concentration of K plus is low. Three membrane proteins are embedded in the plasma membrane. One protein has a channel, through which N a plus leaks into the cytosol from the extracellular region. Another protein has a channel, through which K plus leaks out from the cytosol into the extracellular region. A third protein is a pump protein, through which Na plus is pumped out from the cytosol to the extracellular region and K plus is pumped into the cytosol from the extracellular region.

Figure 1. Section of a cell’s plasma membrane, showing ion concentrations and membrane proteins

 

Based on the model presented in Figure 1, which of the following outcomes will most likely result from a loss of protein X function?


The membrane potential will be disrupted by an increase in K+ concentration inside the cell.


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The rate of transpiration, the flow of water through the stem, and leaf water potential are measured in a tree during a 24-hour period under normal environmental conditions. The results from these measurements are shown in the graphs below.

The figure shows two graphs, graph one and graph two. Graph one is in the first quadrant. It has a horizontal axis labeled time of day over a twenty-four hour period, starting with two a.m., to noon in the center of the graph, and ten p.m. on the far right. There are tick marks at every two hour increment. The vertical axis is labeled transpiration and stem flow in kilograms per hour from zero to fifteen in increments of five. There is a tick mark at each increment. There are two curves; the first is a solid line and is labeled transpiration. The second is a dashed line and is labeled stem flow. The transpiration curve begins at zero kilograms per hour at four a.m., increasing slightly until six a.m., and then increasing sharply to ten kilograms per hour by eight a.m. The curve stays constant from eight a.m. to ten a.m., then decreases to five kilograms per hour at noon, increases slightly then decreases from two p.m. to seven p.m. when it reaches zero. The curve of the stem flow has a similar shape to transpiration but shifted to the right. The stem flow curve begins around seven a.m., increasing sharply to a little below ten kilograms per hour at ten a.m., remaining there until noon when there is a short, sharp decrease, and then a more gradual decrease to five kilograms per hour by six p.m., finally decreasing to zero by nine p.m. Graph two is in quadrant four. It has a horizontal axis labeled time of day over a twenty-four hour period, starting with two a.m., to noon in the center of the graph, and ten p.m. on the far right. There are tick marks at every two hour increment., The vertical axis is labeled leaf water potential in bars. The top of the y-axis is zero, decreasing in increments of five to negative five, negative ten, and negative fifteen as it approaches the intersection with the x-axis. There is a tick mark at each increment. The leaf water potential begins at negative five bars at four a.m., decreases slightly until six a.m., then decreases sharply to below negative fifteen bars by ten a.m. and increasing slowly to approximately negative ten bars by six p.m., where the curve stops.

All of the following changes would be likely to decrease the rate of transpiration at 8 A.M. EXCEPT


increasing the water potential of the soil


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  • Directions: Each group of questions below concerns an experimental or laboratory situation or data. In each case, first study the description of the situation or data. Then choose the one best answer to each question following it and fill in the corresponding circle on the answer sheet.

Dialysis tubing is permeable to water molecules but not to sucrose. Four dialysis tubes are half filled with 5 percent, 10 percent, 20 percent, and 40 percent sucrose solutions, respectively, and two dialysis tubes are half filled with distilled water. The dialysis tubes are all sealed at both ends, and the initial masses are determined. Five dialysis tubes are placed into beakers containing distilled water, and the sixth dialysis tube, containing distilled water, is placed into a 40 percent sucrose solution. The masses of the dialysis tubes are recorded at 30-minute intervals for 90 minutes, as shown in the table below.

The figure shows a table with 7 columns and 7 rows. The top row contains the column labels, from left to right; Dialysis Tube Number; Dialysis Tube Contents; Beaker Contents; Initial Mass; Mass (grams) recorded at 30 minutes, 60 minutes and 90 minutes. From top to bottom, the data is as follows; Row 2; Dialysis Tube Number 1; Dialysis Tube Contents, 5% Sucrose; Beaker Contents, Distilled water; Initial Mass, 12.8; Mass recorded at 30 minutes, 13.3; Mass recorded at 60 minutes, 13.4; and Mass recorded at 90 minutes, 13.8. Row 3; Dialysis Tube Number 2; Dialysis Tube Contents, 10% Sucrose; Beaker Contents, Distilled water; Initial Mass, 15.6; Mass recorded at 30 minutes, 16.7; Mass recorded at 60 minutes, 17.0; and Mass recorded at 90 minutes, 17.3. Row 4; Dialysis Tube Number 3; Dialysis Tube Contents, 20% Sucrose; Beaker Contents, Distilled water; Initial Mass, 13.7; Mass recorded at 30 minutes, 15.4; Mass recorded at 60 minutes, 16.2; and Mass recorded at 90 minutes, 16.5. Row 5; Dialysis Tube Number 4; Dialysis Tube Contents, 40 percent Sucrose; Beaker Contents, Distilled water; Initial Mass 13.4; Mass recorded at 30 minutes, 16.3; Mass recorded at 60 minutes, 18.1; and Mass recorded at 90 minutes, 19.6. Row 6; Dialysis Tube Number 5; Dialysis Tube Contents, Distilled water; Beaker Contents, Distilled water; Initial Mass, 11.2; Mass recorded at 30 minutes, 11.2; Mass recorded at 60 minutes, 11.2; and Mass recorded at 90 minutes, 11.2. Row 7; Dialysis Tube Number 6; Dialysis Tube Contents, Distilled water; Beaker Contents, 40 percent Sucrose; Initial Mass, 13.8; Mass recorded at 30 minutes, 10.1; Mass recorded at 60 minutes, 8.3; and Mass recorded at 90 minutes, 6.3.

The contents of which dialysis tube are initially isotonic to the distilled water in the beaker?


5


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  • Directions: Each group of questions below concerns an experimental or laboratory situation or data. In each case, first study the description of the situation or data. Then choose the one best answer to each question following it and fill in the corresponding circle on the answer sheet.

Dialysis tubing is permeable to water molecules but not to sucrose. Four dialysis tubes are half filled with 5 percent, 10 percent, 20 percent, and 40 percent sucrose solutions, respectively, and two dialysis tubes are half filled with distilled water. The dialysis tubes are all sealed at both ends, and the initial masses are determined. Five dialysis tubes are placed into beakers containing distilled water, and the sixth dialysis tube, containing distilled water, is placed into a 40 percent sucrose solution. The masses of the dialysis tubes are recorded at 30-minute intervals for 90 minutes, as shown in the table below.

The figure shows a table with 7 columns and 7 rows. The top row contains the column labels, from left to right; Dialysis Tube Number; Dialysis Tube Contents; Beaker Contents; Initial Mass; Mass (grams) recorded at 30 minutes, 60 minutes and 90 minutes. From top to bottom, the data is as follows; Row 2; Dialysis Tube Number 1; Dialysis Tube Contents, 5% Sucrose; Beaker Contents, Distilled water; Initial Mass, 12.8; Mass recorded at 30 minutes, 13.3; Mass recorded at 60 minutes, 13.4; and Mass recorded at 90 minutes, 13.8. Row 3; Dialysis Tube Number 2; Dialysis Tube Contents, 10% Sucrose; Beaker Contents, Distilled water; Initial Mass, 15.6; Mass recorded at 30 minutes, 16.7; Mass recorded at 60 minutes, 17.0; and Mass recorded at 90 minutes, 17.3. Row 4; Dialysis Tube Number 3; Dialysis Tube Contents, 20% Sucrose; Beaker Contents, Distilled water; Initial Mass, 13.7; Mass recorded at 30 minutes, 15.4; Mass recorded at 60 minutes, 16.2; and Mass recorded at 90 minutes, 16.5. Row 5; Dialysis Tube Number 4; Dialysis Tube Contents, 40 percent Sucrose; Beaker Contents, Distilled water; Initial Mass 13.4; Mass recorded at 30 minutes, 16.3; Mass recorded at 60 minutes, 18.1; and Mass recorded at 90 minutes, 19.6. Row 6; Dialysis Tube Number 5; Dialysis Tube Contents, Distilled water; Beaker Contents, Distilled water; Initial Mass, 11.2; Mass recorded at 30 minutes, 11.2; Mass recorded at 60 minutes, 11.2; and Mass recorded at 90 minutes, 11.2. Row 7; Dialysis Tube Number 6; Dialysis Tube Contents, Distilled water; Beaker Contents, 40 percent Sucrose; Initial Mass, 13.8; Mass recorded at 30 minutes, 10.1; Mass recorded at 60 minutes, 8.3; and Mass recorded at 90 minutes, 6.3.

A net movement of water into the beaker occurs in which of the following dialysis tubes?


6

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  • Directions: Each group of questions below concerns an experimental or laboratory situation or data. In each case, first study the description of the situation or data. Then choose the one best answer to each question following it and fill in the corresponding circle on the answer sheet.

Dialysis tubing is permeable to water molecules but not to sucrose. Four dialysis tubes are half filled with 5 percent, 10 percent, 20 percent, and 40 percent sucrose solutions, respectively, and two dialysis tubes are half filled with distilled water. The dialysis tubes are all sealed at both ends, and the initial masses are determined. Five dialysis tubes are placed into beakers containing distilled water, and the sixth dialysis tube, containing distilled water, is placed into a 40 percent sucrose solution. The masses of the dialysis tubes are recorded at 30-minute intervals for 90 minutes, as shown in the table below.

The figure shows a table with 7 columns and 7 rows. The top row contains the column labels, from left to right; Dialysis Tube Number; Dialysis Tube Contents; Beaker Contents; Initial Mass; Mass (grams) recorded at 30 minutes, 60 minutes and 90 minutes. From top to bottom, the data is as follows; Row 2; Dialysis Tube Number 1; Dialysis Tube Contents, 5% Sucrose; Beaker Contents, Distilled water; Initial Mass, 12.8; Mass recorded at 30 minutes, 13.3; Mass recorded at 60 minutes, 13.4; and Mass recorded at 90 minutes, 13.8. Row 3; Dialysis Tube Number 2; Dialysis Tube Contents, 10% Sucrose; Beaker Contents, Distilled water; Initial Mass, 15.6; Mass recorded at 30 minutes, 16.7; Mass recorded at 60 minutes, 17.0; and Mass recorded at 90 minutes, 17.3. Row 4; Dialysis Tube Number 3; Dialysis Tube Contents, 20% Sucrose; Beaker Contents, Distilled water; Initial Mass, 13.7; Mass recorded at 30 minutes, 15.4; Mass recorded at 60 minutes, 16.2; and Mass recorded at 90 minutes, 16.5. Row 5; Dialysis Tube Number 4; Dialysis Tube Contents, 40 percent Sucrose; Beaker Contents, Distilled water; Initial Mass 13.4; Mass recorded at 30 minutes, 16.3; Mass recorded at 60 minutes, 18.1; and Mass recorded at 90 minutes, 19.6. Row 6; Dialysis Tube Number 5; Dialysis Tube Contents, Distilled water; Beaker Contents, Distilled water; Initial Mass, 11.2; Mass recorded at 30 minutes, 11.2; Mass recorded at 60 minutes, 11.2; and Mass recorded at 90 minutes, 11.2. Row 7; Dialysis Tube Number 6; Dialysis Tube Contents, Distilled water; Beaker Contents, 40 percent Sucrose; Initial Mass, 13.8; Mass recorded at 30 minutes, 10.1; Mass recorded at 60 minutes, 8.3; and Mass recorded at 90 minutes, 6.3.

To model a plant cell, a permeable, nonflexible case is placed around each piece of dialysis tubing. The greatest pressure potential will develop within dialysis tube number 


4

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The following questions refer to an experiment in which a dialysis-tubing bag is filled with a mixture of 3% starch and 3% glucose and placed in a beaker of distilled water, as shown below. After 3 hours, glucose can be detected in the water outside the dialysis-tubing bag, but starch cannot.

A figure of a dialysis-tubing bag submerged in a beaker of distilled water. The bag is pictured as being tied shut at both ends, and is labeled dialysis-tubing bag with three percent starch and three percent glucose.

From the initial conditions and results described, which of the following is a logical conclusion?


The pores of the bag are larger than the glucose molecules but smaller than the starch molecules.


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The following questions refer to an experiment in which a dialysis-tubing bag is filled with a mixture of 3% starch and 3% glucose and placed in a beaker of distilled water, as shown below. After 3 hours, glucose can be detected in the water outside the dialysis-tubing bag, but starch cannot.

A figure of a dialysis-tubing bag submerged in a beaker of distilled water. The bag is pictured as being tied shut at both ends, and is labeled dialysis-tubing bag with three percent starch and three percent glucose.

Which of the following best describes the condition expected after 24 hours?


The bag will contain more water than it did in the original condition.


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The following questions refer to an experiment in which a dialysis-tubing bag is filled with a mixture of 3% starch and 3% glucose and placed in a beaker of distilled water, as shown below. After 3 hours, glucose can be detected in the water outside the dialysis-tubing bag, but starch cannot.

A figure of a dialysis-tubing bag submerged in a beaker of distilled water. The bag is pictured as being tied shut at both ends, and is labeled dialysis-tubing bag with three percent starch and three percent glucose.

If, instead of the bag, a potato slice were placed in the beaker of distilled water, which of the following would be true of the potato slice?


It would gain mass.


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A student peeled the skins from grapes, exposing cells with membranes that are only permeable to water and small diffusible solutes. The student measured the mass of the peeled grapes. The student then placed each peeled grape into one of five solutions. After 24 hours, the student removed the peeled grapes from the solutions, measured their final mass, and calculated the percent change in mass (Table 1).

TABLE 1. PERCENT CHANGE IN MASS OF PEELED GRAPES IN SOLUTIONS

Solution

Concentration of Solution(weight/volume)

Percent Change in Mass

Distilled water

0%

   13.48%

NaCl

20%

−23.39%

Tap water

0.8%

    9.46%

Grape juice

2.1%

    2.8%

Grape soda

13%

−15.00%

In a second experiment (Table 2), the student placed a peeled grape into a solution containing both small diffusible solutes and solutes to which the membrane is impermeable (nondiffusible solutes).

TABLE 2. CONCENTRATION OF SOLUTES IN SECOND EXPERIMENT

Location

Concentration of Small Diffusible Solutes

Concentration of Nondiffusible Solutes

Inside grape

0.4⁢M

1.2M

In solution

1.6M

0.8M

Based on Table 1, which of the following best explains the difference in water potential between certain solutions and the grapes?


Grape soda and NaCl have a lower water potential because these two solutions caused the grape to lose water.


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A student peeled the skins from grapes, exposing cells with membranes that are only permeable to water and small diffusible solutes. The student measured the mass of the peeled grapes. The student then placed each peeled grape into one of five solutions. After 24 hours, the student removed the peeled grapes from the solutions, measured their final mass, and calculated the percent change in mass (Table 1).

TABLE 1. PERCENT CHANGE IN MASS OF PEELED GRAPES IN SOLUTIONS

Solution

Concentration of Solution(weight/volume)

Percent Change in Mass

Distilled water

0%

   13.48%

NaCl

20%

−23.39%

Tap water

0.8%

    9.46%

Grape juice

2.1%

    2.8%

Grape soda

13%

−15.00%

In a second experiment (Table 2), the student placed a peeled grape into a solution containing both small diffusible solutes and solutes to which the membrane is impermeable (nondiffusible solutes).

TABLE 2. CONCENTRATION OF SOLUTES IN SECOND EXPERIMENT

Location

Concentration of Small Diffusible Solutes

Concentration of Nondiffusible Solutes

Inside grape

0.4⁢M

1.2M

In solution

1.6M

0.8M

Based on Table 1, which of the following percentages is closest to the solute concentration of the grape?


5.5%

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A student peeled the skins from grapes, exposing cells with membranes that are only permeable to water and small diffusible solutes. The student measured the mass of the peeled grapes. The student then placed each peeled grape into one of five solutions. After 24 hours, the student removed the peeled grapes from the solutions, measured their final mass, and calculated the percent change in mass (Table 1).

TABLE 1. PERCENT CHANGE IN MASS OF PEELED GRAPES IN SOLUTIONS

Solution

Concentration of Solution(weight/volume)

Percent Change in Mass

Distilled water

0%

   13.48%

NaCl

20%

−23.39%

Tap water

0.8%

    9.46%

Grape juice

2.1%

    2.8%

Grape soda

13%

−15.00%

In a second experiment (Table 2), the student placed a peeled grape into a solution containing both small diffusible solutes and solutes to which the membrane is impermeable (nondiffusible solutes).

TABLE 2. CONCENTRATION OF SOLUTES IN SECOND EXPERIMENT

Location

Concentration of Small Diffusible Solutes

Concentration of Nondiffusible Solutes

Inside grape

0.4⁢M

1.2M

In solution

1.6M

0.8M

A student hypothesizes that the solute concentration of grape juice is higher than the solute concentration of the actual grape because the grape juice has added sugar.

Based on the data in Table 1, which of the following best evaluates the student’s hypothesis?


The hypothesis is not supported because the mass of the grape increased in the grape juice.


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Stickleback fish are found in both marine and freshwater habitats. The marine fish have no scales but have hardened, armorlike plates along their sides. The plates are thought to protect sticklebacks from certain predators.

In the late 1980s, sticklebacks from a marine population colonized Loberg Lake, a freshwater lake in Alaska. Starting in 1990, researchers sampled fish from the lake every four years and recorded the armor-plate phenotypes of the male sticklebacks in each sample. The armor-plate phenotypes were categorized as either complete (plates extending from head to tail), partial (plates extending from head to abdomen), or low (a few plates near the head only). The results are shown in the table below.

ARMOR-PLATE VARIATION IN THE STICKLEBACK POPULATION OF LOBERG LAKE

 

Percent of Males in the Sample with Each Armor-Plate Phenotype

Year

Low

Partial

Complete

1990

1%

2%

97%

1994

45%

14%

41%

1998

58%

16%

26%

2002

76%

15%

9%

2006

90%

6%

4%

 

 

 

 

 

 

 

 

 

 

Intact cells of two unknown cell types were placed into solutions with different concentrations of NaCl. Type I cells swelled and burst in the solution with the lowest concentration of NaCl. Type II cells swelled but did not burst in the solution with the lowest concentration of NaCl.

Which of the following descriptions of cell type I and cell type II are most consistent with the data?


Cell Type I

Cell Type II

Animal cell surrounded by a plasma membrane only

Plant cell surrounded by a plasma membrane and a cell wall

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A graph of rate of contraction vs. osmolarity of solution. The x axis is labeled osmolality of solution in millimolar. The y axis is labeled Rate of Contraction in contractions per minute. There is a diagonal line with a negative slope that goes from some distance above zero on the y axis down towards some positive distance on the x axis.

Paramecia are unicellular protists that have contractile vacuoles to remove excess intracellular water. In an experimental investigation, paramecia were placed in salt solutions of increasing osmolarity. The rate at which the contractile vacuole contracted to pump out excess water was determined and plotted against osmolarity of the solutions, as shown in the graph. Which of the following is the correct explanation for the data?


The contraction rate increases as the osmolarity decreases because the amount of water entering the paramecia by osmosis increases.


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The figure shows a graph in the first quadrant. The vertical axis is labeled Rate of Contraction in contractions per minute. The horizontal axis is labeled osmolarity of solution in millimolars. There is a diagonal line with a negative slope that goes from some distance above zero on the vertical axis down towards some positive distance on the horizontal axis.

Paramecia are unicellular protists that have contractile vacuoles to remove excess intracellular water. In an experimental investigation, paramecia were placed in salt solutions of increasing osmolarity. The rate at which the contractile vacuole contracted to pump out excess water was determined and plotted against osmolarity of the solutions, as shown in the graph. Which of the following is the correct explanation for the data?


The contractile vacuole is less efficient in solutions of high osmolarity because of the reduced amount of ATP produced from cellular respiration.


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The figure presents a semipermeable membrane in the center of a U-shaped channel separated into two chambers, labeled Chamber A and Chamber B. Both of the chambers are filled with equal amounts of water.

A student placed a semipermeable membrane inside a U-shaped channel with two chambers, as shown. The membrane permits the movement of water but not salt. The student wants to vary the rate of osmosis that occurs across the membrane. Which of the following experimental designs will result in the fastest net rate of water movement into chamber A?


Placing salt water in chamber A and distilled water in chamber B


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A sample of human blood was placed in a test tube containing a physiological saline solution (0.9% sodium chloride). This type of solution is often used intravenously to quickly rehydrate patients. A drop of the blood from the test tube was placed on a slide and red blood cells (RBCs) were observed under a microscope. Three possible outcomes are diagrammed below.

There are three microscope views of red blood cells. View one shows shrunken red blood cells. There are a dozen red blood cells with jagged edges, they are thin and irregular.View two shows a dozen normal red blood cells. The red blood cells are circular and oval with no irregularities. View three shows a dozen swollen and bursting red blood cells. The red blood cells are all large and circular, one has burst.

Which of the following best predicts which diagrammed microscope view the laboratory worker would see and best explains why?


View 2 because the rate of water movement into the RBCs equals the rate of water movement out of the cells


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A common laboratory investigation involves putting a solution of starch and glucose into a dialysis bag and suspending the bag in a beaker of water, as shown in the figure below.

 

A figure of a beaker of water. A dialysis bag labeled as starch plus glucose is tied to a dowel that is sitting across the top of the beaker, allowing the bag to be suspended in the water. There is an arrow to a second figure of a beaker with water. In this figure the dialysis bag is bloated and labeled starch plus glucose, and the water is labeled water plus glucose.

 

 

The investigation is aimed at understanding how molecular size affects movement through a membrane.

Which of the following best represents the amount of starch, water, and glucose in the dialysis bag over the course of the investigation?


A graph with x-axis labeled time and y-axis labeled relative amount in dialysis bag.The amount of starch remains constant. The amount of water starts below the amount of starch, increases to above the amount of starch and flattens out. The amount of glucose starts at higher than the amount of the starch, decreases to less than the amount of starch and flattens out.


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The following question refer to the graph below, which illustrates the percent change in the mass of pieces of plant tissue placed in solutions of different sucrose molarities.

The figure shows a graph in quadrants one and four titled Change In Mass Of Plant Tissue.  The horizontal axis is labeled molarity from zero to one point two in increments of point one with a tick mark at each increment. The vertical axis is labeled percent change in mass from negative thirty to positive twenty-five in increments of five with a tick mark at each increment. The mass begins at twenty percent on the vertical axis and zero on the horizontal axis and decreases steadily to a negative twenty-five percent change in mass at a molarity of zero point eight. At molarity of zero point two the percent change is five, at  zero point four molarity the percent change is negative eight, at zero point six molarity the percent change is negative sixteen, and then it remains constant at negative twenty-five from  zero point eight to one molarity.

Water enters and leaves the plant cells primarily by


osmosis

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The rate of transpiration, the flow of water through the stem, and leaf water potential are measured in a tree during a 24-hour period under normal environmental conditions. The results from these measurements are shown in the graphs below.

The figure shows two graphs, graph one and graph two. Graph one is in the first quadrant. It has a horizontal axis labeled time of day over a twenty-four hour period, starting with two a.m., to noon in the center of the graph, and ten p.m. on the far right. There are tick marks at every two hour increment. The vertical axis is labeled transpiration and stem flow in kilograms per hour from zero to fifteen in increments of five. There is a tick mark at each increment. There are two curves; the first is a solid line and is labeled transpiration. The second is a dashed line and is labeled stem flow. The transpiration curve begins at zero kilograms per hour at four a.m., increasing slightly until six a.m., and then increasing sharply to ten kilograms per hour by eight a.m. The curve stays constant from eight a.m. to ten a.m., then decreases to five kilograms per hour at noon, increases slightly then decreases from two p.m. to seven p.m. when it reaches zero. The curve of the stem flow has a similar shape to transpiration but shifted to the right. The stem flow curve begins around seven a.m., increasing sharply to a little below ten kilograms per hour at ten a.m., remaining there until noon when there is a short, sharp decrease, and then a more gradual decrease to five kilograms per hour by six p.m., finally decreasing to zero by nine p.m. Graph two is in quadrant four. It has a horizontal axis labeled time of day over a twenty-four hour period, starting with two a.m., to noon in the center of the graph, and ten p.m. on the far right. There are tick marks at every two hour increment., The vertical axis is labeled leaf water potential in bars. The top of the y-axis is zero, decreasing in increments of five to negative five, negative ten, and negative fifteen as it approaches the intersection with the x-axis. There is a tick mark at each increment. The leaf water potential begins at negative five bars at four a.m., decreases slightly until six a.m., then decreases sharply to below negative fifteen bars by ten a.m. and increasing slowly to approximately negative ten bars by six p.m., where the curve stops.

What can be deduced from graph I?


The maximal flow of water through the stem lags behind the maximal rate of transpiration.


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A scientist designed an experiment to test an artificial membrane that mimics the phospholipid bilayer of a cell.

The scientist built a tube that was divided by an artificial membrane and filled with distilled water. The scientist put a known amount of a protein into the water on one side of the membrane. After some time, the scientist measured the concentration of the protein on either side of the membrane but found that there had been no change.

Which of the following experimental changes would allow the scientist to observe transport of a solute across the artificial membrane?


Use a small, nonpolar solute instead of a protein


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Cholesterol is an important component of animal cell membranes. Cholesterol molecules are often delivered to body cells by the blood, which transports the molecules in the form of cholesterol-protein complexes. The complexes must be moved into the body cells before the cholesterol molecules can be incorporated into the phospholipid bilayers of cell membranes.

Based on the information presented, which of the following is the most likely explanation for a buildup of cholesterol molecules in the blood of an animal?


The animal’s body cells are defective in endocytosis.


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The image shows a drawing of a cell membrane running horizontally.  The area above the cell membrane is labeled Cytosol, and the area below the cell membrane is labeled Extracellular Fluid. On the left side of the membrane, an arrow that passes directly through the membrane connects a large group of white circles in the extracellular fluid to a small group of white circles in the cytosol. In the middle of the membrane, an arrow that passes between two large ovals that span the membrane connects a large group of black rectangles in the extracellular fluid to a small group of black rectangles in the cytosol. On the right side of the membrane, an arrow that passes through a large rectangle that spans the membrane connects a small group of black ovals in the extracellular fluid to a large group of black ovals in the cytosol.

Which of the following scientific questions is most relevant to the model represented in the figure above?


Which molecular substance is actively transported across the plasma membrane?


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Which of the following statements best explains the processes of passive and active transport?


Passive transport is the net movement of substances down a concentration gradient that does not require metabolic energy. Active transport is the movement of substances up a concentration gradient that requires energy.


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In an experiment, cells were isolated from an aquatic plant and suspended in pond water, a sucrose sugar solution, or distilled water. All of the cells were then viewed under a microscope. Compared with the cell in the pond water, the cell in the sugar solution appeared shriveled, and the cell in the distilled water appeared inflated. The results of the experiment are represented in Figure 1.

Figure 1 shows the results of the experiment in which cells were isolated from an aquatic plant and suspended in pond water, a sucrose sugar solution, or distilled water. The cell in pond water is rectangular, and gray shading fills all of the cell except for space occupied by a central vacuole and the nucleus. The cell walls of the cell in the sugar solution are a bit collapsed, the central vacuole has shrunk to about half the size of the vacuole in the pond-water-cell, and gray shading only fills about half of the space unoccupied by the vacuole and nucleus. The cell walls of the cell in distilled water appear pushed out, the central vacuole is about four times the size of the vacuole in the pond-water-cell, and gray shading fills all the rest of the space in the cell except for that occupied by the nucleus.

Figure 1. The results of an experiment using aquatic plant cells

 

Which of the following statements best explains the observations represented in Figure 1 ?


There was a net movement of water out of the cell suspended in the sugar solution and a net movement of water into the cell suspended in the distilled water.


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What evolutionary advantage does compartmentalization of core metabolic processes offer eukaryotes?


Evolution of a nucleus in eukaryotes separates the processes of transcription and translation and they can be regulated separately.


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Changing the shape or morphology of the mitochondrial inner membrane can change the efficiency of mitochondrial function.

Which of the following outcomes will most likely result from a change in the shape of the mitochondrial inner membrane from a highly folded surface to a smooth, flat surface?


Mitochondria will become less efficient because the surface area of the inner mitochondrial membranes will decrease.


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The figure shows a process by which a cell might absorb food from its surrounding environment and break it down for use as a source of energy and matter. The process involves lysosomes, which are membrane-bound organelles that contain hydrolytic enzymes. Activation of the hydrolytic enzymes requires an acidic pH, and lysosomes maintain an internal acidic pH by using ion pumps.

The figure shows a cell with arrows pointing between labeled organelles and vesicles to indicate a process of food absorption and digestion. In one part of the figure, arrows indicate a transport vesicle moving from the rough endoplasmic reticulum to the Golgi apparatus, and further arrows indicate lysosomes that have pinched off from the Golgi apparatus. In another part of the figure, a food particle is shown in an invagination of the plasma membrane, a process that is labeled phagocytosis. An arrow indicates that the food particle is now moving through the cytosol in a food vacuole. The food vacuole is shown fusing with a lysosome in a process labeled digestion.

Which of the following outcomes will most likely result from a loss of ion pump function in the cell’s lysosomes?


The internal pH of the lysosomes will increase, which will prevent the activation of hydrolytic enzymes and interfere with the intracellular digestion of food.


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Membrane-bound organelles have been an important component in the evolution of complex, multicellular organisms. Which of the following best summarizes an advantage of eukaryotic cells having internal membranes?


Organelles isolate specific reactions, increasing metabolic efficiency.


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Which of the following statements best predicts the effect of increasing the permeability of the mitochondrial membranes to large molecules?



ATP
production will decrease because of an increase in the occurrence of uncontrolled chemical reactions.


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Researchers claimed that a particular organelle originated from a free-living prokaryotic cell that was engulfed by a larger cell, as shown in Figure 1.

Figure 1 shows a model of one cell engulfing a smaller cell in 3 stages. Stage 1 shows a small cell next to a large cell. Stage 2 shows the large cell beginning to wrap around and engulf the small cell. Stage 3 shows the small cell inside the large cell.

Figure 1. A model showing a cell engulfing a smaller cell

Which of the following provides evidence to best support the researchers’ claim?


The organelle has a double membrane.


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The figure shows a diagram of a typical rod-shaped bacterium. The cell body of the bacterium is represented by an elongated oval shape, like a pill capsule. Attached to one end of the cell body is a long, tail-like structure. Covering the outer surface of the cell body are small, spike-like structures. The cell body is shown as being enclosed by three layers, a thick outer layer, a thin middle layer, and a thin inner layer. In some places, the inner layer is shown projecting through the middle and outer layers to reach the exterior of the cell body. The interior of the cell body is a single chamber that contains a large, ribbon-like structure twisted around itself, a much smaller circular, ribbon-like structure, and many dot-like structures scattered throughout the chamber.

The diagram above represents a typical rod-shaped bacterium. Which of the following best describes a feature shown in the diagram that is unique to archaea and bacteria?


The organism does not have a nuclear membrane surrounding its genetic material.


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The following questions refer to the following diagram. For each phrase or sentence, select the labeled part to which it is most closely related. Each option may be used once, more than once, or not at all for each group.

 

The figure shows a three dimensional diagram of a plant cell. A compartment labeled A is a small oval-shaped compartment near the cell membrane. It has an inner membrane that folds over on itself creating a layered structure inside the compartment. Compartment B is a medium-sized oval-shaped compartment filled with small, discreet ovals that are packed tightly and stacked, filling the compartment. There is a dark, round compartment in the cell that is partially surrounded by a maze-like structure with black dots all over the surface. C is a maze-like structure above this structure with no black dots. D is the black line that is the innermost circle surrounding the entire cell. E is a very large circular compartment that takes up about one-third of the cell diagram.

Evolved from a photoautotrophic prokaryote


B (Chloroplast)

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Which of the following best supports the statement that mitochondria are descendants of endosymbiotic bacteria-like cells?


Mitochondria and bacteria possess similar ribosomes and DNA.


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Which of the following statements best supports the claim that certain organelles within eukaryotic cells evolved from free-living prokaryotic cells?


Some organelles contain their own DNA that is more similar to prokaryotic DNA in structure and function than to the eukaryotic DNA found in the cell's nucleus.