Carbohydrates Diagram

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Carbohydrates

It is the most abundant organic compounds

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chemical energy

Carbohydrates act as storehouses for (?)

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Carbohydrates

(?) are supportive components in plants.

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Carbohydrates

(?) are essential components of nucleic acids

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Hydrate of Carbon

True or False? If false replace the underlined word to make the statement correct.

Carbohydrates means “Carbon of Hydrate”

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True

True or False? If false replace the underlined word to make the statement correct.

Carbohydrates are rich in OH

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Aldoses; Ketoses

What are the 2 major groups of Carbohydrates?

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True

MAJOR GROUPS OF CARBOHYDRATES

True or False? If false replace the underlined word to make the statement correct.

Aldehyde —> Aldoses

Ketones —> Ketoses

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Monosaccharides; Disaccharides; Oligosaccharides; Polysaccharides

Give the 4 classifications of Carbohydrates

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Monosaccharides

Carbohydrates that cannot be hydrolyzed to a simpler compound.

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Monosaccharides

General formula: CnH2nOn

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-ose

The suffix “(?)” indicates that a molecule is a carbohydrate.

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A

A.) Monosaccharides

B.) Disaccharides

C.) Oligosaccharides

D.) Polysaccharides

<p>A.) Monosaccharides</p><p>B.) Disaccharides</p><p>C.) Oligosaccharides</p><p>D.) Polysaccharides</p>
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B

A.) Monosaccharides

B.) Disaccharides

C.) Oligosaccharides

D.) Polysaccharides

<p>A.) Monosaccharides</p><p>B.) Disaccharides</p><p>C.) Oligosaccharides</p><p>D.) Polysaccharides</p>
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C

A.) Monosaccharides

B.) Disaccharides

C.) Oligosaccharides

D.) Polysaccharides

<p>A.) Monosaccharides</p><p>B.) Disaccharides</p><p>C.) Oligosaccharides</p><p>D.) Polysaccharides</p>
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D

A.) Monosaccharides

B.) Disaccharides

C.) Oligosaccharides

D.) Polysaccharides

<p>A.) Monosaccharides</p><p>B.) Disaccharides</p><p>C.) Oligosaccharides</p><p>D.) Polysaccharides</p>
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Aldoses

Monosaccharides containing the aldehyde group (-CHO)

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Ketoses

Monosaccharides containing the ketone group (-C=O)

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functional group; carbons; ose

NOMENCLATURE

Step 1: Identify the (?)

Step 2: Count the number of (?)

Step 3: Add the suffix (?)

<p>NOMENCLATURE</p><p>Step 1: Identify the (?)</p><p>Step 2: Count the number of (?)</p><p>Step 3: Add the suffix (?)</p>
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Superimposable mirror images

(?) are images that coincide at all

points when the images are laid

upon each other

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Nonsuperimposable mirror images

(?) are images where not all points coincide when the images are laid upon each other

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not superimposable

True or False? If false replace the underlined word to make the statement correct.

“A person’s left and right hands are superimposable upon each other.”

<p>True or False? If false replace the underlined word to make the statement correct.</p><p>“A person’s left and right hands are superimposable upon each other.”</p>
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Chiral

Nonsuperimposable on its mirror image

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Achiral

Superimposable on its mirror image

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True

True or False? If false, replace the underlined word to make the statement correct.

“If a molecule (or object) has a mirror plane or an inversion center, it cannot be chiral.”

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plane of symmetry

How can you predict whether a given molecule is or is not chiral?

A molecule is not chiral if it has a (?).

<p>How can you predict whether a given molecule is or is not chiral?</p><p>A molecule is not chiral if it has a (?).</p>
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Achiral

<p></p>
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Chiral

<p></p>
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Achiral

<p></p>
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Chiral

If there is a prefix "trans", automatically it is (?)

<p>If there is a prefix "trans", automatically it is (?)</p>
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asymmetric center

An (?) is an atom that is bonded to four different groups.

<p>An (?) is an atom that is bonded to four different groups.</p>
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one

Organic molecules, especially monosaccharides, may contain more than (?) chiral center.

<p>Organic molecules, especially monosaccharides, may contain more than (?) chiral center.</p>
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Fischer Projection

A two-dimensional representation for showing the configuration of tetrahedral stereocenters.

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forward; rear

FISCHER PROJECTION

Horizontal lines represent bonds projecting (?) from the stereocenter.

Vertical lines represent bonds projecting to the (?).

<p>FISCHER PROJECTION</p><p>Horizontal lines represent bonds projecting (?) from the stereocenter.</p><p>Vertical lines represent bonds projecting to the (?).</p>
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plane

FISCHER PROJECTION

Only the stereo center is in the (?).

<p>FISCHER PROJECTION</p><p>Only the stereo center is in the (?).</p>
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1891; Emil Fischer

In the year (?), (?) made the arbitrary assignments of D- and L- to the enantiomers of glyceraldehyde.

<p>In the year (?), (?) made the arbitrary assignments of D- and L- to the enantiomers of glyceraldehyde.</p>
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D-monosaccharide

The -OH on its penultimate carbon is on the right in a Fischer projection

<p>The -OH on its penultimate carbon is on the right in a Fischer projection</p>
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L-monosaccharide

The -OH on its penultimate carbon is on the left in a Fischer projection.

<p>The -OH on its penultimate carbon is on the left in a Fischer projection.</p>
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Amino sugars

Contain an -NH2 group in place of an -OH group.

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colorless; crystalline

PHYSICAL PROPERTIES

Monosaccharides are (?), (?) solids.

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Ethanol

PHYSICAL PROPERTIES

Monosaccharides are slightly soluble to (?) and insoluble to nonpolar solvents such as diethyl ether, dichloromethane and benzene.

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hemiacetals

Aldehydes and ketones react with alcohols to form (?).

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Cyclic hemiacetals

(?) form readily when hydroxyl and carbonyl groups are part of the same molecule and their interaction can form a five- or six-membered ring.

<p>(?) form readily when hydroxyl and carbonyl groups are part of the same molecule and their interaction can form a five- or six-membered ring.</p>
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Haworth Projections

A five- or six-membered cyclic hemiacetal is represented as a planar ring.

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Anomeric carbon

HAWORTH PROJECTIONS

The new carbon stereocenter created in forming the cyclic structure is called the (?)

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Anomers

HAWORTH PROJECTIONS

Stereoisomers that differ in configuration only at the anomeric carbon are called (?).

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right; top

In a Haworth projection, the hemiacetal ring system is viewed “edge on” with the oxygen ring atom at the upper (?) (six- membered ring) or at the (?) (five- membered ring).

<p>In a Haworth projection, the hemiacetal ring system is viewed “edge on” with the oxygen ring atom at the upper (?) (six- membered ring) or at the (?) (five- membered ring).</p>
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above; below

HAWORTH PROJECTIONS

In the D form, CH2OH is positioned (?) the ring.

In the L form, which is not usually encountered in biochemical systems, the terminal CH2OH group is positioned (?) the ring.

<p>HAWORTH PROJECTIONS</p><p>In the D form, CH2OH is positioned (?) the ring.</p><p>In the L form, which is not usually encountered in biochemical systems, the terminal CH2OH group is positioned (?) the ring.</p>
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OH

HAWORTH PROJECTIONS

α or β configuration is determined by the position of the —(?) group on carbon 1 relative to the CH2OH group that determines D or L series.

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same

HAWORTH PROJECTIONS

In β configuration, both —OH group and CH2OH group point in the (?) direction.

<p>HAWORTH PROJECTIONS</p><p>In β configuration, both —OH group and CH2OH group point in the (?) direction.</p>
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opposite

HAWORTH PROJECTIONS

In α configuration, both —OH group and CH2OH group point in (?) directions.

<p>HAWORTH PROJECTIONS</p><p>In α configuration, both —OH group and CH2OH group point in (?) directions.</p>
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anomeric

CONVERTING FISCHER TO HAWORTH

Step 1: Draw a Haworth’s “stem”

Step 2: Number your atoms 1 through 5 starting from the (?) carbon and going clockwise

Step 3: If your sugar was D, then the carbon #6 is going to be looking “up” (down for the L sugar)

Step 4: The “right” groups on carbons 2, 3, and 4 in the Fischer projection go onto the “bottom” positions in Haworth

Step 5: The “left” groups on carbons 2, 3, and 4 in the Fischer projection go onto the “up” positions in Haworth

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alpha-D-glucose; beta-D-glucose

What are the 2 forms of glucose?

<p>What are the 2 forms of glucose?</p>
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Anomers

Cyclic monosaccharides that differ only in the position of the substituents on the anomeric carbon atom.

<p>Cyclic monosaccharides that differ only in the position of the substituents on the anomeric carbon atom.</p>
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Pyranose

Cyclic monosaccharide containing a six-atom ring

<p>Cyclic monosaccharide containing a six-atom ring</p>
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Furanose

Cyclic monosaccharide containing a five-atom ring

<p>Cyclic monosaccharide containing a five-atom ring</p>
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cyclic hemiacetal

Aldopentoses also form (?)

<p>Aldopentoses also form (?)</p>
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furanoses

The most prevalent forms of D-ribose and other pentoses in the biological world are (?).

<p>The most prevalent forms of D-ribose and other pentoses in the biological world are (?).</p>
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cyclic hemiacetal

D-Fructose also forms a 5-membered (?).

<p>D-Fructose also forms a 5-membered (?).</p>
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Strain-free chair conformation

For pyranoses, the six-membered ring is more accurately represented as a (?).

<p>For pyranoses, the six-membered ring is more accurately represented as a (?).</p>
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True

True or False? If false replace the underlined word to make the statement correct.

“In both Haworth projections and chair conformations, the orientations of groups on carbons 1- 5 of b-D-glucopyranose are up, down, up, down, and up and all are equatorial.”

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up; down

CONVERTING HAWORTH TO CHAIR

The trick is to remember that just like the Haworth projections, the chair conformations also have the well-defined “(?)” and “(?)” positions!

<p>CONVERTING HAWORTH TO CHAIR</p><p>The trick is to remember that just like the Haworth projections, the chair conformations also have the well-defined “(?)” and “(?)” positions!</p>
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Glucose

MONOSACCHARIDES

-Most abundant in nature

-Important in human nutrition

-6-membered cyclic form

<p>MONOSACCHARIDES</p><p>-Most abundant in nature</p><p>-Important in human nutrition</p><p>-6-membered cyclic form</p>
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Glucose

MONOSACCHARIDES

Other names:

—Grape sugar

—Blood sugar

—Dextrose

<p>MONOSACCHARIDES</p><p>Other names:</p><p>—Grape sugar</p><p>—Blood sugar</p><p>—Dextrose</p>
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Galactose

MONOSACCHARIDES

-Used to differentiate between blood types

-6-membered cyclic form

<p>MONOSACCHARIDES</p><p>-Used to differentiate between blood types</p><p>-6-membered cyclic form</p>
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Lactase

Which enzyme hydrolyzes β(1,4) glycosidic linkages?

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Fructose

MONOSACCHARIDES

-Ketohexose

-High dietary sugar due to sweetness

-5-membered cyclic form

<p>MONOSACCHARIDES</p><p>-Ketohexose</p><p>-High dietary sugar due to sweetness</p><p>-5-membered cyclic form</p>
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Fructose

Which monosaccharide is the sweetest tasting of all sugars?

<p>Which monosaccharide is the sweetest tasting of all sugars?</p>
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Ribose

MONOSACCHARIDES

-Sugar in RNA

-Part of a variety of complex molecules which include:

RNA, ATP, DNA

-5-membered cyclic form

<p>MONOSACCHARIDES</p><p>-Sugar in RNA</p><p>-Part of a variety of complex molecules which include:</p><p>RNA, ATP, DNA</p><p>-5-membered cyclic form</p>
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Disaccharides

Contain 2 sugar units; 2 monosaccharides joined by a glycosidic bond

<p>Contain 2 sugar units; 2 monosaccharides joined by a glycosidic bond</p>
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Galactose

MONOSACCHARIDES

Other names:

—Brain sugar

—Milk sugar

<p>MONOSACCHARIDES</p><p>Other names:</p><p>—Brain sugar</p><p>—Milk sugar</p>
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Maltose

DISACCHARIDES

Glucose + Glucose

Units: α-D-glucose & β-D-glucose

Linkage: α(1,4) glycosidic linkage

<p>DISACCHARIDES</p><p>Glucose + Glucose</p><p>Units: α-D-glucose & β-D-glucose</p><p>Linkage: α(1,4) glycosidic linkage</p>
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Disaccharides

Two monosaccharides are joined by a glycosidic bond between the anomeric Carbon of one unit and an –OH group of the other unit.

<p>Two monosaccharides are joined by a glycosidic bond between the anomeric Carbon of one unit and an –OH group of the other unit.</p>
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A

2 Galactose

1 N-Acetyl-glucosamine

1 Fucose

A. Type O blood

B. Type A blood

C. Type B blood

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Lactose

DISACCHARIDES

Glucose + Galactose

Units: β-D-galactose & α-D-glucose unit

Linkage: β(1,4) glycosidic linkage

<p>DISACCHARIDES</p><p>Glucose + Galactose</p><p>Units: β-D-galactose & α-D-glucose unit</p><p>Linkage: β(1,4) glycosidic linkage</p>
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Sucrose

Glucose + Fructose

Units: α-D-glucopyranose & β-D-fructofuranose

Linkage: α(1,2) glycosidic linkage

<p>Glucose + Fructose</p><p>Units: α-D-glucopyranose & β-D-fructofuranose</p><p>Linkage: α(1,2) glycosidic linkage</p>
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Sucrose

DISACCHARIDES

The most abundant of all disaccharides and found in plants. Also known as “table sugar”.

<p>DISACCHARIDES</p><p>The most abundant of all disaccharides and found in plants. Also known as “table sugar”.</p>
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B

2 Galactose

1 N-Acetyl-glucosamine

1 Fucose

1 N-Acetyl-galactosamine

A. Type O blood

B. Type A blood

C. Type B blood

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C

3 Galactose

1 N-Acetyl-glucosamine

1 Fucose

A. Type O blood

B. Type A blood

C. Type B blood

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Cellobiose

DISACCHARIDES

Units: α-D-glucose, β-D-glucose

Linkage: β(1,4) glycosidic linkage

<p>DISACCHARIDES</p><p>Units: α-D-glucose, β-D-glucose</p><p>Linkage: β(1,4) glycosidic linkage</p>
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Polysaccharides

Polymers of many monosaccharide units bonded with glycosidic linkages.

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Oligosaccharides

Carbohydrates that contain 3–10 monosaccharide units bonded to each other via glycosidic linkages.

<p>Carbohydrates that contain 3–10 monosaccharide units bonded to each other via glycosidic linkages.</p>
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Cellobiose

DISACCHARIDES

Cannot be digested by humans

<p>DISACCHARIDES</p><p>Cannot be digested by humans</p>
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Oligosaccharides

-Commonly found in onions, cabbage, broccoli, and whole wheat.

-Can distinguish blood types.

<p>-Commonly found in onions, cabbage, broccoli, and whole wheat.</p><p>-Can distinguish blood types.</p>
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sweet; positive

Polysaccharides are not (?) and do not show (?) tests with Tollen’s and Benedict’s solutions,

whereas monosaccharides are sweet and show positive tests.

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True

True or False? If false replace the underlined word to make the statement correct.

“Polysaccharides have limited water solubility.”

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Storage polysaccharide

Polysaccharide that is a storage form for monosaccharides and used as an energy source in cells

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Starches

POLYSACCHARIDES

Storage polysaccharide in plants

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Glucose

POLYSACCHARIDES

(?) is the monomeric unit in starch

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Amylose; Amylopectin

POLYSACCHARIDES

Give the two types of starch

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Amylose

POLYSACCHARIDES

This type of starch is unbranched; α(1→4) glycosidic bonds

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Amylopectin

POLYSACCHARIDES

This type of starch is branched; α(1→4) α(1→6) glycosidic bonds

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B

POLYSACCHARIDES

Which glycosidic bond in Amylopectin causes the branching?

A. α(1→4) glycosidic bonds

B. α(1→6) glycosidic bonds

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Glycogen

POLYSACCHARIDES

Storage polysaccharide in humans and animals

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Glycogen

POLYSACCHARIDES

Branched chain polymer with α(1→4) glycosidic bonds in STRAIGHT chains and α(1,6) in BRANCHES

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B

POLYSACCHARIDES

Which glycosidic bond in Glycogen causes the branching?

A. α(1→4) glycosidic bonds

B. α(1→6) glycosidic bonds

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True

POLYSACCHARIDES

True or False? If false, replace the underlined word to make the statement correct.

“Glycogen contains only glucose units.”

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do not

POLYSACCHARIDES

True or False? If false, replace the underlined word to make the statement correct.

“Humans do have enzymes that hydrolyze β(1,4) linkages.”

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weaker

POLYSACCHARIDES

True or False? If false, replace the underlined word to make the statement correct.

“Chitin is stronger than Cellulose.”

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B; A

Identify the type of structural notation for A and B

A. β(1,4)

B. α(1,4)

<p>Identify the type of structural notation for A and B</p><p>A. β(1,4)</p><p>B. α(1,4)</p>