Weighted Average Atomic Mass
Multiply amu by percentage
Add values together
Answer is the average amu
Molar mass
the mass of 1 mole of ___ in grams
Avogadro’s Number and Mole
1 mole = NA = 6.022 × 1023
Unit Conversions
6.022 × 1023 atoms / 1 mole
grams (avg atomic mass) / mole
Natural Abundance
Average Atomic Mass = (x (#amu1) ) + ( [1 - x] (#amu2) )
Answer is relative abundance for element 1
x + (1 - x) = 1
Answer is relative abundance for element 2
Percent Composition
( n x molar mass of element ) / ( molar mass of compound ) x 100%
n is the number of moles of the element in 1 mole of the compound
Calculating the empirical formula from the mass percent composition
Assume 100 grams of a compound (percentages then become grams)
Calculate the moles of each element
Divide by the smallest number to obtain the subscripts in the empirical formula
Converting empirical formulas to molecular formulas
molecular formula molar mass / empirical formula molar mass
Answer is the multiplier of each subscript in empirical formula