Unit Seven: Differential Equations

0.0(0)
studied byStudied by 4 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/175

flashcard set

Earn XP

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

176 Terms

1
New cards
Basic steps in creating a model
1. State assumptions
2
New cards
2. Completely describe the variables and parameters used
3
New cards
3. Use assumptions to derive equations relating quantities
4
New cards
1st Order Equation
An equation for an unknown function in terms of its derivative: dy/dt=f(t,y)
5
New cards
Only contains 1st derivative of dependent variable.
6
New cards
Ordinary differential equation
Does not contain partial derivatives
7
New cards
Equilibrium solution
dP/dt=0
8
New cards
Unlimited population growth model
dP/dt=kP
9
New cards
Limited resources population growth model
dP/dt=k(1-P/N)P
10
New cards
N is the maximum population
11
New cards
A solution to a differential equation
y(t) is a solution if it satisfies
12
New cards
dy/dt=y'(t)=f(t,y(t))
13
New cards
An initial value problem
A differential equation along with an initial condition
14
New cards
dy/dt=f(t,y), y(t₀)=y₀
15
New cards
Separable equations
An equation is separable if the function f(t,y) can be written
16
New cards
dy/dt=f(t,y)=g(t)h(y)
17
New cards
An autonomous equation (and slope field)
dy/dt=f(t,y)=h(y)
18
New cards
The slope is the same at any t coordinate
19
New cards
Solving separable equations
dy/dt=f(t,y)=g(t)h(y)
20
New cards
1/h(y)dy=g(t)dt
21
New cards
∫1/h(y)dy=∫g(t)dt
22
New cards
Existence theorem (technical)
Suppose f(t,y) is a continuous function in a rectangle of the form {(t,y)|a
23
New cards
Existence theorem (not technical)
If f(t,y) is reasonable, then solutions exist. It does not rule out the possibility that solutions exist even if f(t,y) isn't nice. The solution may be defined for only a short interval of time
24
New cards
Uniqueness theorem (technical)
Suppose f(t,y) and df/dy are continuous functions in a rectangle of the form {(t,y)|a
25
New cards
Existence and Uniqueness theorem
There exists only one solution to a 1st order differential equation which satisfies a given initial condition. By this theorem, a solution that approaches an equilibrium point never actually gets there. Solutions move slowly as they get close to an equilibrium point.
26
New cards
Linearisation theorem
If f'(y₀)
27
New cards
If f'(y₀)>0, y₀ is a source
28
New cards
If f'(y₀)=0 then we need additional information to determine the type of equilibria
29
New cards
Parameter
Parameters are quantities that do not depend on the independent variable but that assume different values depending on the specifics of the application at hand.
30
New cards
A bifurcation
Is when a small change in the parameter can lead to a drastic change in the long-term solutions. We can say that a differential equation that depends on a parameter bifurcates if there is a qualitative change in the behaviour of solutions as the parameter changes.
31
New cards
Linear differential equations
Is a first order differential equation that can be written in the form:
32
New cards
dy/dt=a(t)y+b(t)
33
New cards
Where a(t) and b(t) are arbitrary functions of t
34
New cards
Homogenous/ unforced linear equations
b(t)=0
35
New cards
dy/dt=a(t)y
36
New cards
Constant coefficient linear differential equations
a(t) is constant
37
New cards
dy/dt=ay(t)+b(t)
38
New cards
Linearity Principle (Homogenous Case)
If y(t) is a solution of the homogenous linear equation,
39
New cards
dy/dt=a(t)y
40
New cards
Then any constant multiple of y(t) is also a solution
41
New cards
ky(t) is a solution for constant k
42
New cards
Extended Linearity Principle (Propositions)
Consider the non-homogenous equation dy/dt=a(t)y+b(t) and its associated homogeneous equation dy/dt=a(t)y.
43
New cards
1) If yh(t) is any solution of the homogenous equation and yp(t) is any solution of the non-homogenous equation, then yh(t)+y(p)t is also a solution of the non-homogenous equation
44
New cards
2) Suppose yp(t) and yq(t) are two solutions of the non-homogenous equation. Then yp(t)-yq(t) is a solution of the associated homogenous equation
45
New cards
Extended Linearity Principle (Conclusions)
If yh(t) is non-zero, kyh(t)+yp(t) is the general solution to the non-homogeneous equation.
46
New cards
Solving Linear Differential Equations (Integrating Factor Method)
dy/dt+g(t)y=b(t)
47
New cards
Integrating factor = µ(t)=exp(∫g(t)dt)
48
New cards
µ(t)dy/dt+µ(t)g(t)y=µ(t)b(t)
49
New cards
dy/dt(y.µ(t))=b(t)µ(t)
50
New cards
y(t)=1/(µ(t))∫µ(t)b(t)dt
51
New cards
Solving Linear Differential Equations (Linearity Principle Method)
1) Find the general solution to the associated homogeneous DE
52
New cards
2) Find one particular solution to the non-homogeneous DE (guess)
53
New cards
3) Obtain one general solution to the non-homogeneous DE by adding the general solution to the homogeneous DE and the particular solution the the non-homogeneous DE.
54
New cards
Limited resources population model with harvesting
dP/dt=kP(1-P/N)-H
55
New cards
H is harvested
56
New cards
Euler's Method
dy/dt=f(t,y), y(t₀)=y₀
57
New cards
t₁=t₀+∆t
58
New cards
y₁=y₀+f(t₀,y₀)∆t
59
New cards
Improved Euler Method
(a) take an ordinary Euler step of length h. Calculate the slope at the end of this step
60
New cards
(b) go back and take a step of length h with the slope being the average of the slope at the beginning and the slope at the end
61
New cards
4th Order Runge-Kutta
tⁿ⁺¹=tⁿ+h
62
New cards
m₁=f(tⁿ+(h/2),yⁿ+(h/2)m₁)
63
New cards
m₂=f(tⁿ+(h/2),yⁿ+(h/2)m₂)
64
New cards
m₃=f(tⁿ+(h/2),yⁿ+(h/2)m₂
65
New cards
m₄=f(tⁿ+h,yⁿ+hm₃)
66
New cards
yⁿ⁺¹=yⁿ+h/6(m₁+2m₂+2m₃+m₄)
67
New cards
Order of Numerical Methods
Measures the change in error of numerical solution as step size is decreased. Define E(h) to be the error in the approximate solution obtained when we solve the IVP
68
New cards
|E(h)|≈khⁿ as h→0. n is the order of the method.
69
New cards
Order of Various Numerical Methods
Euler: 1 : E≈kh¹ - error is halved when step size is halved
70
New cards
Improved Euler: 2: E≈kh²
71
New cards
R-K4: 4: E≈kh⁴
72
New cards
Solution to System of Differential Equations
x(t), y(t) is a solution if
73
New cards
dx/dt=x'(t)=f(t,x(t))
74
New cards
dy/dt=y'(t)=f(t,y(t))
75
New cards
Vector Notation
dx/dt=f(x,y) dy/dt=g(x,y)
76
New cards
Y(t)=(x(t) y(t))
77
New cards
V(Y)=(f(x,y) g(x,y))
78
New cards
dY/dt=V(Y)
79
New cards
The Vector Field
V(Y) is known as a vector field, i.e. the function that assigns a vector to each point in the x-y plane
80
New cards
Drawing vector fields for 2D autonomous systems
1) for selected points in the x-y plane, calculate V(Y)
81
New cards
2) For each point Y₀(x₀) draw the vector V(Y₀) with the base of the vector at Y₀ and with the arrow showing the direction. The length is proportional to size
82
New cards
Direction Field
Vectors have the same direction as in the vector field (x-y plane), but are scaled to a uniform length and arrows are often omitted
83
New cards
Solution curves as functions of t
We could plot solutions of a system of equations as functions of t. For a system of two dependent variables, x and y, we could either plot x(t) and y(t) separately, or we could plot the solution in the 3D x-y-t space
84
New cards
Phase Space
The space of dependent variables. In this case it is the x-y plane. It is the preferred method to plot solutions for an autonomous system
85
New cards
Sketching Solution Curves
dV/dt=F(Y), Y=(x(t) y(t))
86
New cards
A solution is a vector of functions
87
New cards
γ(t)=(y₁(t) y₂(t)) such that dγ/dt=F(γ)
88
New cards
As we vary t, the point (y₁(t) y₂(t)) will trace out a curve in the x-y plane. this curve is parameterised by time and is called the solution curve.
89
New cards
You can sketch solution curves for a DE by
90
New cards
1) Plot the direction field
91
New cards
2) Starting at some initial point, sketch a smooth curve that follows the line segments of the direction field.
92
New cards
Equilibrium solutions of DEs
Y₀ is an equilibrium point of the system dY/dt=V(Y) if V(Y₀)=0.
93
New cards
The intersection of the x and y nullclines is an equilibrium
94
New cards
X Nullcline
Consider a system dx/dt=f(x,y), dy/dt=g(x,y)
95
New cards
The x-nullcline is the set of all points (x,y) where f(x,y)=0. On the x-nullcline, dx/dt=0 and the direction field is vertical (pointing straight up or down)
96
New cards
Y Nullcline
Consider a system dx/dt=f(x,y), dy/dt=g(x,y)
97
New cards
The y-nullcline is the set of all points (x,y) where g(x,y)=0. On the y-nullcline, dy/dt=0 and the direction field is horizontal (pointing left or right)
98
New cards
Points to note about nullclines
1) Nullclines are not necessarily a solution curve
99
New cards
2) Nullclines are not necessarily a straight line
100
New cards
When is f(t,y)=y√t continuous?
For all y∈R and for all t>0